2. NEXT Click the ‘NEXT’ button to continue

3.  Today, in Ms. Stechschulte’s 7 th grade class, we will be learning how to solve one-step equations. To navigate through this presentation, click on the arrows and buttons at the bottom of the screen. The arrow labeled ‘NEXT’, will take you to the next slide. The arrow labeled ‘BACK’, will take you back to the previous slide. When you get to the Main Menu, click on the first link to begin the lesson. If you need to go back to the previous lessons to clarify concepts, please do so.  Click the arrow below to continue. NEXT

4.  Your goal is to learn the concept of solving equations so you are successful answering the quiz questions. You must know the concepts well enough to solve two-step equations for tomorrow’s class. When you are finished with the first 2 Lessons, go to Lesson 3 and play the online math games for the remainder of the class period.  Good luck and have fun NEXT BACK

5.  “An equation is a written statement indicating the equality of two expressions”  It consists of a sequence of symbols that are split into left and right sides joined by an equal sign.  For example, 2 + 4 = 6 is an equation. http://dictionary.reference.com/browse/equation NEXT Left side Right side BACK

6. * Remember * 2x + 3 = 5 NEXT Coefficient: the number that is in front of the x. This means that 2 and x are multiplied. Variable: the letter you are solving for; it needs to be isolated on one side of the equation. A variable can be any letter. Left sideRight side BACK

7. Lesson 1: Using adding & subtractingUsing adding & subtracting Lesson 2: Using multiplication & divisionUsing multiplication & division Lesson 3: Online Math GamesOnline Math Games Click on the link for Lesson 1 to begin. When finished with Lesson 1, continue with Lesson 2 then 3.

8.  Hoop Shoot Hoop Shoot  Equation Buster Equation Buster  Easy Algebra Equations Easy Algebra Equations  Say the ‘2 – steps’: Rags to Riches Say the ‘2 – steps’: Rags to Riches BACK

9. 1 x = 1 1 1 x + 1 = 3 To solve an equation you must get x by itself on one side of the equal sign, while keeping the scale balanced NEXT BACK

10. = x 1 1 1 1 NEXT To get x by itself you have to take away (subtract) 1. However, this will cause the scale to become unbalanced, so you also have to take away 1 from the other side of the equal sign. BACK

11. 1 x = 1 1 1 x + 1 = 3 -1 -1 x = 2 NEXT After you subtract 1 from both sides of the equal sign, you are left with x = 2 BACK

12. NEXT  “Two operations are said to be inverse to each other if one operation undoes the effect of the other operation.”  Addition and Subtraction are inverse operations  Multiplication and Division are inverse operations http://www.icoachmath.com/Sitemap/InverseOperation.html BACK

13. NEXT Inverse operations must be used when solving equations. In the previous example we SUBTRACTED to undo the ADDITION to get x by itself. To solve x – 5 = 3, what operation must you use to get x by itself? BACK

14. MORE EXAMPLES If you said ADDITION you are correct! To undo SUBTRACTION you must ADD. To solve x – 5 = 3 +5 +5 x = 8 Add 5 to both sides to keep the equation balanced. Begin Quiz 1 BACK

15. 1 x = 1 1 1 x + 2 = 4 To solve an equation get rid of whatever is with the variable (x). What you do to one side, you must also do to the other side. NEXT 1 1

16. 1 x = 1 1 1 x + 2 = 4 Subtract 2 from both sides to keep the scale balanced 11 x = 2 To Quiz 1 NEXT BACK

17. Since 2 is SUBTRACTED from x, you must ADD 2 to both sides to solve x – 2 = 3 +2 +2 x = 5 Add 2 to both sides to keep the equation balanced. To Quiz 1 NEXT BACK

18. -1 = 7 + x is the same as saying 7 + x = -1 Since 7 is ADDED to x, you must SUBTRACT 7 from both sides to solve -1 = 7 + x -7 -7 -8 = x x = -8 Subtract 7 from both sides to keep the equation balanced. To Quiz 1 BACK

19. Question 1: Solve x + 4 = 9 A.A. x = 13 B.B. x = 5 C.C. x = 9 Click on a letter to continue.

20. Question 2: Solve x – 5 = 2 A.A. x = -3 B.B. x = 2 C.C. x = 7 Click on a letter to continue.

21. Question 3: Solve – 5 = 4 + x A.A. x = -9 B.B. x = -1 C.C. x = 9 Click on a letter to continue.

22. Correct!! Nice Work! NEXT

23. Correct!! Great Job! NEXT

24. Correct!! Fabulous! NEXT

25. Incorrect Try Again Let’s look at another example NEXT

26. 1 x = 1 1 1 x + 2 = 4 To solve an equation get rid of whatever is with the variable (x). What you do to one side, you must also do to the other side. NEXT 1 1

27. 1 x = 1 1 1 x + 2 = 4 Subtract 2 from both sides to keep the scale balanced 11 x = 2 To Quiz 1 BACK

28. Incorrect Try Again Let’s look at another example NEXT

29. Since 2 is SUBTRACTED from x, you must ADD 2 to both sides to solve x – 2 = 3 +2 +2 x = 5 Add 2 to both sides to keep the equation balanced. To Quiz 1

30. Incorrect Try Again Let’s look at another example NEXT

31. -1 = 7 + x is the same as saying 7 + x = -1 Since 7 is ADDED to x, you must SUBTRACT 7 from both sides to solve -1 = 7 + x -7 -7 -8 = x x = -8 Subtract 7 from both sides to keep the equation balanced. To Quiz 1

32. What is the inverse operation of MULTIPLICATION? NEXT BACK

33. The answer is… DIVISION NEXT BACK

34. What is the inverse operation of DIVISION? NEXT BACK

35. The answer is… MULTIPLICATION NEXT BACK

36. When you have an equation with multiplication or division, you will do the inverse operation to solve! NEXT BACK

37. Since 6 and x are multiplied, to solve, we divide by 6. 6x = 48 6 x = 8 Divide by 6 on both sides to keep the equation balanced. BACK NEXT Reminder: When a number is divided by itself, it equals 1.

38. Since x is divided by 4, to solve, we multiply by 4. x = 5 4 (4)x = 5(4) 4 x = 20 Multiply by 4 on both sides to keep the equation balanced. To Quiz 2 BACK MORE EXAMPLES

39. The inverse operation of MULTIPLICATION is DIVISION, so we divide by 10. 10x = 30 10 10 x = 3 Divide by 10 on both sides to keep the equation balanced. NEXT To Quiz 2 BACK

40. The inverse operation of DIVISION is MULTIPLICATION, so we multiply by -5. x = 3 -5 (-5)x = 3(-5) -5 x = -15 Multiply by -5 on both sides to keep the equation balanced. NEXT To Quiz 2 ** Remember: Negative times a positive = negative BACK

41. The inverse operation of MULTIPLICATION is DIVISION, so we divide by -2. -2x = -10 -2 -2 x = 5 Divide by -2 on both sides to keep the equation balanced. To Quiz 2 ** Remember: Negative times a negative = positive BACK

42. Question 1: Solve 5x = 35 A.A. x = 175 B.B. x = 30 C.C. x = 7 Click on a letter to continue.

43. Incorrect Try Again Let’s look at another example NEXT

44. Correct!! Super! NEXT

45. Question 2: Solve x = 4 -2 A.A. x = -8 B.B. x = 6 C.C. x = -2 Click on a letter to continue.

46. Incorrect Try Again Let’s look at another example NEXT

47. Correct!! Fantastic! NEXT

48. Question 3: Solve -3x = 6 A.A. x = 2 B.B. x = -2 C.C. x = -18 Click on a letter to continue.

49. Incorrect Try Again Let’s look at another example NEXT

50. Correct!! Great Job! NEXT

51. The inverse operation of MULTIPLICATION is DIVISION, so we divide by 10. 10x = 30 10 10 x = 3 Divide by 10 on both sides to keep the equation balanced. To Quiz 2

52. The inverse operation of DIVISION is MULTIPLICATION, so we multiply by -5. x = 3 -5 (-5)x = 3(-5) -5 x = -15 Multiply by -5 on both sides to keep the equation balanced. To Quiz 2 ** Remember: Negative times a positive = negative

53. The inverse operation of MULTIPLICATION is DIVISION, so we divide by -2. -2x = -10 -2 -2 x = 5 Divide by -2 on both sides to keep the equation balanced. To Quiz 2 ** Remember: Negative times a negative = positive