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Landmark-Based Speech Recognition: Spectrogram Reading, Support Vector Machines, Dynamic Bayesian Networks, and Phonology Mark Hasegawa-Johnson jhasegaw@uiuc.edu University of Illinois at Urbana-Champaign, USA
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Lecture 2: Acoustics of Vowel and Glide Production One-Dimensional Linear Acoustics –The Acoustic Wave Equation –Transmission Lines –Standing Wave Patterns One-Tube Models –Schwa –Front cavity resonance of fricatives Two-Tube Models –The vowel /a/ –Helmholtz Resonator –The vowels /u,i,e/ Perturbation Theory –The vowels /u/, /o/ revisited –Glides
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1. One-Dimensional Acoustic Wave Equation and Solutions
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Acoustics: Constitutive Equations
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Acoustic Plane Waves: Time Domain
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Acoustic Plane Waves: Frequency Domain Tex
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Solution for a Tube with Constant Area and Hard Walls
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2. One-Tube Models
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Boundary Conditions L 0
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Resonant Frequencies
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Standing Wave Patterns
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Standing Wave Patterns: Quarter- Wave Resonators Tube Closed at the Left End, Open at the Right End
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Standing Wave Patterns: Half- Wave Resonators Tube Closed at Both Ends Tube Open at Both Ends
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Schwa and Invv (the vowels in “a tug”) F1=500Hz=c/4L F2=1500Hz=3c/4L F3=2500Hz=5c/4L
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Front Cavity Resonances of a Fricative /s/: Front Cavity Resonance = 4500Hz 4500Hz = c/4L if Front Cavity Length is L=1.9cm /sh/: Front Cavity Resonance = 2200Hz 2200Hz = c/4L if Front Cavity Length is L=4.0cm
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3. Two-Tube Models
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Conservation of Mass at the Juncture of Two Tubes A1A1 A 2 = A 1 /2 U 1 (x,t) U 2 (x,t)= 2U 1 (x,t) Total liters/second transmitted = (velocity) X (tube area)
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Two-Tube Model: Two Different Sets of Waves Incident Wave P1+ Reflected Wave P1-Incident Wave P2- Reflected Wave P2+
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Two-Tube Model: Solution in the Time Domain
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Two-Tube Model in the Frequency Domain
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Approximate Solution of the Two- Tube Model, A 1 >>A 2 Approximate solution: Assume that the two tubes are completely decoupled, so that the formants include - F(BACK CAVITY) = c/4 L BACK - F(FRONT CAVITY) = c/4L FRONT L BACK L FRONT
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The Vowels /AA/, /AH/ L BACK L FRONT L BACK =8.8cm F2= c/4L BACK = 1000Hz L FRONT =12.6cm F1= c/4L FRONT = 700Hz
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Acoustic Impedance Z( ,j ) 0 0
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Low-Frequency Approximations of Acoustic Impedance
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Helmholtz Resonator -Z 1 ( ,j ) = 0 Z 2 ( ,j ) 0
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The Vowel /i/ Back Cavity = Pharynx Resonances: 0Hz, 2000Hz, 4000Hz Front Cavity = Palatal Constriction Resonances: 0Hz, 2500Hz, 5000Hz Back Cavity Volume = 70cm 3 Front Cavity Length/Area = 7cm -1 1/2 √MC = 250Hz Helmholtz Resonance replaces all 0Hz partial-tube resonances. 250Hz 2000Hz 2500Hz
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The Vowel /u/: A Two-Tube Model Back Cavity = Mouth + Pharynx Resonances: 0Hz, 1000Hz, 2000Hz Front Cavity = Lips Resonances: 0Hz, 18000Hz, … Back Cavity Volume = 200cm 3 Front Cavity Length/Area = 2cm -1 1/2 √MC = 250Hz Helmholtz Resonance replaces all 0Hz partial-tube resonances. 250Hz 1000Hz 2000Hz
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The Vowel /u/: A Four-Tube Model Two Helmholtz Resonators = Two Low-Frequency Formants! F1 = 250Hz F2 = 500Hz F3 = Pharynx resonance, c/2L = 2000Hz 250Hz 500Hz 2000Hz Pharynx Velar Tongue Body Constriction Mouth Lips
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4. Perturbation Theory
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Perturbation Theory (Chiba and Kajiyama, The Vowel, 1940) A(x) is constant everywhere, except for one small perturbation. Method: 1. Compute formants of the “unperturbed” vocal tract. 2. Perturb the formant frequencies to match the area perturbation.
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Conservation of Energy Under Perturbation
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“Sensitivity” Functions
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Sensitivity Functions for the Quarter- Wave Resonator (Lips Open) L /AA//ER/ /IY//W/
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Sensitivity Functions for the Half- Wave Resonator (Lips Rounded) L /L,OW//UW/
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Formant Frequencies of Vowels From Peterson & Barney, 1952
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Summary Acoustic wave equation easiest to solve in frequency domain, for example: –Solve two boundary condition equations for P+ and P-, or –Solve the two-tube model (four equations in four unknowns) Quarter-Wave Resonator: Open at one end, Closed at the other –Schwa or Invv (“a tug”) –Front cavity resonance of a fricative or stop Half-Wave Resonator: Closed at the glottis, Nearly closed at the lips –/uw/ Two-Tube Models –Exact solution: use reflection coefficient –Approximate solution: decouple the tubes, solve separately Helmholtz Resonator –When the two-tube model seems to have resonances at 0Hz, use, instead, the Helmholtz Resonance frequency, computed with low-frequency approximations of acoustic impedance –/iy/: F1 is a Helmholtz Resonance –/uw/ and /ow/: Both F1 and F2 are Helmholtz Resonances Perturbation Theory –Perturbed area Perturbed formants –Sensitivity function explains most vowels and glides in one simple chart
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