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Published byTimothy Warren Modified over 9 years ago
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DEdwards Square on Hypotenuse Square on Leg 1 Square on Leg 2 = +
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Sine Cosine Tangent
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Prove: . .
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Special Angles θ 0°0° 30 ° 45 ° 60 ° 90 ° Sin θ Cos θ Tan θ ?? ? ? ? ? ? ? ? ? ? ? ? ? ? DEdwards proof
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Sin 30 ° = Cos 30 ° = Tan 30 ° = Sin 60 ° = Cos 60 ° = Tan 60 ° = 2 2 2 60 ° 1 30 ° table
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Sin 45 ° = Cos 45 ° = Tan 45 ° = 1 1 45 ° table
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Trigonometric Graphs are PERIODIC i.e. they repeat themselves after a “cycle” is complete
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y-intercept = 0 x-intercepts = 0 °, ±180 °, ±360 °
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y-intercept = 1 x-intercepts = ±90 °, ±270 °
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Complementary Relationships Sin x = Cos ( 90 - x) Cos x = Sin ( 90 - x) Tan x =
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Supplementary Relationships Sin x = Sin ( 180 - x) Cos x = - Cos ( 180 - x) Tan x = - Tan ( 180 - x)
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The function has ASYMPTOTES at these points
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(0,1) THE UNIT CIRCLE Circle on the Cartesian plane with radius of 1 unit
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(0,1) THE UNIT CIRCLE
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(0,1) THE UNIT CIRCLE: 1 st Quadrant Theta θ : Angle between Terminal side & Initial side Reference Angle α : Acute Angle between Terminal Side & x-axis
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(0,1) THE UNIT CIRCLE: 2 nd Quadrant Theta, θ Reference Angle α
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(0,1) THE UNIT CIRCLE: 3 rd Quadrant Theta, θ Reference Angle α
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(0,1) THE UNIT CIRCLE: 4 th Quadrant Theta, θ Reference Angle α
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(0,1) THE UNIT CIRCLE Coordinates of points on the unit circle show (cos θ, sin θ) When the terminal side is drawn through that point
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(0,1) THE UNIT CIRCLE (cos θ, sin θ) x P(a, b) θ ° O X
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(0,1) THE UNIT CIRCLE Coordinates of points on the unit circle show (cos θ, sin θ) When the terminal side is drawn through that point x θ=90 ° cos90 °=0 sin90 ° =1 Hence point on circle is (0,1)
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(0,1) THE UNIT CIRCLE Coordinates of points on the unit circle show (cos θ, sin θ) When the terminal side is drawn through that point x θ=180 ° Cos180° = -1 Sin 180° = 0 Hence point on circle is (-1,0)
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(0,1) THE UNIT CIRCLE Coordinates of points on the unit circle show (cos θ, sin θ) When the terminal side is drawn through that point x θ=270 ° Cos 270° = 0 Sin 270° = -1 Hence point on circle is (0, -1) DEdwards
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(0,1) THE UNIT CIRCLE (cos θ, sin θ) x θ=30 ° Cos 30 °= 0.866=0.9 (1dp) sin30 ° = 0.5 Hence point on circle is (0.9, 0.5) (0.9, 0.5) θ=30 °
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(0,1) THE 1 st QUADRANT 0 <θ ≤ 90 For all points (x,y) x is positive & y is positive So, all points (cos θ,sin θ ) Cos θ :positive Sin θ : positive Tan θ = sin θ /cos θ=positive ll are Positive
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(0,1) THE 2 nd QUADRANT 90 ° <θ ≤ 180° For all points (x,y) x is negative & y is positive So, all points (cos θ,sin θ ) Cos θ :negative Sin θ : positive Tan θ = sin θ /cos θ=negative ll are Positive INE (only) is Positive
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(0,1) THE 3 rd QUADRANT 180 ° <θ ≤ 270° For all points (x,y) x is negative & y is negative So, all points (cos θ,sin θ ) Cos θ :negative Sin θ : negative Tan θ = sin θ /cos θ=positive ll are Positive INE (only) is Positive AN (only) is Positive
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(0,1) THE 4 th QUADRANT 270 ° <θ ≤ 360° For all points (x,y) x is positive & y is negative So, all points (cos θ,sin θ ) Cos θ :positive Sin θ : negative Tan θ = sin θ /cos θ=negative ll are Positive INE (only) is Positive AN (only) is Positive OS (only) is Positive
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(0,1) ll are Positive INE (only) is Positive AN (only) is Positive OS (only) is Positive
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“CAST” Relationships Sin x = Sin (180 - x) = -Sin (180 + x) = Sin ( 360 - x) Cos x = -Cos (180 - x) = -Cos (180+ x) = Cos (360 - x) Tan x = -Tan (180 - x) = Tan (180+ x) = -Tan(360 - x)
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