2.  The limited Reagent is the reactant in a chemical reaction that limits the amount of product that can be formed.  The molecule that produces the least of moles/grams.  To solve for limiting reagent you need to use mole to mole ratio. What you WANT What you HAVE What they GIVE x

3. Given 1.8 mol. of C4H10 and 16 moles of O2. Which is the limiting reagent ? 2 C4H10 + 13 O28 CO2 + 10 H2O C 4 H 10 O2O2 Solving for H 2 O 1.8 x 10 H2O 2 C4H10 multiply 18 2 = 9 9 moles of H2O WANT HAVE GIVEx 16 x 10 H2O 13 O2 multiply 160 13 = 12.3 12.3 moles of H2O

4. Given 6 mol. of C4H10 and 8 moles of O2. Which is the limiting reagent ? 2 C4H10 + 13 O28 CO2 + 10 H2O C 4 H 10 O2O2 Solving for H 2 O 6 x 10 H2O 2 C4H10 multiply 60 2 = 30 30 moles of H2O WANT HAVE GIVEx 8 x 10 H2O 13 O2 multiply 80 13 = 6.15 6.15 moles of H2O

5. 2 C5H12 + 8 O25 CO2 + 6 H2O  16 moles CO2 & 4 moles C5H12 19.2 moles from CO2 & 12 moles from CO2  4 moles C5H12 & 27 moles of O2 12 from C5H12 & 20.5 moles from O2  11 moles of C5H12 & 18 mol of O2 31 moles by O2 & 13.5 by O2  6 moles of C5H12 & 20 moles of O2 18 moles produced by c5H12 & 15 by O2