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Entry Task: March 8 th Friday Entry task question: 2AgCl + Mg  MgCl 2 + 2Ag Question: How many grams of silver can be produced if 150 grams of magnesium.

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Presentation on theme: "Entry Task: March 8 th Friday Entry task question: 2AgCl + Mg  MgCl 2 + 2Ag Question: How many grams of silver can be produced if 150 grams of magnesium."— Presentation transcript:

1 Entry Task: March 8 th Friday Entry task question: 2AgCl + Mg  MgCl 2 + 2Ag Question: How many grams of silver can be produced if 150 grams of magnesium reacts with excess AgCl? You have ~10 minutes

2 Agenda: TURN IN ALL STOICH LAB!!- NOW!!! – OR it will be considered LATE!! Break out periodic tables and calculators

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4 Stoichiometry – gram-gram Clear off Desks! QUIETLY work through the first problem. After ~10-15 minutes we will check answers If you get done sooner- move on

5 Iron III sulfate reacts with potassium hydroxide to create potassium sulfate and iron III hydroxide ___Fe 2 (SO 4 ) 3 + ___KOH  ___K 2 SO 4 + ___Fe(OH) 3 236

6 236 a. How many grams of potassium hydroxide were used to create 50.9 grams of iron III hydroxide? 50.9 grams Fe(OH) 3 g of KOH 106.9 g of Fe(OH) 3 1 mole of Fe(OH) 3 56.10 g of KOH 1 mole of KOH 2 mole of Fe(OH) 3 6 mole of KOH 50.9 X 6 X 56.10 106.9 X 2 17132.9 213.8 80.1 g of KOH

7 ___Fe 2 (SO 4 ) 3 + ___KOH  ___K 2 SO 4 + ___Fe(OH) 3 236 b. How many grams of iron III sulfate were used to create 155 grams of potassium sulfate? 155 grams K 2 SO 4 g of Fe 2 (SO 4 ) 3 174.3 g of K 2 SO 4 1 mole of K 2 SO 4 399.873 g of Fe 2 (SO 4 ) 3 1 mole of Fe 2 (SO 4 ) 3 3 mole of K 2 SO 4 1 mole of Fe 2 (SO 4 ) 3 155 X 1 X 399.873 174.3 X 3 61980.3 522.9 119 g of Fe 2 (SO 4 ) 3

8 ___Fe 2 (SO 4 ) 3 + ___KOH  ___K 2 SO 4 + ___Fe(OH) 3 236 c. How many grams of potassium sulfate were produced if 35.0 grams of potassium hydroxide were used? 35.0 grams KOH g of K 2 SO 4 56.10 g of KOH 1 mole of KOH 174.3 g of K 2 SO 4 1 mole of K 2 SO 4 6 mole of KOH 3 mole of K 2 SO 4 35.0 X 3 X 174.3 56.10 X 6 18301.5 336.6 54.4 g of K 2 SO 4

9 ___Fe 2 (SO 4 ) 3 + ___KOH  ___K 2 SO 4 + ___Fe(OH) 3 236 d. How many grams of iron III hydroxide were produced if 25.0 grams iron III sulfate were used? 25.0 grams Fe 2 (SO 4 ) 3 g of Fe(OH) 3 399.87 g of Fe 2 (SO 4 ) 3 1 mole of Fe 2 (SO 4 ) 3 106.9 g of Fe(OH) 3 1 mole of Fe(OH) 3 1 mole of Fe 2 (SO 4 ) 3 2 mole of Fe(OH) 3 25.0 X 2 X 106.9 399.87 534.5 399.87 13.4 g of Fe(OH) 3

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