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TODAY IN GEOMETRY… Review:

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1 TODAY IN GEOMETRY… Review: Learning Target : 10.4 You will use inscribed angles of circles Independent practice CH.10 QUIZ - FRIDAY

2 REVIEW: Graph △𝐴𝐡𝐢. 𝐴 3, 4 𝐡 βˆ’1, 5 𝐢 1, βˆ’2
Translate the Pre-Image and record the image points. (π‘₯, 𝑦)β†’(π‘₯βˆ’2, 𝑦+3) 𝐴′ 𝐡′ 𝐢′ π‘ƒπ‘œπ‘–π‘›π‘‘ 𝐴: 3, 4 β†’ 3βˆ’2, 4+3 (3, 4)β†’(1, 7) 𝑨′(𝟏, πŸ•) π‘ƒπ‘œπ‘–π‘›π‘‘ 𝐡: βˆ’1, 5 β†’ βˆ’1βˆ’2, 5+3 (βˆ’1, 5)β†’(βˆ’3, 8) 𝑩′(βˆ’πŸ‘, πŸ–) π‘ƒπ‘œπ‘–π‘›π‘‘ 𝐢: 1, βˆ’2 β†’ 1βˆ’2, βˆ’2+3 1, βˆ’2 β†’ βˆ’1, 1 π‘ͺβ€²(βˆ’πŸ, 𝟏) 𝐴 𝐡 𝐢

3 REVIEW: Graph △𝐴𝐡𝐢. 𝐴 3, 4 𝐡 βˆ’1, 5 𝐢 1, βˆ’2
Reflect the pre-image across the y-axis. RULE FOR RELECTION ACROSS Y-AXIS: (π‘₯, 𝑦)β†’(βˆ’π‘₯, 𝑦) 𝐴′ 𝐡′ 𝐢′ 𝐴 𝐡 𝐢 π‘ƒπ‘œπ‘–π‘›π‘‘ 𝐴: 3, 4 β†’ βˆ’3, 4 π‘ƒπ‘œπ‘–π‘›π‘‘ 𝐡: βˆ’1, 5 β†’ 1, 5 π‘ƒπ‘œπ‘–π‘›π‘‘ 𝐢: 1, βˆ’2 β†’ βˆ’1, βˆ’2

4 REVIEW: Graph △𝐴𝐡𝐢. 𝐴 3, 4 𝐡 βˆ’1, 5 𝐢 1, βˆ’2
Reflect the pre-image across the line π‘₯=1. EACH POINT IN A REFLECTION IS EQUAL DISTANT FROM THE LINE OF REFLECTION 𝐴′ 𝐡′ 𝐢′ π‘ƒπ‘œπ‘–π‘›π‘‘ 𝐴: 7, 1 β†’ βˆ’5, 1 π‘ƒπ‘œπ‘–π‘›π‘‘ 𝐡: 3, 2 β†’ βˆ’1, 2 π‘ƒπ‘œπ‘–π‘›π‘‘ 𝐢: 5, βˆ’5 β†’ βˆ’3, βˆ’5 𝐴 𝐡 𝐢 π‘₯=1

5 SOME IMPORTANT DEFINITIONS-not on your notes:
INSCRIBED ANGLE: An angle whose vertex is on circle. INTERCEPTED ARC: The arc made from an inscribed angle.

6 INSCRIBED ARC FORMULA: The measure of an inscribed angle is one half the measure of its intercepted arc. Intercepted arc Inscribed arc π‘₯ 2π‘₯

7 PRACTICE:

8 PRACTICE:

9 Two inscribed angles that intercept the same arc are congruent.
𝐡 Be able to see that these figures are the same! Shared Intercepted arc 𝐴 𝐴 𝐡 𝐢 𝐷 𝐷 𝐢

10 PRACTICE: Β° =πŸ’πŸ“Β° 2 38Β° =πŸ•πŸ”Β° πŸ•πŸΒ°

11 The circle that contains the vertices is a circumscribed circle.
A polygon is an inscribed polygon if all of its vertices lie on the circle. The circle that contains the vertices is a circumscribed circle. Circumscribed circle Inscribed triangle Inscribed polygon

12 A quadrilateral can be inscribed in a circle if and only if its opposite angles are supplementary.
𝐹 π‘šβˆ π·+π‘šβˆ πΉ=180Β° 𝐺 𝐸 π‘šβˆ πΈ+π‘šβˆ πΊ=180Β° 𝐷

13 Opposite angles of an inscribed polygon are supplementary:
PRACTICE: Opposite angles of an inscribed polygon are supplementary: a. 𝑦+75Β°=180Β° βˆ’ βˆ’ 75 π’š=πŸπŸŽπŸ“Β° π‘₯+80Β°=180Β° βˆ’ βˆ’ 80 𝒙=𝟏𝟎𝟎° b. 2π‘Ž+2π‘Ž=180Β° 4π‘Ž=180Β° 𝒂=πŸ’πŸ“ 4𝑏+2𝑏=180Β° 6π‘Ž=180Β° 𝒂=πŸ‘πŸŽ

14 Opposite angles of an inscribed polygon are supplementary:
PRACTICE: Opposite angles of an inscribed polygon are supplementary: 6. 8π‘₯+10π‘₯=180Β° 18π‘₯=180Β° 𝒙=𝟏𝟎 5. 𝑦+68Β°=180Β° βˆ’ βˆ’ 68 π’š=𝟏𝟏𝟐° π‘₯+82Β°=180Β° βˆ’ βˆ’ 82 π’š=πŸ—πŸ–Β° 𝑐+2π‘βˆ’6=180Β° 3cβˆ’6=180Β° 3𝑐=186 𝒄=πŸ”πŸ

15 HOMEWORK #4: Pg. 676: 3-16 Pg. 679: 40-46 If finished, work on other assignments: HW #1: Pg. 655: 3-20, 24-26, 30 HW #2: Pg. 661: 3-14, 17, 23 HW #3: Pg. 667: 3-15


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