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Warm-Up How would you describe the roof at the right?
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Warm-Up slope Anything that isn’t completely vertical has a slope. This is a value used to describe its incline or decline.
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Warmer-Upper pitch The slope or pitch of a roof is quite a useful measurement. How do you think a contractor would measure the slope or pitch of a roof?
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Warmer-Upper The slope or pitch of a roof is defined as the number of vertical inches of rise for every 12 inches of horizontal run.
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Warmer-Upper The steeper the roof, the better it looks, and the longer it lasts. But the cost is higher because of the increase in the amount of building materials.
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3.4 Find and Use Slopes of Lines 3.5 Write and Graph Equations of Lines Objectives: 1.To find the slopes of lines 2.To find the slopes of parallel and perpendicular lines 3.To graph and write equations based on the Slope-Intercept Form, Standard Form, or Point-Slope Form of a Line
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Investigation 1 Click on the button and use the activity, to discover something about the actual value of the slope of a line. Then complete the table on the next slide.
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Slope Summary Summarize your findings about slope in the table below: m > 0m < 0m = 0m = undef Insert Picture Insert Picture Insert Picture Insert Picture As the absolute value of the slope of a line increases, --?--. the line gets steeper. Copy and complete in your notebook
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Slope of a Line The slope of a line (or segment) through P 1 and P 2 with coordinates (x 1,y 1 ) and (x 2,y 2 ) where x 1 x 2 is rise
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Example 2 Find the slope of the line containing the given points. Then describe the line as rising, falling, horizontal, or vertical. 1.(6, − 9) and ( − 3, − 9) 2.(8, 2) and (8, − 5) 3.(−1, 5) and (3, 3) 4.(−2, −2) and (−1, 5) 0horizontal undefined vertical -1/2falling 7rising
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Example 3 A line through points (5, -3) and ( − 4, y ) has a slope of − 1. Find the value of y.
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Investigation 2 Use the Geometer’s Sketchpad activity to complete the two following postulates, and then add them to your Because I Said So… Postulate page.
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Parallel and Perpendicular parallel lines Two lines are parallel lines iff they have the same slope. perpendicular lines Two lines are perpendicular lines iff their slopes are negative reciprocals.
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Example 4 Tell whether the pair of lines are parallel, perpendicular, or neither 1.Line 1: through ( − 2, 1) and (0, − 5) Line 2: through (0, 1) and ( − 3, 10) 2.Line 1: through ( − 2, 2) and (0, − 1) Line 2: through ( − 4, − 1) and (2, 3) -3 & -3 parallel -3/2 & 2/3 perpendicular
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Example 5 Line k passes through (0, 3) and (5, 2). Graph the line perpendicular to k that passes through point (1, 2). Find slope, use it’s negative reciprocal to find slope of new line, then use new slope to plot the 2 nd point of new line.
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Example 6 Find the value of y so that the line passing through the points (3, y ) and ( − 5, − 6) is perpendicular to the line that passes through the points ( − 2, − 7) and (10, 1). -18
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Example 7 Find the value of k so that the line through the points ( k – 3, k + 2) and (2, 1) is parallel to the line through the points ( − 1, 1) and (3, 9). K=2
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Tangent
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Tangent tangent A line is a tangent if and only if it intersects a circle in one point.
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Investigation 3 Use the Geometer’s Sketchpad activity to discover the relationship between a radius and a line tangent to a circle.
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Tangent Line Theorem In a plane, a line is tangent to a circle if and only if the line is perpendicular to a radius of the circle at its endpoint on the circle.
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Example 8 The center of a circle has coordinates (1, 2). The point (3, -1) lies on this circle. Find the slope of the tangent line at (3, -1).
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Intercepts x -intercept The x -intercept of a graph is where it intersects the x -axis. a( a, 0) y -intercept The y -intercept of a graph is where it intersects the y -axis. b(0, b )
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Investigation 4 Use the Geometer’s Sketchpad Activity “Equations of Lines” to complete the Slope-Intercept Form of a Line.
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Slope-Intercept Slope-Intercept Form of a Line: If the graph of a line has slope m and a y -intercept of (0, b ), then the equation of the line can be written in the form y = mx + b. Equation of a Horizontal Line Equation of a Vertical Line y = b (where b is the y -intercept) x = a (where a is the x -intercept)
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Example 9 Find the equation of the line with the set of solutions shown in the table. 1.Find slope 2.Plug in x, y and slope into y=mx+b 3.Solve for “b” 4.Write the equation using slope and y-intercept x 13579… y 511172329… 3 5=3(1) + b 2 y = 3x + 2
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Example 10 Graph the equation:
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Slope-Intercept To graph an equation in slope-intercept form: 1.Solve for y to put into slope-intercept form. 2.Plot the y -intercept (0, b ). 3.Use the slope m to plot a second point. 4.Connect the dots.
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Example 11 Graph the equation:
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Standard Form Standard Form of a Line The standard form of a linear equation is A x + B y = C, where A and B are not both zero. A, B, and C are usually integers.
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Standard Form To graph an equation in standard form: 1.Write equation in standard form. 2.Let x = 0 and solve for y. This is your y -intercept. 3.Let y = 0 and solve for x. This is your x -intercept. 4.Connect the dots.
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Example 12 Without your graphing calculator, graph each of the following: In your notebook 1. y = − x + 2 2. y = (2/5) x + 4 3. f ( x ) = 1 – 3 x 4. 8 y = −2 x + 20
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Example 13 Graph each of the following: In your notebook 1. x = 1 2. y = −4
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Example 14 A line has a slope of −3 and a y -intercept of (0, 5). Write the equation of the line. Y = -3x + 5
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Example 15 A line has a slope of ½ and contains the point (8, − 9). Write the equation of the line. HINT: Plug all value into slope-intercept form first y=1/2x -13
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Point-Slope Form Given the slope and a point on a line, you could easily find the equation using the slope-intercept form. Alternatively, you could use the point-slope form of a line. Point-Slope Form of a Line: A line through ( x 1, y 1 ) with slope m can be written in the form y – y 1 = m ( x – x 1 ).
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Example 16 Find the equation of the line that contains the points (−2, 5) and (1, 2). y=-x +3
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Example 17 Write the equation of the line shown in the graph. y= -1/3x + 1/2
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Example 18 Write an equation of the line that passes through the point (−2, 1) and is: 1.Parallel to the line y = −3 x + 1 2.Perpendicular to the line y = −3 x + 1 y=-3x - 5 y= 1/3x - 5
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Example 19 Find the equation of the perpendicular bisector of the segment with endpoints (-4, 3) and (8, -1). HINT: find midpoint, then use that point to find formula of new line y= -3x + 7
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Example 20 The center of a circle has coordinates (1, 2). The point (3, −1) lies on this circle. Find the equation of the tangent line at (3, −1).
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Assignment Give me 1.5 hours: P. 175-7: 1-14 all, 16, 19, 23, 26-28, 33, 42, 43 P. 184-6: 4-44 multiples of 4, 30, 33, 53-59, 67, 68 Challenge Problems
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