1. Chapter 10 NMR in Practice I.Chemical Equivalence A.Using Molecular Symmetry 1)Chemically equivalent protons have identical chemical shifts 2)It is not always easy to see if protons are equivalent 3)If protons are related by a mirror plane, they are equivalent 4)If protons are related by a rotational axis, they are equivalent 5)Rotational axis = line of molecular rotation producing identical structures

2. B.Conformational Changes can cause equivalence 1)Chloroethane has 2 1 H NMR peaks, not 3 a)Conformational rotation averages out gauche and anti positions b)Must be fast on the NMR timescale (Lifetime < 1 s) c)Cool down solution to –180 o C to see all three peaks 2)Cyclohexane has only one 1 H NMR peak, not 2 a)Axial and equatorial protons have different chemical environments b)Ring flip conformational change is fast on NMR timescale, averages out the axial and equatorial protons to one peak c)Cool to –90 o C to see both peaks

3. II.Integration A.The number of protons responsible for a peak determines the peak size 1)Integration = finding the area under a 1 H NMR peak 2)The NMR computer will trace a line above each peak that has its length proportional to the area under the peak 3)We measure the length of each line (area under each peak) and compare them with each other 4)There can only be integer numbers of protons, so we normalize to whole #

4. B.We can use chemical shift and integration to assign structure 1)Dichlorination of propane: 2)CH 3 CH 2 CHCl 2 1H 2H 3H 3)ClCH 2 CH 2 CH 2 Cl 4H 2H 4)CH 3 CHClCH 2 Cl 1H 2H 3H III.Spin-Spin Splitting A.Neighboring protons effect each other 1)Protons are tiny magnets, with  and  spin states in a magnetic field 2)Proton on the same carbon or on adjacent carbons influence the total magnetic field felt by their neighbor, just as e- magnetic field does 3)Simple case of one proton on each adjacent carbon

5. 4)This phenomenon is called Spin-Spin Splitting 5)Single peak is split into a Multiplet by spin-spin splitting Singlet, Doublet, Triplet, Quartet, etc… to Multiplet 6)Coupling Constant = J (Hz) = how far apart the multiplet peaks are 7)Spin-spin splitting is only seen for: a)Geminal Protons = chemically inequivalent protons on the same carbon (J up to 18 Hz) b)Vicinal Protons = chemically inequivalent protons on adjacent carbons (J = 6-8 Hz) c)Both protons are always split by same J. If H a splits H b, then H b splits H a by the same amount d)Chemically equivalent protons do not split each other B.Local Field Effects are Additive 1)What if a proton has multiple neighboring protons? Triplet, 1:2:1, 3H, 1.5 ppm Quartet, 1:3:3:1, 2H, 1.3 ppm

6. 2)N + 1 Rule = N equivalent nuclei split a neighboring proton resonance into N + 1 peaks a)CH—CH 3 doublet(3H) and quartet(1H) b)CH 2 —CH 3 triplet(3H) and quartet(2H) 3)Pascal’s Triangle Predicts relative intensities of the peaks in a multiplet

7. 4)Example: Bromoethane

8. 5)Example: 2-Iodopropane

9. 6)Example: 1,1-dichloro-2,2-diethoxyethane

11. D.Complications to Splitting Patterns 1)First Order Spectrum =  >> J (easy to see all splitting) 2)Non-First Order Spectrum =  = J (all smashed together) 3)You can go to higher magnetic field to spread it back out 90 MHz 500 MHz

12. 4)Many close  peaks in same molecule = won’t see all of the splitting Long Alkyl Chains are Notorious for this

13. 5)We must take into account all neighbors, when predicting splitting a)Predict splitting based on one type of neighbor b)Apply splitting by other type of neighbor to each of the split peaks from the first type of neighbor

14. 6)Sometimes the spectrum will appear First Order, but isn’t (J’s are same)

15. 7)Fast Proton Exchange “Decouples” some protons a)RCH 2 OH protons exchange quickly with protic solvents b)See an average RCH 2 O—H peak c)Happens fast on the NMR time scale d)See no coupling to the CH 2 group, unless you cool solution down E.NMR Solvents 1)You usually take NMR spectra of a sample dissolved in a solvent 2)The fast tumbling of molecules in solution is best for NMR 3)Solvent is at much greater concentration than sample, so you would see only the solvent protons in your spectrum 4)We use Deuterated solvents ( 2 H) because they have the same chemical properties (solubilities) but have shifts outside the 1 H range. 5)You can’t get rid of all 1 H, so you usually still see a small solvent peaks CH 3 OH

16. IV.Carbon-13 NMR A.Abundance of 13 C effects its use in NMR 1)98.9% of carbon is 12 C, 1.11% is 13 C 2)Much weaker signal for carbon NMR, we must take many scans, ( time) 3) 13 C- 13 C next to each other is statistically unlikely; no C-C splitting 4)Carbon peaks are split by the 1 H’s attached to them a)Useful to tell us how many H’s are attached (triplit = CH 2 ) b)Usually Decouple the protons with a broad constant proton pulse, which keeps protons  flipping and gives no splitting c)Decoupling produces all singlets in the 13 C NMR spectrum B.Chemical Shift in Carbon-13 NMR 1)Carbon resonances occur over a large range 0-250 ppm (TMS = 0 ppm) 2)This is very useful, because often proton NMR is smashed together 3)Every chemically inequivalent carbon gives a unique singlet a)Alkyl groups: 5-50 ppm b)Alkyl Halides: 25-50 c)Alcohols/Ethers: 50-90 d)Alkenes:100-150 e)Carbonyl: 170-210

17. Bromoethane Carbon-13 NMR

18. C.DEPT (Distortionless Enhanced Polarization Transfer) 1) 13 C NMR Experiment that tells you how many H’s are attached to each C D.Using 13 C NMR to assign structure All C’s CH only +CH 3 and –CH 2 only

19. COSY 2D NMR Spectrum

20. HETCOR 2D NMR Spectrum