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The Multivariate Normal Distribution, Part 1 BMTRY 726 1/10/2014
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Univariate Normal Recall the density function of the univariate normal We can rewrite this as
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Multivariate Normal Distribution We denote the MVN distribution as What is the density function of X ?
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Multivariate Normal Distribution What is the density function of X ?
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Multivariate Normal Note, the density does not exist if – is not positive definite – = 0 – does not exist We will assume that is positive definite for most of the MVN methods we discuss
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Multivariate Density Function If we assume that is positive definite is the square of the generalized distance from x to . Also called – Squared statistical distance of x to . – Squared Mahalanobis distance of x to – Squared standardized distance of x to
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Why Multivariate Normal The MVN distribution makes a good choice in statistics for several reasons – Mathematical simplicity – Multivariate central limit theorem – Many naturally occurring phenomenon approximately exhibit this distribution
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Bivariate Normal Example Consider samples from Let’s write out the joint distribution of x 1 and x 2
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Bivariate Normal Example Joint distribution of x 1 and x 2
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Bivariate Normal Example Joint distribution of x 1 and x 2
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Bivariate Normal Example This yields joint distribution of x 1 and x 2 in the form
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Bivariate Normal Example The density if a function of 1, 2, 1, 2, and – The density is well defined if - 1 < < 1 – If = 0, then …
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Contours of constant density What if we take a slice of this bivariate distribution at a constant height? – i.e.
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Contours of constant density The density is constant for all points for which This is an equation for an ellipse centered at
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Bivariate Normal Example Let’s look at an example of the bivariate normal when we vary some of the parameters…
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Examples X1X1 X1X1 X1X1 X1X1 X2X2 X2X2 X2X2 X2X2
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Contours of constant density What happens when
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Contours of constant density How do we find the axes of the ellipse? – Axes are in the direction of the eigenvectors of – Axes lengths are proportional to the reciprocals of the square root of the eigenvalues of – We can get these from (avoid calculating ) Let’s look at this for the bivariate case... We must find the eigenvalues and eigenvectors for – Eigenvalues: – Eigenvectors:
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Eigenvalues of :
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The corresponding eigenvector, e 1, of :
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Similarly we can find e 2, which corresponds to 2 : The axes of the contours of constant density will have length
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If we let then are the eigenvalues of and e 1 and e 2 are the corresponding eigenvectors
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The ratio of the lengths of the axes The actual lengths depend on the contour being considered. For the (1-a)x100% contour, the ½ lengths are given by Thus the solid ellipsoid of x values satisfying has probability 1- .
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Univariate case: length of the interval containing the central 95% of the population is proportional to Bivariate case: the area of the region containing 95% of the population is proportional to.
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We can call this “smallest” region the central (1- )x100% of the multivariate normal population. The “area” of this smallest ellipse in the 2-D case is: This extends to higher dimensions (think volume) – Consider – The smallest region for which there is 1- that a randomly selected observation falls in the region is a p-dimensional ellipsoid centered at with volume
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Visual of the 3-dimensional case
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Next Time Properties of the MVN…
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