1. Isothermal Reactor Design – Part 2
Pressure Drop In Reactors

2. Design a PBR In case of 2nd order rxn, gas phase, isothermal
mole balance
rate laws
stoichiometry
combination
Need to relate pressure drop to catalyst weight (in order to determine conversion)

3. Design a PBR Ergun equation
= pressure (kPa) = inlet pressure (kPa) = temperature (K) = inlet temperature (K) = porosity = volume of void = void fraction = volume of solid total bed volume total bed volume = cross sectional area (m2) =diameter of particle in the bed, ft (m) =viscosity of gas passing through the bed, (kg/m.s) =length down the packed bed of pipe, ft (m) =superficial velocity = volumetric flow ÷ cross-sectional area of pipe (m/s) =gas density (kg/m3) = solid density (kg/m3) = inlet gas density = = superficial mass velocity, (kg/m2.s)

4. Design a PBR
For isothermal operation, we have two sets of equation with two unknowns, X & P
(1) (2)
Special case: if ε=0, an analytical solution to second equation is obtained as follows
Used only when ε=0

5. Design a PBR In case of 2nd order rxn, gas phase, isothermal
mole balance
rate laws
stoichiometry
Combination
Solve
By integration;
When ε=0

6. Design a PBR Solving for conversion gives:
Solving for catalyst weight,

7. For gas phase reactions, as the pressure drop increases, the concentration decreases, resulting in a decreased rate of reaction, hence a lower conversion when compared to a reactor without a pressure drop.
↑ W, ↓P, ↑ΔP
↑ ΔP, ↓P, ↓CA, ↓-rA
↑ W, ↓P, ↓CA
↑W, ↑X

8. Effect of pressure drop on the conversion profile
Consider a packed bed column with a second order reaction is taking place in 20 meters of a 1 ½ schedule 40 pipe packed with catalyst.
2A  B + C
The following data are given:
Inlet pressure, P0 = 10 atm=1013 kPa
Entering flowrate, v0 = 7.15 m3/h
Catalyst pellet size, Dp = m
Solid catalyst density: ρc = 1923 kg/m3
Cross sectional area of 1 ½ -in schedule 40 pipe: AC = m2
Pressure drop parameter, β0 = 25.8 kPa/m
Reactor length, L = 20 m
Void fraction = 45%
Calculate the conversion in the absence of pressure drop.
Calculate the conversion accounting for pressure drop.
What is conversion in part (b) if the catalyst particle diameter were doubled.
The entering concentration of A is 0.1 kmol/m3 and the specific reaction rate is .

9. Effect of pressure drop on the conversion profile
(a) Conversion for ΔP = 0
α = 0 thus,
[Volume of catalyst] x [catalyst density]

10. Effect of pressure drop on the conversion profile
(b) Conversion with pressure drop

11. Effect of pressure drop on the conversion profile
(c) Conversion when catalyst diameter were doubled. (increase by a factor of 2, ) From , thus
dominant

12. Effect of pressure drop on the conversion profile
(c) Conversion when catalyst diameter were doubled.
Thus,
Conversion increases from to by increasing catalyst diameter by a factor of 2.
Increasing particle size decrease the pressure drop parameter, increase conversion & reaction rate