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EXAMPLE 3 Model with finite differences

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1 EXAMPLE 3 Model with finite differences The first seven triangular pyramidal numbers are shown below. Find a polynomial function that gives the nth triangular pyramidal number. SOLUTION Begin by finding the finite differences.

2 EXAMPLE 3 Model with finite differences Because the third-order differences are constant, you know that the numbers can be represented by a cubic function of the form f (n) = an3 + bn2 + cn + d. By substituting the first four triangular pyramidal numbers into the function, you obtain a system of four linear equations in four variables.

3 EXAMPLE 3 Model with finite differences a(1)3 + b(1)2 + c(1) + d = 1 a + b + c + d = 1 a(2)3 + b(2)2 + c(2) + d = 4 8a + 4b + 2c + d = 4 a(3)3 + b(3)2 + c(3) + d = 10 27a + 9b + 3c + d = 10 a(4)3 + b(4)2 + c(4) + d = 20 64a + 16b + 4c + d = 20 Write the linear system as a matrix equation AX = B. Enter the matrices A and B into a graphing calculator, and then calculate the solution X = A– 1 B.

4 Model with finite differences
EXAMPLE 3 Model with finite differences 1 8 27 64 4 9 16 2 3 a b c d A x = 1 4 10 20 B The solution is a = ,b = , c = , and d = 0. So, the nth triangular pyramidal number is given by f (n) = n n n. 1 6 2 3

5 Use finite differences to find a polynomial function
GUIDED PRACTICE for Example 3 Use finite differences to find a polynomial function that fits the data in the table. SOLUTION Write function values for equally-spaced n - values. First-order differences Second-order differences Third-order differences

6 GUIDED PRACTICE for Example 3 Because the third-order differences are constant, you know that the numbers can be represented by a cubic function of the form f (n) = an3 + bn2 + cn + d. By substituting the first four triangular pyramidal numbers into the function, you obtain a system of four linear equations in four variables. a(1)3 + b(1)2 + c(1) + d = 6 a + b + c + d = 6 a(2)3 + b(2)2 + c(2) + d = 15 8a + 4b + 2c + d = 15 a(3)3 + b(3)2 + c(3) + d = 22 27a + 9b + 3c + d = 22 a(4)3 + b(4)2 + c(4) + d = 1 64a + 16b + 4c + d = 21

7 GUIDED PRACTICE for Example 3 Write the linear system as a matrix equation AX = B. Enter the matrices A and B into a graphing calculator, and then calculate the solution X = A– 1 B. 1 8 27 64 4 9 16 2 3 a b c d = 6 15 22 21 The solution is a = 1, b = 5, c = 1, and d = 1. So, the nth triangular pyramidal number is given by f (x) = – x3 + 5x2 + x + 1.


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