Download presentation
Presentation is loading. Please wait.
Published byAllen Campbell Modified over 9 years ago
1
Section 4.3 Absolute Value Equations & Inequalities Absolute Value Equations |2x + 5| = 13 Absolute Value Inequalities |3x – 2| < 4 4.31
2
Find the Solution Set for |x| = 4 4.32
3
Find the Solution Set for |x| = 0 Find the Solution Set for |x| = -7 4.33
4
Using the Absolute Value Principle |x + 1| = 2 x + 1 = 2 or x + 1 = -2 {1,-3} |2y – 6| = 0 2y – 6 = 0 {3} |5x – 3| = -2 no solution φ 4.34
5
Solve 4.35
6
Solve 4.36
7
Solve 4.37
8
If f(x) = 2|x + 3| + 1 find all x for which f(x) = 15 First, You must Isolate the Radical 4.38
9
9
10
What do we do when an equation has Two Absolute Values? |3| = |3| or |3| = |-3| or |-3| = |3| or |-3| = |-3| Only 2 cases: They are equal, or opposite If |X| = |Y| then solve X = Y or X = -Y Let’s try it: |5x + 3| = |3x + 25| 5x + 3 = 3x + 25 or 5x + 3 = -(3x + 25) or 5x + 3 = -3x – 25 2x = 22 or 8x = -28 x = 11 or x = -7/2 4.310
11
Solve 4.311
12
Opposites Practice |x + 4| = |2x – 7| x + 4 = 2x – 7 or x + 4 = -2x + 7 |x + 4| = |x – 3| x + 4 = x – 3 or x + 4 = -x + 3 |3a – 1| = |2a + 4| 3a – 1 = 2a + 4 or 3a – 1 = -2a – 4 |n – 3| = |3 – n| n – 3 = 3 – n or n – 3 = -3 + n |7 – a| = |a + 4| 7 – a = a + 4 or 7 – a = -a – 4 4.312
13
Inequalities with Absolute Value ) ( 4.313
14
A Similar Example [ ] ][ 4.314
15
Principles for Solving AVE’s ( ) )( 4.315
16
Solve -⅔ )( -p < X < p 4.316
17
If f(x)=|4x + 2| then find all x such that f(x) ≥ 6 [ ] X ≤ -p or p ≤ X 4.317
18
What if p is a Negative Number? Consider |x + 3| < -5 (or ≤ ) That’s impossible … so: No Solution ϕ Consider |x + 3| > -5 (or ≥ ) The absolute value will always be greater, so: All Real Numbers R 4.318
19
What Next? Section 5.1 - Wednesday Intro to Polynomials & Polynomial Functions Section 5.1 4.319
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.