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Mix the following solutions in pairs Write down the solution pairs and record your results  Potassium Iodide  Barium Nitrate  Lead Nitrate  When finished,

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Presentation on theme: "Mix the following solutions in pairs Write down the solution pairs and record your results  Potassium Iodide  Barium Nitrate  Lead Nitrate  When finished,"— Presentation transcript:

1 Mix the following solutions in pairs Write down the solution pairs and record your results  Potassium Iodide  Barium Nitrate  Lead Nitrate  When finished, try Silver Nitrate with Potassium Iodide.

2 Precipitate Reactions  Precipitates  Solubility rules  Using the rules of solubility

3 Reaction of PbNO 3 and KI  Lead II Nitrate and Potassium Iodide  Both are strong electrolytes  That means they completely dissociate into ions  Adding the solutions together will create something new…  A chemical change the evidence is the precipitate.

4 Pb (NO) 3 Look closer at Lead (II) Nitrate  Strong Electrolyte  Ions completely dissociate into:  Lead Pb 2+ ions  Nitrate NO 3 - Ions

5 The KI does the same thing  Posassium K+ ions and Iodide I- ions form. They are floating around in the water. (an aqueous solution)

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7 When the lead and the iodide ions come into contact, they form a precipitate  The precipitate falls to the bottom, spectator ions are left in solution

8 KI….Potassium Iodide  With Lead nitrate it forms Lead Iodide, A yellow precipitate. This tells us that the iodide compoud PbI 2 is not soluble  So are all Iodide compounds insoluble?  If you mix with barium nitrate, Ba(NO 3)2 You might expect Barium Iodide BaI 2 to form a ppt.

9 The rules can be broken into 4 categories. 1 solubleno exceptions 2 solublesome exceptions 3 not solublesome exceptions 4 not solublefew exceptions

10 Solubility Rules: Always Always Soluble 1. Always Soluble:  Li +, Na +,K +, NH 4 + Group 1A(Alkali Metals) and ammonium compounds are soluble.  C 2 H 3 O 2 -, NO 3 -, ClO 3 -, ClO 4 - Acetates, Nitrates, Chlorates, Perchlorates are all soluble.

11 The solubility rules: Usually soluble  Cl -, Br -, I - Most chlorides, bromides and Iodides are soluble Exceptions AP/H (Ag) Silver: AgCl, AgBr, AgI (Pb) Lead (II) PbCl 2, PbBr 2, PbI 2 (Hg) Mercury (I): Hg 2 Cl 2, Hg 2 Br 2, Hg 2 I 2 F - Most fluorides are soluble Exceptions CBS-PM Calcium, Barium, Strontium, Lead, Magnesium MgF 2, CaF 2, SrF 2, BaF 2 Lead (II) PbF 2 SO 4 2- Most Sulfates are soluble Exceptions CBS/PBS Calcium, Strontium, Barium, Lead (II) CaSO 4 SrSO 4 BaSO 4 PbSO 4

12 The solubility rules: Usually NOT Soluble O 2-, OH - Most hydroxides and oxides are insoluble Exceptions: CBS CaO, Ca(OH) 2 SrO, Sr(OH) 2 BaO, Ba (OH) 2 And the ‘always group’ of Alkali metals and Ammonium

13 The solubility rules: Insoluble Ions  Not soluble  CO 3 2- PO 4 3- SO 3 2- S 2- C 2 O 4 2- CrO 4 2- Exceptions: The things that are always soluble. Group 1A (Alkali Metals) Li 2 CO 3, Na 2 CO 3 … etc Ammonium compounds (NH 4 ) 2 CO 3

14 Types of reactions  Remember net ionic equations?

15 Showing everything in the reaction vessel (beaker, well plate, test tube…

16 Sometimes parts of the equation do nothing but sit and watch. Spectators

17 Complete ionic vs. net ionic Sodium sulfate + Barium Chloride react to form Solid barium sulfate and Sodium chloride 2 Na + (aq) + SO 4 2- (aq) + Ba 2+ (aq) + 2 Cl - (aq)  BaSO 4 (s) + 2 Na + (aq) + 2 Cl - (aq) NaCl is a strong electrolyte, so it does not combine to form a solid

18 Stoichiometry in Aqueous Reactions What volume of 0.200 M copper (II) sulfate is required to react with 50.0mL if 0.100 M NaOH? 1) Write the net ionic equation Cu 2+ (aq) + 2 OH - (aq)  Cu(OH) 2 (s)

19 What volume of 0.200 M copper (II) sulfate is required to react with 50.0mL if 0.100 M NaOH? find the moles of each reactant needed: n OH - = n Cu 2+ =


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