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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 1 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege.edu Engineering 43 Chp 14-2 Op Amp Circuits
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 2 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis RC OpAmp Circuits Introduce Two Very Important Practical Circuits Based On Operational Amplifiers Recall the OpAmp The “Ideal” Model That we Use R O = 0 R i = ∞ A v = ∞ BW = ∞ Consequences of Ideality R O = 0 v O = A v (v + − v − ) R i = ∞ i + = i − = 0 A v = ∞ v + = v − BW = ∞ OpAmp will follow the very Highest Frequency Inputs
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 3 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis RC OpAmp Ckt Integrator KCL At v − node By Ideal OpAmp R i = ∞ i + = i − = 0 A v = ∞ v + = v − = 0 0 v
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 4 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis RC OpAmp Integrator cont By the Ideal OpAmp Assumptions Separating the Variables and Integrating Yields the Solution for v o (t) A simple Differential Eqn Thus the Output is a (negative) SCALED TIME INTEGRAL of the input Signal
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 5 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis RC OpAmp Ckt Differentiator By Ideal OpAmp v − = GND = 0V i − = 0 KCL at v − KVL Now the KVL 0 v
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 6 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis RC OpAmp Differentiator cont. Recall Ideal OpAmp Assumptions R i = ∞ i + = i − = 0 A v = ∞ v + = v − = 0 Then the KCL Recall the Capacitor Integral Law Thus the KVL Multiply Eqn by C 1, then Take the Time Derivative of the new Eqn
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 7 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis RC OpAmp Differentiator cont In the Previous Differential Eqn use KCL to sub v O for i 1 Using Examination of this Eqn Reveals That if R 1 were ZERO, Then v O would be Proportional to the TIME DERIVATIVE of the input Signal In Practice An Ideal Differentiator Amplifies Electrical Noise And Does Not Operate well The Resistor R 1 Introduces a Filtering Action. –Its Value Is Kept As Small As Possible To Approximate a Differentiator
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 8 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Aside → Electrical Noise ALL electrical signals are corrupted by external, uncontrollable and often unmeasurable, signals. These undesired signals are referred to as NOISE The Signal-To-Noise Ratio Simple Model For A Noisy 1V, 60Hz Sinusoid Corrupted With One MicroVolt of 1GHz Interference SignalNoise Use an Ideal Differentiator The SN is Degraded Due to Hi-Frequency Noise SignalNoise
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 9 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Class Exercise Ideal Differen. Given Input v 1 (t) SAWTOOTH Wave Let’s Turn on the Lites for 10 minutes for YOU to Differentiate Given the IDEAL Differentiator Ckt and INPUT Signal Find v o (t) over 0-10 ms Recall the Differentiator Eqn R 1 = 0; Ideal ckt
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 10 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis RC OpAmp Differentiator Ex. Given Input v 1 (t) The Slope from 0-5 mS For the Ideal Differentiator Units Analysis
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 11 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis RC OpAmp Differentiator cont. Derivative Scalar PreFactor A Similar Analysis for 5-10 mS yields the Complete v O Apply the Prefactor Against the INput Signal Time-Derivative (slope) InPutOutPut
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 12 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis RC OpAmp Integrator Example Given Input v 1 (t) SQUARE Wave For the Ideal Integrator Units Analysis Again
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 13 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis RC OpAmp Integrator Ex. cont. The Integration PreFactor 0<t<0.1 S v 1 (t) = 20 mV (Const) Next Calculate the Area Under the Curve to Determine the Voltage Level At the Break Points 0.1 t<0.2 S v 1 (t) = –20 mV (Const) Integrate In Similar Fashion over 0.2 t<0.3 S 0.3 t<0.4 S
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 14 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis RC OpAmp Integrator Ex. cont.1 Apply the 1000/S PreFactor and Plot Piece-Wise
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 15 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Design Example Design an OpAmp ckt to implement in HARDWARE this Math Relation Examine the Reln to find an Integrator Summer
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 16 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Design Example The Proposed Solution The by Ideal OpAmps & KCL & KVL & Superposition
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 17 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Design Example Then the Design Eqns The Ckt Eqn TWO Eqns in FIVE unknowns This means that we, as ckt designers, get to PICK 3 values For 1 st Cut Choose C = 20 μF R 1 = 100 kΩ R 4 = 20 kΩ
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 18 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Design Example In the Design Eqns If the voltages are <10V, then all currents should be the in mA range, which should prevent over-heating 20μ 100k 20k 10k 20k Then the DESIGN
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 19 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis LM741 OpAmp Schematic
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 20 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Some LM741 Specs
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 21 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis OpAmp Frequency Response The Ideal OpAmp has infinite Band- Width so NO Matter how FAST the input signals However, REAL OpAmps Can NOT Keep up with very fast signals The Open Loop Gain, A O, starts to degrade with increasing input frequencies
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 22 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Gain∙BandWidth for LM741 −20db/Decade Slope The Unity Gain Frequency, f t, is the BandWidth Spec
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 23 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis BandWidth Limit Implications Recall the OpAmp based Inverting ckt The NONideal Analysis yielded Noting That All the R’s are Constant; Rewrite above as For Very Large A
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 24 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis BandWidth Limit Implications As Frequency Increases the Open- Loop gain, A, declines so the Limit does NOT hold in: If Then the Denom in the above Eqn ≠ 1 Thus significantly smaller A DECREASES the Ideal gain For Typical Values of the R’s the Open- Loop Gain, A, becomes important when A is on the order of about 1000
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 25 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Gain∙BandWidth for LM741 Frequency significantly degrades Amplification Performance for Source Frequencies > 10 kHz
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 26 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Voltage Swing Limitations Real OpAmps Can NOT deliver Unlimited Voltage- Magnitude Output Recall the LM741 Spec Sheet that show a Voltage Output Swing of about ±15V For Source Voltages of ±20 V If the Circuit Analysis Predicts v o of more than the Swing, the output will be “Clipped” Consider the Inverting Circuit:
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 27 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Vswing Clipping Since the Real OutPut can NOT exceed 15V, the cosine wave OutPut is “Clipped Off” at the Swing Spec of 15V ENGR43_Lec14b_OpAmp_V_Swing_Plot_1204.m
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 28 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Short-Ckt Current Limitations Real OpAmps Can NOT deliver Unlimited Current- Magnitude Output Recall the LM741 Spec Sheet that shows an Output Short Circuit Current of about 25mA If the Circuit Analysis Predicts i o of more than This Current, the output will also be “Clipped” Consider the Inverting Circuit:
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 29 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Current Saturation Since the Real OutPut can NOT exceed 25mA, the cosine wave OutPut is “Clipped Off” at the Short Circuit Current spec of 25mA ENGR43_Lec14b_OpAmp_Current_Saturation_ Plot_1204.m
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 30 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Slew Rate = dv o /dt For a Real OpAmp we expect the OutPut Cannot Rise or Fall Infinitely Fast. This Rise/Fall Speed is quantified as the “Slew Rate”, SR Mathematically the Slew Rate limitation The 741 Specs indicate a Slew Rate of
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 31 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Slew Rate = dv o /dt If dv in /dt exceeds the SR at any point in time, then the output will NOT be Faithful to input The OpAmp can NOT “Keep Up” with the Input Consider the Example at Top Right Then the Time Slope of the Source
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 32 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Slew Rate = dv o /dt The Maximum value of dv S /dt Occurs at t=0. Compare the max to the SR Thus the source Rises & Falls Faster than the SR When the Source Slope exceeds the SR the OpAmp Output Rises/Falls at the SR This produces a STRAIGHT-LINE output with a slope of the SR when the source rises/falls Faster than the SR until the OpAmp “Catches Up” with the Ideal OutPut
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 33 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Slew Rate = dv o /dt
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 34 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Full Power BandWidth The Full Power BW is the Maximum Frequency that the OpAmp can Deliver an Undistorted Sinusoidal Signal The Quantity, f FP, is limited by the SLEW RATE Determine This Metric for the LM741 The 741 has a max output, V om, of ±12V Applying a sinusoid to the input find at full OutPut power (Full Output Voltage) Recall the Slew Rate
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 35 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Full Power BandWidth Taking d/dt of the OpAmp running at Full Output Thus the maximum output change-rate (slope) in magnitude Recall ω = 2πf Setting |dv o /dt| max = to the Slew Rate
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 36 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Full Power BandWidth Isolating f in the last expression yields f FP : From the LM741 Spec Sheet SR = 0.5 V/µS |V omax | min = 12V Then f FP :
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 37 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Full Power BandWidth Thus the 741 OpAmp can deliver UNdistorted, Full Voltage, sinusoidal Output (±12V) for input Frequencies up to about 6.63 kHz
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 38 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis WhiteBoard Work Let’s Work These Probs Choose C Such That Find Energy Stored on Cx
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 39 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis All Done for Today OpAmp Circuit Design
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 40 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Bruce Mayer, PE Registered Electrical & Mechanical Engineer BMayer@ChabotCollege.edu Engineering 43 Appendix
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 41 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 42 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 43 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 44 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 45 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 46 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Practical Example Simple Circuit Model For a Dynamic Random Access Memory Cell (DRAM) Also Note the TINY Value of the Cell-State Capacitance (50x10 -15 F) Note How Undesired Current Leakage is Modeled as an I-Src
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 47 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Practical Example cont The Criteria for a Logic “1” V cell >1.5 V Now Recall that V = Q/C Or in terms of Current During a WRITE Cycle the Cell Cap is Charged to 3V for a Logic-1 Thus The TIME PERIOD that the cell can HOLD the Logic-1 value Now Can Calculate the DRAM “Refresh Rate”
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BMayer@ChabotCollege.edu ENGR-43_Lec-14a_IDeal_Op_Amps.pptx 48 Bruce Mayer, PE Engineering-43: Engineering Circuit Analysis Practical Example cont.2 Consider the Cell at the Beginning of a READ Operation Then The Output Calc the Best-Case Change in V I/O at the READ When the Switch is Connected Have Caps in Parallel
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