1. Potential and Kinetic Energy Problems
What is the potential energy of a rock that weighs 100 Newtons that is sitting on top of a hill 300 meters high?

2. Potential and Kinetic Energy Problems
What is the potential energy of a rock that weighs 100 Newtons that is sitting on top of a hill 300 meters high?
PE = mgh

3. Potential and Kinetic Energy Problems
What is the potential energy of a rock that weighs 100 Newtons that is sitting on top of a hill 300 meters high?
PE = mgh
PE = 100N x 300m

4. Potential and Kinetic Energy Problems
What is the potential energy of a rock that weighs 100 Newtons that is sitting on top of a hill 300 meters high?
PE = mgh
PE = 100N x 300m
PE = 30,000N*m

5. Potential and Kinetic Energy Problems
What is the potential energy of a rock that weighs 100 Newtons that is sitting on top of a hill 300 meters high?
PE = mgh
PE = 100N x 300m
PE = 30,000N*m
PE = 30,000J

6. Potential and Kinetic Energy Problems
2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s?

7. Potential and Kinetic Energy Problems
2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s?
KE = ½ mv2

8. Potential and Kinetic Energy Problems
2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s?
KE = ½ mv2
KE = ½ (14kg)(3m/s)2
Square 1st

9. Potential and Kinetic Energy Problems
2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s?
KE= ½ mv2
KE = ½ (14kg)(3m/s)2
KE = ½ (14kg) (9m2/s2)
Multiply 2nd

10. Potential and Kinetic Energy Problems
2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s?
KE= ½ mv2
KE = ½ (14kg)(3m/s)2
KE = ½ (14kg) (9m2/s2)
KE = ½ 126 kg*m2/s2 = 126 N*m

11. Potential and Kinetic Energy Problems
2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s?
KE= ½ mv2
KE = ½ (14kg)(3m/s)2
KE = ½ (14kg) (9m2/s2)
KE = ½ 126 kg*m2/s2 = 126 N*m
Kg*m/s2

12. Potential and Kinetic Energy Problems
2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s?
KE= ½ mv2
KE = ½ (14kg)(3m/s)2
KE = ½ (14kg) (9m2/s2)
KE = ½ 126 kg*m2/s2 = 126 N*m
Divide last

13. Potential and Kinetic Energy Problems
2. What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s?
KE= ½ mv2
KE = ½ (14kg)(3m/s)2
KE = ½ (14kg) (9m2/s2)
KE = ½ 126 kg*m2/s2 = 126 N*m
KE = 63 Joules

14. Potential and Kinetic Energy Problems
3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball?

15. Potential and Kinetic Energy Problems
3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball?
KE = ½ mv2

16. Potential and Kinetic Energy Problems
3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball?
KE= ½ mv2
50J = ½ (1kg)v2

17. Potential and Kinetic Energy Problems
3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball?
KE= ½ mv2
50J = ½ (1kg)v2
2 x 50J = (1kg)v2 x 2 2

18. Potential and Kinetic Energy Problems
3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball?
KE= ½ mv2
50J = ½ (1kg)v2
2 x 50J = (1kg)v2 x 2 2
100kg*m2/s2 = (1kg)v2
1 kg kg

19. Potential and Kinetic Energy Problems
3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball?
KE= ½ mv2
50J = ½ (1kg)v2
2 x 50J = (1kg)v2 x 2 2
100kg*m2/s2 = (1kg)v2
1 kg kg
100 m2/s2 = v2

20. Potential and Kinetic Energy Problems
3. A 1-kilogram ball has a kinetic energy of 50 joules. What is the velocity of the ball?
KE= ½ mv2
50J = ½ (1kg)v2
2 x 50J = (1kg)v2 x 2 2
100kg*m2/s2 = (1kg)v2
1 kg kg
100 m2/s2 = v2
10m/s = v

21. Potential and Kinetic Energy Problems
4. What is the potential energy of the rock?

22. Potential and Kinetic Energy Problems
4. What is the potential energy of the rock?
Given in kg, not Newtons…must multiply mass times gravity

23. Potential and Kinetic Energy Problems
4. What is the potential energy of the rock?
PE = mgh

24. Potential and Kinetic Energy Problems
4. What is the potential energy of the rock?
PE = mgh
PE = 95kg(9.8m/s2)(100m)

25. Potential and Kinetic Energy Problems
4. What is the potential energy of the rock?
PE = mgh
PE = 95kg(9.8m/s2)(100m)
PE = 93,100 kg*m2/s kg*m/s2 = N *m

26. Potential and Kinetic Energy Problems
4. What is the potential energy of the rock?
PE = mgh
PE = 95kg(9.8m/s2)(100m)
PE = 93,100 kg*m2/s kg*m/s2 = N *m
PE = 93,100 N*m

27. Potential and Kinetic Energy Problems
4. What is the potential energy of the rock?
PE = mgh
PE = 95kg(9.8m/s2)(100m)
PE = 93,100 kg*m2/s kg*m/s2 = N *m
PE = 93,100 N*m
PE = 93,100 J

28. Potential and Kinetic Energy Problems
5. What is the approximate difference in gravitational potential energy of the two shaded boxes?

29. Potential and Kinetic Energy Problems
5. What is the approximate difference in gravitational potential energy of the two shaded boxes?
PE = mgh

30. Potential and Kinetic Energy Problems
5. What is the approximate difference in gravitational potential energy of the two shaded boxes?
PE = mgh
PE = 2.0kg(9.8m/s2)(3.0m)

31. Potential and Kinetic Energy Problems
5. What is the approximate difference in gravitational potential energy of the two shaded boxes?
PE = mgh
PE = 2.0kg(9.8m/s2)(3.0m)
PE = 58.8 kg*m2/s2 or N*m

32. Potential and Kinetic Energy Problems
5. What is the approximate difference in gravitational potential energy of the two shaded boxes?
PE = mgh
PE = 2.0kg(9.8m/s2)(3.0m)
PE = 58.8 kg*m2/s2 or N*m
PE = 58.8 J

33. Potential and Kinetic Energy Problems
5. What is the approximate difference in gravitational potential energy of the two shaded boxes?
PE = mgh

34. Potential and Kinetic Energy Problems
5. What is the approximate difference in gravitational potential energy of the two shaded boxes?
PE = mgh
PE = 2.0kg (9.8m/s2)(1.0m)

35. Potential and Kinetic Energy Problems
5. What is the approximate difference in gravitational potential energy of the two shaded boxes?
PE = mgh
PE = 2.0kg (9.8m/s2)(1.0m)
PE = 19.6 kg*m/s2 or N*m

36. Potential and Kinetic Energy Problems
5. What is the approximate difference in gravitational potential energy of the two shaded boxes?
PE = mgh
PE = 2.0kg (9.8m/s2)(1.0m)
PE = 19.6 kg*m/s2 or N*m
PE = 19.6 J

37. Potential and Kinetic Energy Problems
5. What is the approximate difference in gravitational potential energy of the two shaded boxes?
58.8J – 19.6J = 39.2J