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Published byNicholas Chapman Modified over 9 years ago
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Anna Chang 10-1 / T2
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Perpendicular bisector is a line that cuts a segment into two equal parts, it creates 90 degrees.
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Here’s a segment AB N is the perpendicular bisector of segment AB b/c n is the perpendicular bisector, then it creates a 90 degree angle
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A B 90 degrees n is the perpendicular bisector of the segmen AB
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ㄱ 90 degrees n is the perpendicular bisector of the segmen AB
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90 degrees n is the perpendicular bisector of XY
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90 degrees Q is the perpendicular bisector of OP
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If a point lies on the perpendicular bisector of a segment then it is equidistant from both of the endpoints of the segment. XA=XB
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Example 1 : AB and CB 1.AB=CB 2.5z+23=6z+14 3.9=1z 4.Z=9 5.5(9)+23 AB=68 6.6(9)+14 CB=68
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Find X X=24 Since l is perpendicular bisector of TU, W is the midpoint of TU. <TWV and <WUV are right angles by def. of perpendicular. Later WV=VW by reflexive property. VT=VU by CPCT So X=24
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AA point lies on the perpendicular bisector of a segment if and only if is equidistant from both of the sides
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