1. Mrs. Rivas

6. (x − 26) + x = 180 x − 26 + x = 180 2x − 26 = 180 2x = 206 x = 103 103 77 Same-side Interior angles 103 + 77 = 180 Mrs. Rivas

7. Corresponding angles (3x − 5) = (x + 55) 3x − 5 = x + 55 2x − 5 = 55 2x = 60 x = 30 3(30) − 5 = 30 + 55 90 − 5 = 30 + 55 85 = 85 Mrs. Rivas

8. (x + 20) + (x + 10) = 180 Linear Pair angles = Suppl. x + 20 + x + 10 = 180 2x + 30 = 180 2x = 150 x = 75 95 85 95 + 85 = 180 Mrs. Rivas

9. (y − 40) + y = 180 Linear Pair angles = Suppl. y − 40 + y = 180 2y − 40 = 180 2x = 220 x = 110 110 70 110 + 70 = 180 Mrs. Rivas

10. Alternate Exterior angles (2x + 6) = 42 2x + 6 = 42 2x = 36 x = 18 42 Mrs. Rivas

11. (3x − 17) + 98 = 180 3x − 17 + 98 = 180 3x + 81 = 180 3x = 99 x = 33 Same-side Interior angles 82 98 + 82 = 180 Mrs. Rivas

12. 2x + 20 + 6x + 24 = 180 8x + 44 = 180 8x = 136 x = 17 Same-side Interior angles (2x + 20) + (6x + 24) = 180 54 126 126 + 54 = 180 Mrs. Rivas

13. Alternate Exterior angles (2x + 2) = (3x − 63) 2x + 2 = 3x − 63 2x = 3x − 65 − x = − 65 x = 65 132 Mrs. Rivas

14. Linear Pair angles = Suppl. (5x − 5) + 140 = 180 5x − 5 + 140 = 180 5x + 135 = 180 5x = 45 x = 9 40 140 + 40 = 180 Mrs. Rivas

15. Same-side Interior angles (4x − 8) + 112 = 180 4x − 8 + 112 = 180 4x + 104 = 180 4x = 76 x = 19 68 112 + 68 = 180 Mrs. Rivas

16. (7x + 14) + (2x + 4) = 180 7x + 14 + 2x + 4 = 180 9x + 18 = 180 9x = 162 x = 18 140 40 140 + 40 = 180 Linear Pair angles = Suppl. Mrs. Rivas

17. (4x − 5) + (x + 20) = 180 4x − 5 + x + 20 = 180 5x + 15 = 180 5x = 165 x = 33 127 53 127 + 53 = 180 Linear Pair angles = Suppl. Mrs. Rivas

20. 19. Developing Proof Complete the flow proof below. Given:  1 and  4 are supplementary. Given Vertical ∠s are ≅ ∠2 ∠3 are supplementary ∠2 and ∠3 are supplementary Converse of same-side Interior Angles

21. Mrs. Rivas 20. Developing Proof Complete the flow proof below. ∠2 ∠3 are supplementary ∠2 and ∠3 are supplementary Give ∠s ∠s suppl. to the same ∠ are ≅ ∠1 ∠4 ∠1 ≅ ∠4