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Given: Prove: x = 10 1. __________ 1. ___________ 2. __________ 2. ___________ 3. __________ 3. ___________ 4. __________ 4. ___________ StatementsReasons x = 10 Given Substitution Subtraction Multiplication
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Given: m 4 + m 6 = 180 Prove: m 5 = m 6 1. 2. 3. 4. 5. StatementsReasons Given Angle Add. Post. Substitution Reflexive m 4 = m 4 m 4 + m 5 = m 4 + m 6 m 4 + m 5 = 180 m 4 + m 6 = 180 m 5 = m 6 Subtraction
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Given: m 1 = m 3 m 2 = m 4 Prove: m ABC = m DEF 1. 2. 3. 4. StatementsReasons m 1 = m 3; m 2 = m 4 m ABC = m DEF m 1 + m 2 = m 3 + m 4 m 1 + m 2 = m ABC m 3 + m 4 = m DEF Given Addition Prop. Angle Add. Post. Substitution AB C 1 24 3 DE F
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Given: ST = RN; IT = RU Prove: SI = UN 1. ST = RN 1. 2. 3. SI + IT = RU + UN 3. 4. IT = RU 4. 5. Statements Reasons ST = SI + IT RN = RU + UN SI = UN Given Segment Add. Post. Substitution Given Subtraction Prop. S IT RUN
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Postulate – A statement accepted without proof. Theorem – A statement that can be proven using other definitions, properties, and postulates. In this class, we will prove many of the Theorems that we will use.
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If M is the midpoint of AB, then AM = ½AB and MB = ½AB. Hypothesis: M is the midpoint of AB Conclusion: AM = ½AB and MB = ½AB Write these pieces of the conditional statement as your “given” and “prove” information. Given: Prove:
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Definition of Midpoint: the point that divides a segment into two congruent segments. If M is the midpoint of AB, then AM MB. A B M Midpoint Theorem: If M is the midpoint of AB, then AM = ½AB and MB = ½AB. The theorem proves properties not given in the definition.
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Proof of the Midpoint Theorem Given: M is the midpoint of AB Prove: AM = ½AB; MB = ½AB 1.2.3.4.5.6. M is the midpoint of AB MB = ½AB AM = MB AM + MB = AB AM + AM = AB 2AM = AB AM = ½AB Given Def. of a Midpoint Segment Add. Post. Substitution Division Property Substitution AMB
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If BX is the bisector of ABC, then m ABX = ½m ABC and m XBC = ½m ABC. Prove: m ABX = ½m ABC and m XBC = ½m ABC. Given: BX is the bisector of ABC.
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A ray that divides an angle into two congruent adjacent angles. X Y ZW XWY YWZ If WY is the bisector of XWZ, then m XWY = ½m XWZ and m YWZ = ½m XWZ.
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Proof of the Bisector Thm Prove: m ABX = ½m ABC and m XBC = ½m ABC. Given: BX is the bisector of ABC. X B C A 1. BX is the bisector of ABC. 1. Given 2. m ABX = m XBC2. Def. of an angle bisector 3. m ABX + m XBC = m ABC3. Angle Addition Postulate 4. m ABX + m ABX = m ABC 2m ABX = m ABC 4. Substitution 5. m ABX = ½m ABC5. Division Property 6. m XBC = ½m ABC6. Substitution
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