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The Chemistry of Acids and Bases
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Acids and Bases: Calculate pH/pOH At the conclusion of our time together, you should be able to: 1. Change any pH reading to pOH 2. Convert pH to concentration of hydronium ion concentrations, hydronium ion concentrations to pH
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Review of the pH Scale Since 1 mole of OH - in one Liter of water would be a pOH = 0 And the pH and pOH of water is 7 or neutral, Therefore, the pH of a strong base with a pOH of 0 would be pH = 14 Therefore, any pH can be converted to pOH by subtracting from 14.
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Examples of Converting pH If an acid has a pH of 3, what would be the pOH? 14 – 3 = 11 If an base has a pOH of 2, what would be the pH? 14 – 2 = 12
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Calculating the pH pH = - log [H+] (Remember that the [ ] mean Molarity) Example: If [H + ] = 1 X 10 -10 pH = - log 1 X 10 -10 pH = - (- 10) pH = 10 Example: If [H + ] = 1.8 X 10 -5 pH = - log 1.8 X 10 -5 pH = - (- 4.74) pH = 4.74
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pH Calculations – Solving for H + on Worksheet #1 If the pH of Coke is 3.55, [H + ] = ??? Because pH = - log [H + ] then - pH = log [H + ] - pH = log [H + ] Take antilog/inverse log (10 x ) of both sides and get 10 -pH = [H + ] [H + ] = 10 -3.55 = 2.82 x 10 -4 M *** to find antilog/inverse on your calculator, look for “Shift” or “2 nd function” and then the log button *** to find antilog/inverse on your calculator, look for “Shift” or “2 nd function” and then the log button
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Worksheet #2, #3 If an acid has a pH of 3.55, what would be the pOH? 14 – 3.55 = 10.45 What is the concentration of OH - ? [OH - ] = 10 -10.45 = 3.55 x 10 -11 M
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pH Calculations – #4 A solution has a [OH - ] of 4.25 x 10 -4. pOH = - log [OH - ] pOH = - log [4.25 x 10 -4 ] pOH = 3.37 pH = 14 – 3.37 = 10.63 pOH = - log [OH - ] pOH = - log [4.25 x 10 -4 ] pOH = 3.37 pH = 14 – 3.37 = 10.63
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pH [H + ] [OH - ] pOH
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A Former Student Trying to Apply His Knowledge of Chemistry!!
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[OH - ] [H + ] pOH pH 10 -pOH 10 -pH -Log[H + ] Log[OH - ] -Log[OH - ] 14 - pOH 14 - pH 1.0 x 10 -14 [OH - ] [OH - ] 1.0 x 10 -14 [H + ] [H + ]
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Acids and Bases: Calculate pH/pOH Let’s see if you can: 1. Change any pH reading to pOH 2. Convert pH to concentration of hydronium ion concentrations, hydronium ion concentrations to pH
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Calvin’s Approach to Math in Chemistry:
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If a solution has a pH of 6.5, what is the pOH of that same solution? 1234567891011121314151617181920 21222324252627282930 1. 4.5 2. 7.5 3. 6.5 4. 0.0 5. 12.5
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If a solution has a pH of 8.6, what is the [H + ] of that solution? 1234567891011121314151617181920 21222324252627282930 1. 8.6 2. 2.51 x 10 -9 3. 1.0 x 10 8.6 4. 1.0 x 10 5.4 5. 5.4
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If a solution has a pOH of 9.44, what is the [OH - ] of that same solution? 1234567891011121314151617181920 21222324252627282930 1. 0.975 2. 1.00 x 10 9.44 3. 3.63 x 10 -10 4. 4.56 5. 9.44
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If a solution has a [H 3 O + ] of 6.20 x 10 -8, what is the pH of that solution? 1234567891011121314151617181920 21222324252627282930 1. 6.79 2. 8.79 3. 5.21 4. 4.56 5. 7.21
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If a solution has a [OH - ] of 1.05 x 10 -3, what is the pH of that solution? 1234567891011121314151617181920 21222324252627282930 1. 11.02 2. 2.98 3. 1.00 4. 3.02 5. 10.98
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Acid Base Calculation Practice #1 pH = 12.40, what would be the pOH? 14 – 12.40 = 1.60 What is the concentration of OH - ? [OH - ] = 10 -1.60 = 0 0251 M
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Acid Base Calculation Practice #2 pOH? of 0.00162 M KOH pOH = - log 0.00162 = 2.79 pH = 14 – 2.79 = 11.21
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Converting pH to pOH If an acid has a pH of 6, what would be the pOH? 14 – 6 = 8888
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[H 3 O + ], [OH - ] and pH What is the pH of the 0.0010 M NaOH solution? [OH - ] = 0.0010 (or 1.0 X 10 -3 M) pOH = - log 0.0010 pOH = - log 0.0010 pOH = 3 pOH = 3 pH = 14 – 3 = 11 pH = 14 – 3 = 11
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The pH of rainwater collected in a certain region of the northeastern United States on a particular day was 4.82. What is the H + ion concentration of the rainwater? The OH - ion concentration of a blood sample is 2.5 x 10 -7 M. What is the pH of the blood? Try These! 1.51 x 10 -5 pOH = 6.6 14.0 – 6.6 = 7.4 pH
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Calculating [H 3 O + ], pH, [OH - ], and pOH Problem 1: A chemist dilutes concentrated hydrochloric acid to make two solutions: (a) 3.0 M and (b) 0.0024 M. Calculate the [H 3 O + ], pH, [OH - ], and pOH of the two solutions at 25°C. [H 3 O + ] = 3.0 M pH = -0.47 [OH - ] = 3.388 x 10 -15 M pOH = 14.47 [H 3 O + ] = 0.0024 M pH = 2.6 [OH - ] = 3.98 x 10 -12 M pOH = 11.4
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Calculating [H 3 O + ], pH, [OH - ], and pOH Problem 2: What is the [H 3 O + ], [OH - ], and pOH of a solution with pH = 3.67? Is this an acid, base, or neutral? [H 3 O + ] = 2.14 x 10 -4 M pH = 3.67 [OH - ] = 4.677 x 10 -11 M pOH = 10.33
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