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Homework π=π.ππππ π.ππ π=π.πππ π.ππ π=π.ππ π.ππ π=π.πππ π.π
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1. (7.3) What is Natural Base e?
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1. Answer Eulerβs Number:
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What is a common logarithm?
2. (7.4 d1) What is a common logarithm?
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A log with a base of 10. Written as log.
2 . Answer A log with a base of 10. Written as log.
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What is a natural logarithm?
3. (7.4 D1) What is a natural logarithm?
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A log with a base of e. Written as ln.
3 . Answer A log with a base of e. Written as ln.
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What is the formula for Compound Interest?
4. M (7.1 D3) What is the formula for Compound Interest?
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4 . Answer π¨=π·(π+ π π ) ππ A = amount after t years P = initial Principal (deposit) r = interest Rate t = time in years n = times per year
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What is the formula for Continuously Compounded Interest?
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5 . Answer π¨=π·π ππ
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What is the formula for the Product Property?
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6 . Answer πππ π ππ= πππ π π+ πππ π π
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What is the formula for the Quotient Property?
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7 . Answer πππ π π π = πππ π π β πππ π π
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What is the formula for the Power Property?
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8 . Answer πππ π π π =π πππ π π
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What is the formula for Change of Base?
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9 . Answer πππ π π= πππ π π πππ π π
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What is the Exponential Growth Model?
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10 . Answer π¨=π·(π+π) π
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What is the Exponential Decay Model?
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11 . Answer π¨=π·(πβπ) π
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12. How do you know if an exponential function is a growth or decay function?
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12 . Answer You look at b in the equation π=ππ π . If 0 <b < 1, it is a decay function. If b > 1, it is a growth function.
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13. Solve (7.3) You deposit $700 in an account that pays 3.5% annual interest compounded continuously. What is the balance after 2 years?
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13 . Answer π¨=π·π ππ π¨=ππππ π.πππ(π) A = $750.76
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How do you translate an exponential function when graphing?
14. Solve ( ) How do you translate an exponential function when graphing?
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π=ππ πβπ +π h = left & right (sign changes) k = up & down
14 . Answer π=ππ πβπ +π h = left & right (sign changes) k = up & down
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Simplify the expression πππ π ππ π .
19. solve (7.4 D2) Simplify the expression πππ π ππ π .
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πππ π ππ π πππ π π π π πππ π π cancels out 4x
15 . Answer πππ π ππ π πππ π π π π πππ π π cancels out 4x
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Rewrite the expression πππ π ππ=π.
16. Solve (7.4) Rewrite the expression πππ π ππ=π.
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16 . Answer π π =ππ
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Find the inverse function of π=π π +π.
17. Solve (7.4) Find the inverse function of π=π π +π.
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17 . Answer π=π π +π Swap x & y. π=π π +π X β 2 = π π πππ π π βπ = πππ π π π πππ π π cancels out y= πππ π π βπ
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Condense the expression: y = 2log x + 3log y β 5log z
18. Solve (7.5) Condense the expression: y = 2log x + 3log y β 5log z
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18 . Answer y = 2log x + 3log y β 5log z Power Property: π= πππ π π + πππ π π β πππ π π Product Property π=πππ π π π π βπππ π π Quotient Property πππ π π π π π π
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Solve the equation: πππ π π βπ = πππ π (ππ +π)
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19 . Answer πππ π π βπ = πππ π (ππ +π) Drop the πππ π x β 7 = 2x + 3 Subtract x from both sides. -7 = x + 3 Subtract 3 from both sides. -10 = x
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20. Solve (7.6) Solve the equation: π π =ππ
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20 . Answer π π =ππ πππ π π π = πππ π ππ πππ π π Cancels out. X = πππ π ππ Change of Base π= πππ ππ πππ π X = 2.07
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21. Solve (7.7) Write an exponential function in the form π¦=ππ π₯ that passes through the points (3, 1) and (5, 4).
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21 . Answer π¦=ππ π₯ , (3, 1) and (5, 4). π= ππ π π= π π π π= ππ π π= π π π π π π= π π 2 = b π= π π π a = 1/8 π= π π (π) π
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22. Solve (7.7) Write a power function in the form π¦=ππ π that passes through the points (2, 3) and (6, 12).
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22 . Answer π¦=ππ π , (2, 3) and (6, 12) π=ππ π π= π π π ππ=ππ π ππ= π π π ( π π ) 12 = 3( π π ) 4 = π π πππ π π= πππ π π π b = πππ π πππ π b = 1.26 π= π π π.ππ = 1.25 y = 1.25 π π.ππ
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bonus Write an exponential growth function of the form π¦=ππ π₯ββ +π whose graph has a y-intercept of 5 and an asymptote of 2.
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bonus Explain how you can determine if a power function is a good model for a set of data pairs.
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