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Section 8.2 – Integration by Parts
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Find the Error The following is an example of a student response. How can you tell the final answer is incorrect? Where did the student make an error? The integral of a product is not equal to product of the integrals. This should remind us of the Product Rule. Is there a way to use the Product Rule to investigate the antiderivative of a product?
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Integration by Parts: An Explanation When u and v are differentiable functions of x : The Product Rule tells us… If we integrate both sides… If we simplify the integrals… If we solve for one of the integrals…
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Integration by Parts Rewrite the function into the product of u and dv. The integral equals… u times the antiderivative of dv. The integral of the product of the antiderivative of dv and the derivative of u.
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Integration by Parts: The Process
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Example 1 Pick the u and dv. Find du and v. Apply the formula. Differentiate.Integrate.
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Example 2 Pick the u and dv. Find du and v. Apply the formula. Differentiate.Integrate. You may need to apply Integration by Parts Again. Pick the u and dv. Find du and v. Apply the formula.
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White Board Challenge
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Example 3 Since, multiple Integration by Parts are needed, a Tabular Method is a convenient method for organizing repeated Integration by parts. Repeated DifferentiationRepeated Integration + – + – Must get 0. Start with + Alternate Find the sum of the products of each diagonal: Differentiate the u. Integrate the dv. Connect the diagonals. Notice the cubic function will go to zero. So it is a good choice for u.
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Example 4 Pick the u and dv. Find du and v. This was a bad choice for u and dv. Differentiate.Integrate.
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Example 4: Second Try Pick the u and dv. Find du and v. Apply the formula. Differentiate.Integrate. Try the opposite this time.
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Example 5 If there is only one function, rewrite the integral so there is two. Pick the u and dv. Find du and v. Apply the formula. Differentiate.Integrate.
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Example 6 Pick the u and dv. Find du and v. Apply the formula. You may need to apply Integration by Parts Again. Apply the formula. Pick the u and dv. Find du and v. If you see the integral you are trying to find, solve for it.
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Example 7 If there is only one function, rewrite the integral so there is two. Pick the u and dv. Find du and v. Apply the formula.
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Integration by Parts: Helpful Acronym When deciding which product to make u, choose the function whose category occurs earlier in the list below. Then take dv to be the rest of the integrand. L I A T E ogarithmic nverse trigonometric lgebraic rigonometric xponential
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White Board Challenge
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