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Lesson 4-2 Example 4 4-2 Solve. MONEY Casey and Jerald each purchased a ticket to the movies at $6.45 each. They used a different combination of bills.

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Presentation on theme: "Lesson 4-2 Example 4 4-2 Solve. MONEY Casey and Jerald each purchased a ticket to the movies at $6.45 each. They used a different combination of bills."— Presentation transcript:

1 Lesson 4-2 Example 4 4-2 Solve. MONEY Casey and Jerald each purchased a ticket to the movies at $6.45 each. They used a different combination of bills and coins to pay. Represent $6.45 in two ways. Understand Read the problem. Write what you know. Each person paid a total of $6.45.

2 Lesson 4-2 Example 4 4-2 Plan Pick a strategy. One strategy is to use logical reasoning. First represent $6.45 using the fewest coins. Then find a combination using different coins and bills.

3 Lesson 4-2 Example 4 4-2 Solve The least number of bills that can make $6.45is one 5-dollar bill and one 1-dollar bill. What amount is left?45¢ a quarter Which coin represents the greatest amount? 25¢ + 10¢ = 35¢ 35¢ + 10¢ = 45¢ So, one combination for $6.45 is one 5-dollar bill, one 1-dollar bill, one quarter, two dimes.

4 Lesson 4-2 Example 4 4-2 SolveNow represent $6.45 using a different combination of bills and coins. $6 = six 1-dollar bills A second combination of bills and coins is six 1-dollar bills, four dimes, one nickel. 45¢ = 10¢ 20¢ 30¢ 40¢ 45¢ +10¢ +5¢ 45¢ = 10¢ 20¢ 30¢ 40¢45¢ = 10¢ 20¢ 30¢45¢ = 10¢ 20¢45¢ =45¢ = 10¢

5 Lesson 4-2 Example 4 4-2 Check Add each amount. The total of each amount should be $6.45.


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