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Fundamentals of Electric Circuits Chapter 11

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1 Fundamentals of Electric Circuits Chapter 11
Copyright © The McGraw-Hill Companies, Inc. Permission required for reproduction or display.

2 Overview The concept of power in an AC circuit.
The difference between instantaneous power and average power. The difference between resistive and reactive. Other forms of averaged measurements will be covered Apparent power and complex power.

3 Instantaneous Power This is the power at any instant in time.
It is the rate at which an element absorbs power Consider the generalized case where the voltage and current at the terminals of a circuit are: Multiplying the two together, yields:

4 Instantaneous Power II
Note that this has two components. One is constant, depending on the phase difference between the voltage and current The second is sinusoidal with a frequency twice that of the voltage and current. A sketch of the possible instantaneous power is below.

5 Instantaneous Power III
Note that the figure shows times where the power goes negative. This is possible with circuit elements like inductors or capacitors which can store and release energy. Note also that instantaneous power is very hard to measure as it is constantly changing. The more common power measured is average power.

6 Average Power Average power is the instantaneous power averaged over a period. It is given by: When evaluated, this returns the component of instantaneous power that was constant. The time dependent part is a sinusoid and thus averages to zero.

7 Average Power II In order to get the instantaneous power, you need to work in the time domain. But for average power it is possible to work in frequency domain. In this case, the average power is:

8 Resistive vs. Reactive Consider the case when θv= θi the voltage and current are in phase and the circuit is purely resistive: When θv- θi = ±90°, the circuit absorbs no power and is purely reactive

9 Example Find the average power supplied by the source and the average power absorbed by the resistor.

10 Example Calculate the average power absorbed by each of the five elements.

11 Maximum Average Power Transfer
How to maximize power delivered to a resistive load. The maximum power was transferred when the load resistance equaled the Thevenin resistance of the supply circuit.

12 Maximum Average Power In rectangular form, the Thevenin impedance and load impedance are: The current through the load is: The average power delivered to the load is:

13 Maximum Average Power II
We want to find the peak in this function, which means finding the derivative and identifying where it goes to zero. This must be done for both RL and XL. For ∂P/∂XL For ∂P/∂RL

14 Maximum Average Power III
Combining these one finds that XL= -XTh and RL=RTh satisfy the requirements: The load impedance must be equal to the complex conjugate of the Thevenin impedance. The maximum average power will be:

15 Example Determine the load impedance that maximizes the average power. What is the maximum power.

16 Effective Value When a time varying source is delivering power to a resistive load, we often want to know the effectiveness of that source on delivering power. This value is the DC current that delivers the same average power to a resistor as the periodic current For a periodic current, the average power absorbed is:

17 Average Power For a DC current, the average power absorbed is:
Equating these two and solving for the effective DC current yields: The effective voltage is found in a similar manner:

18 RMS The effective values for both current and voltage take the form of the square root of the average of the square of the periodic signal. This is typically referred to as the root mean square, or RMS value for short. This can be extended to any periodic function:

19 RMS II If the parameter of interest is a constant, the RMS value will be that constant. The RMS value is applicable to any periodic function, regardless of its shape. However, for a sinusoidal waveform, the RNS value is related to the amplitude as follows: RMS power can be determined from either RMS current or voltage:

20 Example Determine the rms value of the current waveform in the figure. If the current is passed through a resistor, find the average power absorbed by the resistor.

21 Apparent Power The product of RMS voltage and current will be called apparent power. Note that this is modulated by the phase difference: This will be referred to as the power factor

22 Apparent Power II Apparent power is measured in VA, to distinguish it from the average or real power. The angle θv-θi is called the power factor angle. This is equal to the angle of the load impedance if V is the voltage across the load and I is the current through it.

23 Power Factor The power factor can range from zero to unity.
Leading power factor means current leads voltage, which implies a capacitive load. Lagging power factor means current lags voltage, which implies a inductive load. Purely reactive loads will have a power factor of zero. Power factors affect the way utilities bill for electricity.

24 Example Calculate the average power absorbed by each of the five elements.

25 Complex Power The complex power, S, absorbed by an AC load is:
This may also be expressed in terms of the RMS values and load impedance as:

26 Complex Power II The complex power expressed in rectangular form is:
Where: P is the average or real power Q depends on the load’s reactance and is called reactive (or quadrature) power

27 Real and Reactive Power
The real power is the only useful power. It is measured in watts. The reactive power is a measure of the energy exchange between the source and the reactive load. It is measured in units of volt-ampere reactive (VAR)

28 Summarizing Power

29 Conservation of AC Power
Regardless of how circuit elements are connected, the total complex power delivered is equal to the total complex power absorbed by the elements. The same is true of real and reactive power, but not of apparent power.

30 Power Factor Correction
Most domestic and industrial loads, such as washing machines, air conditioners, and induction motors are inductive. They have a low, lagging power factor. The load cannot be changed, but the power factor can be increased without altering the voltage or current to the original load. This is referred to as power factor correction.

31 Adding a Capacitor To mitigate the inductive aspect of the load, a capacitor is added in parallel with the load. Looking at the phasor diagram, showing before and after adding the capacitor, the power factor has improved.

32 Adding a Capacitor II With the same supplied voltage, the current draw is less by adding the capacitor. Since power companies charge more for larger currents because it leads to larger power losses. Overall, the power factor correction benefits the power company and the consumer. By choosing a suitable size for the capacitor, the power factor can be made to be unity.

33 Adding a Capacitor III The capacitor needed in order to shift the power factor angle from θ1 to θ2 is: Note that the real power dissipated in the load is not affected by the shunt capacitor. Although it is not as common, if a load is capacitive in nature, the same treatment with an inductor can be used.

34 Example When connected to a 120-V(rms), 60-Hz power line, a load absorbs 4KWat a lagging power factor of 0.8. Find the value of capacitance nexessary to raise the pf to 0.95.

35 Wattmeter Power consumption in a AC system can be measured using a Wattmeter. The meter consists of two coils; the current and voltage coils. The current coil is designed with low impedance and is connected in series with the load. The voltage coil is designed with very large impedance and is connected in parallel with the load.


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