1. Algebra 1 Unit 2 Review

2. Mrs. Fox wants to take her children to Hartford Stage to see a play. Tickets cost $55 per person, there is a handling fee of $2.00 per ticket and a parking voucher will cost $6.50. If she spends $405.50 for tickets, handling fees, and parking, how many tickets did she buy? Define your variables, write an equation, and solve it to determine the number of tickets that Mrs. Fox bought. Algebra 1 – Unit 2 Review

3. ANSWER let t = number of tickets (55 + 2)t + 6.50 = 405.50 t = 7 tickets Algebra 1 – Unit 2 Review Mrs. Fox wants to take her children to Hartford Stage to see a play. Tickets cost $55 per person, there is a handling fee of $2.00 per ticket and a parking voucher will cost $6.50. If she spends $405.50 for tickets, handling fees, and parking, how many tickets did she buy? Define your variables, write an equation, and solve it to determine the number of tickets that Mrs. Fox bought.

4. Algebra 1 – Unit 2 Review Phyllis the plumber is a busy lady. For service calls to homes she uses the following formula to figure out how much to charge for her labor (materials are extra of course): c = 40n + 60 where c is the amount she charges and n is the number of hours she works. What is the meaning of 40 in the formula above? What is the meaning of 60 in the formula above?

5. ANSWER Algebra 1 – Unit 2 Review Phyllis the plumber is a busy lady. For service calls to homes she uses the following formula to figure out how much to charge for her labor (materials are extra of course): c = 40n + 60 where c is the amount she charges and n is the number of hours she works. What is the meaning of 40 in the formula above? What is the meaning of 60 in the formula above? $40 is how much she charges for each additional hour of work. Phyllis charges $60 just to get to the house.

6. Algebra 1 – Unit 2 Review Phyllis the plumber is a busy lady. For service calls to homes she uses the following formula to figure out how much to charge for her labor (materials are extra of course): c = 40n + 60 where c is the amount she charges and n is the number of hours she works. If she works at a house for 2 hours, how much would she charge for labor? A bill comes to $150. That includes $30 for materials. How long did that job take?

7. ANSWER Algebra 1 – Unit 2 Review Phyllis the plumber is a busy lady. For service calls to homes she uses the following formula to figure out how much to charge for her labor (materials are extra of course): c = 40n + 60 where c is the amount she charges and n is the number of hours she works. If she works at a house for 2 hours, how much would she charge for labor? A bill comes to $150. That includes $30 for materials. How long did that job take? $140 1.5 hours

8. Algebra 1 – Unit 2 Review Solve the following equation. Justify each step. x + 6x + 38 = 2(5x + 10)

9. Solve the following equation. Justify each step. x + 6x + 38 = 2(5x + 10) x + 6x + 38= 10x + 20distributive property 7x + 38= 10x + 20combining like terms 7x + -7x + 38= 10x – 7x + 20subtraction property of = 38= 3x + 20 38 – 20 = 3x + 20 – 20 subtraction property of = 18 = 3x 18/3 = 3x/3division property of = 6 = x x = 6 ANSWER Algebra 1 – Unit 2 Review

11. ANSWER Algebra 1 – Unit 2 Review x = 7

12. Algebra 1 – Unit 2 Review Solve the formula y = mx + b for x.

13. ANSWER Algebra 1 – Unit 2 Review

15. ANSWER Algebra 1 – Unit 2 Review

16. Translate each real world situation into an inequality using the appropriate inequality symbol. 1.You must be less than 48 inches tall to ride the kiddie rides at the amusement park. 2.The cost of a meal there is at least $18. 3.I am spending no more than $70 for the visit.

17. Translate each real world situation into an inequality using the appropriate inequality symbol. 1.You must be less than 48 inches tall to ride the kiddie rides at the amusement park. 2.The cost of a meal there is at least $18. 3.I am spending no more than $70 for the visit. ANSWER Algebra 1 – Unit 2 Review h < 48 m ≥ 18 v ≤ 70

18. Algebra 1 – Unit 2 Review

19. ANSWER Algebra 1 – Unit 2 Review p ≤ -5 -8 -7 -6 -5 -4 -3 -2 -1

20. Algebra 1 – Unit 2 Review A jar can hold no more than 500 jellybeans. There are 200 in the jar right now. You are filling it with handfuls of jellybeans taken from a bag. Each handful has 30 beans. How many handfuls can you put into the jar? Define a variable, write an inequality, and solve.

21. ANSWER Algebra 1 – Unit 2 Review n is the number of handfuls 30n + 200 ≤ 500 n ≤ 10 A jar can hold no more than 500 jellybeans. There are 200 in the jar right now. You are filling it with handfuls of jellybeans taken from a bag. Each handful has 30 beans. How many handfuls can you put into the jar? Define a variable, write an inequality, and solve.