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Published byJeremy Brooks Modified over 9 years ago
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Macho: Programming With Man Pages Anthony Cozzie, Murph Finnicum, Sam King University of Illinois at Urbana-Champaign
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Programming is hard! Extreme Detail Extreme Precision
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Lots of Automated Tools Static Analysis – Coverity Code Snippet search engines – Prospector, SNIFF, Xsnippet, even Google Automated Debuggers – Genetic programming, Delta debugging
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Automating Programming Computer makes decisions But it will make mistakes too! Programmer must go back and check the tool – not easy So, how can we do this efficiently?
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Macho Architecture NL parsing Database Stitching Debugger Raw Text Requested Computation Code Snippets Candidate Programs Runtime Feedback Solutions
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The Trick NL parsing Database Stitching Debugger
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Examples! Example is end-to-end: covers many decisions Easy to understand compared to code
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The Example (LS) Print the names of files in a directory. Sort the names.
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Extract Implied Computation directory -> files files -> names print(names) sort(names) Print the names of files in a directory. Sort names.
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Use Programmer’s Labels public static void main(String[] args) {.... //first (original) database files = directory.listFiles();.... }
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Input to Synthesis: LS1 public static void Ls1(java.lang.String p_directory) { java.io.File tmp = new File(p_directory); java.io.File[] files = tmp.listFiles(); int tmp_0 = files.length; java.lang.String[] tmp_1 = new java.lang.String[tmp_0]; for(int tmp_3 = 0; tmp_3 < files.length; ++tmp_3) { java.io.File tmp_2 = files[tmp_3]; java.lang.String names = tmp_2.getName(); tmp_1[tmp_3] = names; } Arrays.sort(tmp_1); for(int tmp_5 = 0; tmp_5 < tmp_1.length; ++tmp_5) { java.lang.String tmp_4 = tmp_1[tmp_5]; System.out.println(tmp_4); }
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Bugs! Prints hidden files Crashes if the input is not a directory
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Synthesized Version of LS public static void Ls3(String p_dir) { java.io.File tmp = new File(p_dir); java.io.File[] files = tmp.listFiles(); boolean tmp_3 = tmp.isDirectory(); if(tmp_3) { Arrays.sort(files); for(int tmp_1 = 0; tmp_1 < files.length; ++tmp_1) { java.io.File tmp_0 = files[tmp_1]; java.lang.String names = tmp_0.getName(); boolean tmp_2 = tmp_0.isHidden(); if(!tmp_2) System.out.println(names); } else System.out.println(tmp + ""); }
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Pure NL Spec Take the path "/home/zerocool/" If the path is a file, print it. Otherwise get the list of files in the directory. Sort the result alphabetically. Go over the result from the beginning to the end: If the current element's filename does not begin with ".", print it.
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Macho Print the names of files in a directory. Sort the names. + simple example
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Input Synergy NL: moderate information over a large part of the state space Examples: very precise information over a tiny part of the state space Together: win
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