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Solving Inequalities by Adding or Subtracting (SOL 7.15)

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Presentation on theme: "Solving Inequalities by Adding or Subtracting (SOL 7.15)"— Presentation transcript:

1 Solving Inequalities by Adding or Subtracting (SOL 7.15)
Course 2: Inequalities Solving Inequalities by Adding or Subtracting (SOL 7.15)

2 Key Concept Addition Property of Inequalities
Words: If any number is added to each side of a true inequality, the resulting inequality is also true. Symbols: For all numbers a, b, and c, the following are true; If a > b, then a + c > b + c If a < b, then a + c < b + c

3 Key Concept Subtraction Property of Inequalities
Words: If any number is subtracted from each side of a true inequality, the resulting inequality is also true. Symbols: For all numbers a, b, and c, the following are true; If a > b, then a - c > b - c If a < b, then a - c < b - c

4 Addition and Subtraction Rules

5 Addition and Subtraction Properties
Examples: 2 < > 3 2 + 5 < – 2 > 3 – 2 7 < > 1

6 Solve an Inequality Using Subtraction
Solve y + 5 > 11 y + 5 – 5 > 11 – 5 (Subtract 5 from both sides) y > 6 (Simplify) Check: y + 5 > 11 7 + 5 > 11 (Replace y with 7 – a number > 6) 12 > 11 (This statement is true.)

7 Try it! Solve a < 3 a + 9 < 3 (You can rewrite the inequality.) a + 9 – 9 < 3 – 9 a < -6 Check: 9 + a < 3 < 3 (Replace “a” with -6 or less) 3 < 3 Why can you replace a with -6?

8 Solve an Inequality Using Addition
Solve x – 23 < 12 x – < (Add 23 to both sides) x < 35 (This means all numbers less than or equal to 35) Check: x – 23 < 12 < 12 (Replace x with 35) 12 < 12 (This statement is true.)

9 Solve an Inequality Using Addition
Solve > d – 8 > d – (Add 8 to each side) -13 > d OR d < -13 Check > d – 8 -21 > -13 – 8 -21 > -21 Why can you use -13?

10 Try It! Solve a – 5 > 6 a – 5 + 5 > 6 + 5 a > 11
Can you use 11 to check your solution? Check: a – 5 > 6 12 – 5 > 6 7 > 6

11 Graph Solutions of Inequalities
Solve h – 1.5 < 5 h – < (Add 1.5 to each side) h < 6.5 (Simplify) Graph the solution on a number line If your variable is on the left, the inequality will point in the direction you should shade

12 Try It! Solve 33 < m – (-6) 33 < m + 6 (Simplify)
m + 6 > 33 (You can rewrite it with the variable on the left.) m + 6 – 6 > 33 – 6 (Subtract 6 from each side) m > 27 Graph the solution on a number line. Place a closed circle on the number line on the number 27 Shade to the right (positive) side

13 Graph Solutions of Inequalities
Solve 33 < m – (-6) 33 < m + 6 (Simplify) m + 6 > 33 (You can rewrite it with the variable on the left.) m + 6 – 6 > 33 – 6 (Subtract 6 from each side) m > 27 Graph the solution on a number line

14 Use an Inequality to Solve a Problem
Katya has $12 to take to the bowling alley. If the shoe rental costs $3.75, what is the most she can spend on games and snacks? “The most” means “no more than” or “less than or equal to” Cost of shoe rental + games and snacks must be less than or equal to $12. $ c < $12 $ c - $3.75 < $12 - $3.75 c < $8.25 Katya can spend no more than $8.25.

15 Try It! Chris is saving money for a ski trip. He has $62.50, but his goal is to save at least $100. What is the least amount Chris needs to save to reach his goal? Current amount + money saved must be greater than or equal to $100 $ s > $100 $ s - $62.50 > $100 - $62.50 s > $37.50 Chris must save at least $37.50.


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