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MAT 1234 Calculus I Section 3.1 Maximum and Minimum Values

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Presentation on theme: "MAT 1234 Calculus I Section 3.1 Maximum and Minimum Values"— Presentation transcript:

1 MAT 1234 Calculus I Section 3.1 Maximum and Minimum Values http://myhome.spu.edu/lauw

2 Next WebAssign 3.1 Quiz– 2.7, 2.9

3 1 Minute… You can learn all the important concepts in 1 minute.

4 1 Minute… High/low points – most of them are at points with horizontal tangent

5 1 Minute… High/low points – most of them are at points with horizontal tangent. Highest/lowest points – at points with horizontal tangent or endpoints

6 1 Minute… You can learn all the important concepts in 1 minute. We are going to develop the theory carefully so that it works for all the functions that we are interested in. There are a few definitions…

7 Preview Definitions absolute max/min local max/min critical number Theorems Extreme Value Theorem Fermat’s Theorem The Closed Interval Method

8 Max/Min We are interested in max/min values Minimize the production cost Maximize the profit Maximize the power output

9 Definition (Absolute Max) f has an absolute maximum at x=c on D if for all x in D (D =Domain of f) c D

10 Definition (Absolute Min) f has an absolute minimum at x=c on D if for all x in D (D =Domain of f) c D

11 Definition The absolute maximum and minimum values of f are called the extreme values of f.

12 x Example 1 y Absolute max. Absolute min.

13 Definition (Local Max/Min) f has an local maximum at x=c if for all x in some open interval containing c f has an local minimum at x=c if for all x in some open interval containing c

14 x Example 1 y Local max. Local min.

15 Q&A An end point is not a local max/min, why?

16 The Extreme Value Theorem If f is continuous on a closed interval [a,b], then f attains an absolute max value f(c) and an absolute min value f(d) at some numbers c and d in [a,b]. No guarantee of absolute max/min if one of the 2 conditions are missing.

17 The Extreme Value Theorem If f is continuous on a closed interval [a,b], then f attains an absolute max value f(c) and an absolute min value f(d) at some numbers c and d in [a,b]. No guarantee of absolute max/min if one of the 2 conditions are missing.

18 Q&A Give 2 examples of functions on an interval that do not have absolute max value.

19 Example 2 (No abs. max/min) f is not continuous on [a,b] x y b a y=f(x) c

20 Example 2 (No abs. max/min) The interval is not closed x y b a y=f(x)

21 How to find Absolute Max./Min.? The Extreme Value Theorem guarantee of absolute max/min if f is continuous on a closed interval [a,b]. Next: How to find them?

22 Fermat’s Theorem If f has a local maximum or minimum at c, and if exists, then c x y

23 Q&A: T or F The converse of the theorem: If, then f has a local maximum or minimum at c

24 Definition (Critical Number) A critical number of a function f is a number c in the domain of f such that either or does not exist.

25 Critical Number (Translation) Critical numbers give all the potential local max/min values

26 Critical Number (Translation) If the function is differentiable, critical points are those c such that

27 Example 3 Find the critical numbers of

28 Example 3 Find the critical numbers of

29 The Closed Interval Method Idea: the absolute max/min values of a continuous function f on a closed interval [a,b] only occur at 1. the local max/min (the critical numbers) 2. end points of the interval

30 The Closed Interval Method To find the absolute max/min values of a continuous function f on a closed interval [a,b]: 1. Find the values of f at the critical numbers of f in (a,b). 2. Find the values of f at the end points. 3. The largest of the values from steps 1 and 2 is the absolute maximum value; the smallest of the those values from is the absolute minimum value.

31 The Closed Interval Method To find the absolute max/min values of a continuous function f on a closed interval [a,b]: 1. Find the values of f at the critical numbers of f in (a,b). 2. Find the values of f at the end points. 3. The largest of the values from steps 1 and 2 is the absolute maximum value; the smallest of the those values from is the absolute minimum value.

32 The Closed Interval Method To find the absolute max/min values of a continuous function f on a closed interval [a,b]: 1. Find the values of f at the critical numbers of f in (a,b). 2. Find the values of f at the end points. 3. The largest of the values from steps 1 and 2 is the absolute maximum value; the smallest of the those values from is the absolute minimum value.

33 Example 4 Find the absolute max/min values of

34 Expectations: Formal Conclusion

35 Classwork Do part (a) only.


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