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April 6, 2010 Unit 5 Unit 5. Why might Materials and Structures be important to engineers? Structural Optical Fluid Thermal Biotech Electrical Electronic.

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Presentation on theme: "April 6, 2010 Unit 5 Unit 5. Why might Materials and Structures be important to engineers? Structural Optical Fluid Thermal Biotech Electrical Electronic."— Presentation transcript:

1 April 6, 2010 Unit 5 Unit 5

2 Why might Materials and Structures be important to engineers? Structural Optical Fluid Thermal Biotech Electrical Electronic Mechanical Material

3 1.What material properties do we use to characterize materials? 2.How are those properties determined? 3.What are the parameters that affect materials in tension and compression? 4.What are the optimal sizes of tension and compression members to satisfy design requirements? 5.What forces do effective structures overcome? 6.What is a truss and what structural problems do they solve? 7.What sort of calculation goes into bridge design? Unit 5 will answer the following questions:

4 Let’s look at your Final Engineering Practicum Project:

5 Design and Construction of a Spaghetti Bridge

6 1)To take math and science out of the textbook and into a project involving design, planning, and construction. 2)Because the process is instructive and fun, and it exemplifies the difficulties of putting theory into practice. You can build a bridge (or anything, for that matter) without math and science. But – to carry a maximum load, you need to understand material properties, the theory of beams, and the physics of canceling forces (statics). Why a Bridge Project?

7 1)Cost 2)Spaghetti is very unforgiving. Design is much more important in a spaghetti bridge than a toothpick/balsa wood one. 3)Available in a nice form for construction – long cylindrical rods. Why Spaghetti? Why not toothpicks or Balsa Wood? Build a bridge out of spaghetti and epoxy that carries the most load suspended from the middle of the span. Project Goal:

8 Material Constraints: 1)Regular-diameter spaghetti. 2)5-minute epoxy. Physical Constraints: 1)Minimum length > 50cm 2)25cm maximum height 3)250g maximum weight 4)Only horizontal supports on ends 5)Minimum span width 5cm; maximum space between span members, 2mm Grading Criteria: 1)Minimum passing load is 7kg 2)Highest class load determines grading scale (maximum load = 100%) Design Criteria/Constraints:

9 ≥ 5cm ≤ 2mm Bridge Decking Load 50 cm ≤ 25 cm 5cm x 10cm Loading Platform ≤ 2.5cm Total Weight ≤ 250gms Criteria Schematic:

10

11 We’ll begin by answering the question, “Why Epoxy?” Why not white (Elmer’s) glue? 1.It’s water-based – what problem does this pose for spaghetti? Spaghetti is softened by the glue. 2.Glue joints take forever to dry. 3.Once dry, joints are not very strong. Why not model (airplane) glue? Dries quickly, but joints are slightly flexible. We want rigid joints. Why not hot glue? Joints are far too flexible Materials and their Properties

12 “Why Epoxy?” Why Epoxy? 1.It’s not water-based 2.Creates rigid joints 3.Can choose the drying time (5-, 10-, 30-minute Epoxy) What is Epoxy? A polymer formed by the chemical reaction of a “resin” and a “hardener” – two viscous liquids Problems with Epoxy: 1.Irreversible curing 2.Very messy 3.Must mix two equal portions 4.Possible endocrine disrupter and main cause of occupational asthma Materials and their Properties HIGHER LOWER

13 Atoms The story begins with atoms… Various combinations of the 115 or so elements make up all matter on Earth. How? Bonding: 1.Covalent 2.Ionic 3.Metallic 4.Hydrogen 5.Van der Waals forces Materials and their Properties

14 Structure Related to the arrangement of components 1.Any length scale – nanometer, micrometer, meter, etc. 2. Materials and their Properties Diamond Graphite C 60 - Fullerene Carbon nanotubes

15 Structure Related to the arrangement of components 1.Any length scale – nanometer, micrometer, meter, etc. 2. Materials and their Properties

16 Properties What is a Material Property? 1.A quantitative trait – tells us something about a material 2.They have units 3.May be constant 4.May be a function of independent variables (like temperature) Materials and their Properties

17 Properties Materials and their Properties

18 Properties What is a Material Property? 1.A quantitative trait – tells us something about a material 2.They have units 3.May be constant 4.May be a function of independent variables (like temperature) Different types of Properties: Mechanical OpticalManufacturing Electrical Acoustical Thermal Radiological Chemical Environmental Magnetic Atomic Mechanical Properties relate deformation to applied load Materials and their Properties

19 Mechanical Properties Young’s Modulus Tensile Strength Compressive Strength Yield Strength Shear Strength Ductility Poisson’s Ratio Specific Weight Specific Modulus Materials and their Properties

20 Mechanical Properties – Stress-Strain Curve Materials and their Properties Typical yield behavior for non-ferrous alloys. 1: True elastic limit 2: Proportionality limit 3: Elastic limit 4: Yield strength Young’s Modulus

21 Materials and their Properties Mechanical Properties – Stress-Strain Curve

22 Materials and their Properties Mechanical Properties – Stress-Strain Curve

23 Beams and loads--tension: Beam under tension Maximum load is tensile strength times cross-sectional area. L max = T * A cs For regular spaghetti (diameter = 2mm), maximum load is ~ 10 pounds. Load capacity does not depend on length. Failure occurs when ultimate tensile strength is exceeded.

24 Beams and loads--compression: Beam in compression Failure occurs two ways: 1) When L/d < 10, failure is by crushing 2) When L/d > 10, failure is by buckling We are almost always concerned with failure by buckling. L d

25 Beams and loads--compressive buckling: Buckling strength F = k * d 4 /L 2 To determine constant of proportionality k: 1) Measure length and diameter of a piece of spaghetti 2) Hold spaghetti vertically on postal scale 3) Press down on spaghetti until it begins to bend 4) Read load F on postal scale 5) Calculate k

26 Some consequences of buckling properties: If a beam of length L and diameter d can support a compressive load of F, L d F then a beam of length L/2 and diameter d can support a compressive load of 4F. L/2 d 4F

27 L 2d 16F then a beam of length L and diameter 2d can support a compressive load of 16F. L d F ALSO… If a beam of length L and diameter d can support a compressive load of F,

28 Bigger beams can be fabricated out of smaller beams, as in a truss. The fabricated beam will have the same buckling strength as a solid beam, provided the buckling/tension strengths of the component beams are not exceeded.

29 Beams and loads--bending: Very little strength. Never design a structure that relies on bending strength to support a load.

30 Beams and loads--bending:

31 Statics – the two conditions for static equilibrium are… 1) At each joint or node: 2) Triangles cancel out moments 3) Joints are assumed to carry no bending loads; therefore all forces are compression or tension and lie in the directions of the beams. x y -F F/2

32 Use Bridge Designer to calculate loads: http://www.jhu.edu/~virtlab/bridge/bridge.htm

33 Design and construction ideas: 1) Triangles are a construction engineer’s best friend, i.e. there are no bending moments in triangular elements. Good design Bad design – truss strength depends on bending strengths of members

34 Design and construction ideas (cont.): 2) Taller is better: note loads on these two structures.

35 Design and construction ideas (cont.): 3) Don’t forget about the 3rd dimension. A good design in the x-y plane, may be a terrible one in the z-direction. 4) Recall: tension members do not need to be fabricated as trusses. Their strength depends only on cross- sectional area. 5) Plan the total bridge design. Estimate the weight of each of the components so that you will not exceed the weight limit. 6) Make a full-size pattern of your bridge. Build the bridge on this pattern. This will ensure that all components will assemble properly.

36 7) If a number of strands of spaghetti are to be used together as a single member, do not glue their entire lengths. “Spot” glue them at intervals of about 1”. This will provide adequate strength without adding excessive weight. Design and construction ideas (cont.): 8) For economy of time, joints should be “overlaid” not “butted”. Butt joints require careful sizing. Overlaid joints do not. Excess material may be cut off after assembly. Butt jointsOverlaid joints

37 Which is the better design and why? a) b) a)b)

38 Which is the better design and why? a)b) a)b)


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