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1/23/07184 Lecture 91 PHY 184 Spring 2007 Lecture 9 Title: The Electric Potential
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1/23/07184 Lecture 92AnnouncementsAnnouncements Homework Set 2 done, Set 3 ongoing and Set 4 will open on Thursday Helproom hours of the TAs are listed on the syllabus in LON-CAPA Honors Option students will provide help in the in the SLC starting this week. Remember Clicker’s Law… Up to 5% (but not more!)
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1/23/07184 Lecture 93 Review - Potential Energy When an electrostatic force acts between charged particles, assign an electric potential energy, U. The difference in U of the system in two different states, initial i and final f, is Reference point: Choose U=0 at infinity. If the system is changed from initial state i to the final state f, the electrostatic force does work, W Potential energy is a scalar.
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1/23/07184 Lecture 94 Review - Work Work done by an electric field Q is the angle between electric field and displacement (1) Positive W U decreases (2) Negative W U increases
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1/23/07184 Lecture 95 Clicker Question In the figure, a proton moves from point i to point f in a uniform electric field directed as shown. Does the electric field do positive, negative or no work on the proton? A: positive B: negative C: no work is done on the proton
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1/23/07184 Lecture 96 Clicker Question In the figure, a proton moves from point i to point f in a uniform electric field directed as shown. Does the electric field do positive, negative or no work on the proton? B: negative
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1/23/07184 Lecture 97 Electric Potential V The electric potential, V, is defined as the electric potential energy, U, per unit charge The electric potential is a characteristic of the electric field, regardless of whether a charged object has been placed in that field. (because U q) The electric potential energy is an energy of a charged object in an external electric field (or more precisely, an energy of the system consisting of the charged object and the external field).
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1/23/07184 Lecture 98 Electric Potential Difference V The electric potential difference between an initial point i and final point f can be expressed in terms of the electric potential energy of q at each point Hence we can relate the change in electric potential to the work done by the electric field on the charge
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1/23/07184 Lecture 99 Electric Potential Difference (2) Taking the electric potential energy to be zero at infinity we have where W e, is the work done by the electric field on the charge as it is brought in from infinity. The electric potential can be positive, negative, or zero, but it has no direction. (i.e., scalar not vector) The SI unit for electric potential is joules/coulomb, i.e., volt. Explain: i = , f = x, so that V = V(x) 0
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1/23/07184 Lecture 910 The Volt The commonly encountered unit joules/coulomb is called the volt, abbreviated V, after the Italian physicist Alessandro Volta (1745 - 1827) With this definition of the volt, we can express the units of the electric field as For the remainder of our studies, we will use the unit V/m for the electric field.
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1/23/07184 Lecture 911 Example - Energy Gain of a Proton A proton is placed between two parallel conducting plates in a vacuum as shown. The potential difference between the two plates is 450 V. The proton is released from rest close to the positive plate. What is the kinetic energy of the proton when it reaches the negative plate? + - = V(+)-V( ) The potential difference between the two plates is 450 V. The change in potential energy of the proton is U, and V = U / q (by definition of V), so U = q V = e[V( ) V(+)] = 450 eV
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1/23/07184 Lecture 912 Example - Energy Gain of a Proton (2) Because the acceleration of a charged particle across a potential difference is often used in nuclear and high energy physics, the energy unit electron-volt (eV) is common. An eV is the energy gained by a charge e that accelerates across an electric potential of 1 volt The proton in this example would gain kinetic energy of 450 eV = 0.450 keV. initial final Conservation of energy K = U = + 450 eV Because the proton started at rest, K = 1.6x10 -19 C x 450 V = 7.2x10 -17 J
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1/23/07184 Lecture 913 The Van de Graaff Generator A Van de Graaff generator is a device that creates high electric potential. The Van de Graaff generator was invented by Robert J. Van de Graaff, an American physicist (1901 - 1967). Van de Graaff generators can produce electric potentials up to many 10s of millions of volts. Van de Graaff generators can be used to produce particle accelerators. We have been using a Van de Graaff generator in lecture demonstrations and we will continue to use it.
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1/23/07184 Lecture 914 The Van de Graaff Generator (2) The Van de Graaff generator works by applying a positive charge to a non-conducting moving belt using a corona discharge. The moving belt driven by an electric motor carries the charge up into a hollow metal sphere where the charge is taken from the belt by a pointed contact connected to the metal sphere. The charge that builds up on the metal sphere distributes itself uniformly around the outside of the sphere. For this particular Van de Graaff generator, a voltage limiter is used to keep the Van de Graaff generator from producing sparks larger than desired.
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1/23/07184 Lecture 915 The Tandem Van de Graaff Accelerator One use of a Van de Graaff generator is to accelerate particles for condensed matter and nuclear physics studies. Clever design is the tandem Van de Graaff accelerator. A large positive electric potential is created by a huge Van de Graaff generator. Negatively charged C ions get accelerated towards the +10 MV terminal (they gain kinetic energy). Terminal at +10MV C -1 C +6 Stripper foil strips electrons from C Electrons are stripped from the C and the now positively charged C ions are repelled by the positively charged terminal and gain more kinetic energy.
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1/23/07184 Lecture 916 Example - Energy of Tandem Accelerator Suppose we have a tandem Van de Graaff accelerator that has a terminal voltage of 10 MV (10 million volts). We want to accelerate 12 C nuclei using this accelerator. What is the highest energy we can attain for carbon nuclei? What is the highest speed we can attain for carbon nuclei? There are two stages to the acceleration The carbon ion with a -1e charge gains energy accelerating toward the terminal The stripped carbon ion with a +6e charge gains energy accelerating away from the terminal 15 MV Tandem Van de Graaff at Brookhaven
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1/23/07184 Lecture 917 Example - Energy of Tandem Accelerator (2)
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1/23/07184 Lecture 918 Equipotential Surfaces and Lines When an electric field is present, the electric potential has a given value everywhere in space. V(x) = potential function Points close together that have the same electric potential form an equipotential surface. i.e, V(x) = constant value If a charged particle moves on an equipotential surface, no work is done. Equipotential surfaces exist in three dimensions. We will often take advantage of symmetries in the electric potential and represent the equipotential surfaces as equipotential lines in a plane. Equipotential surface from eight point charges fixed at the corners of a cube
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1/23/07184 Lecture 919 If a charged particle moves perpendicular to electric field lines, no work is done. If the work done by the electric field is zero, then the electric potential must be constant Thus equipotential surfaces and lines must always be perpendicular to the electric field lines. if d E General Considerations
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1/23/07184 Lecture 920 Electric field lines and equipotential surfaces
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1/23/07184 Lecture 921 Constant Electric Field Electric field lines: straight lines parallel to E Equipotential surfaces (3D): planes perp to E Equipotential lines (2D): straight lines perp to E
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1/23/07184 Lecture 922 Electric Field from a Single Point Charge Electric field lines: radial lines emanating from the point charge. Equipotential surfaces (3D): concentric spheres Equipotential lines (2D): concentric circles
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1/23/07184 Lecture 923 Electric Field from Two Oppositely Charged Point Charges The electric field lines from two oppositely charge point charges are a little more complicated. The electric field lines originate on the positive charge and terminate on the negative charge. The equipotential lines are always perpendicular to the electric field lines. The red lines represent positive electric potential. The blue lines represent negative electric potential. Close to each charge, the equipotential lines resemble those from a point charge.
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1/23/07184 Lecture 924 ELECTRIC DIPOLE
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1/23/07184 Lecture 925 Electric Field from Two Identical Point Charges The electric field lines from two identical point charges are also complicated. The electric field lines originate on the positive charge and terminate at infinity. Again, the equipotential lines are always perpendicular to the electric field lines. There are only positive potentials. Close to each charge, the equipotential lines resemble those from a point charge.
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1/23/07184 Lecture 926 TWO POSITIVE CHARGES
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1/23/07184 Lecture 927 Calculating the Potential from the Field To calculate the electric potential from the electric field we start with the definition of the work dW done on a particle with charge q by a force F over a displacement ds In this case the force is provided by the electric field F = qE Integrating the work done by the electric force on the particle as it moves in the electric field from some initial point i to some final point f we obtain
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1/23/07184 Lecture 928 Calculating the Potential from the Field (2) Remembering the relation between the change in electric potential and the work done … …we find Taking the convention that the electric potential is zero at infinity we can express the electric potential in terms of the electric field as ( i = , f = x)
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1/23/07184 Lecture 929 Example - Charge moves in E field Given the uniform electric field E, find the potential difference V f -V i by moving a test charge q 0 along the path icf. Idea: Integrate E ds along the path connecting ic then cf. (Imagine that we move a test charge q 0 from i to c and then from c to f.)
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1/23/07184 Lecture 930 Example - Charge moves in E field distance = sqrt(2) d by Pythagoras
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1/23/07184 Lecture 931 Clicker Question We just derived V f -V i for the path i -> c -> f. What is V f -V i when going directly from i to f ? A: 0 B: -Ed C: +Ed D: -1/2 Ed Quick: V is independent of path. Explicit: V = - E. ds = E ds = - Ed
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