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Object Recognizing
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Object Classes
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Individual Recognition
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Object parts Headlight Window Door knob Back wheel Mirror Front wheel Headlight Window Bumper
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ClassNon-class
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Unsupervised Training Data
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Features and Classifiers Same features with different classifiers Same classifier with different features
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Generic Features Simple (wavelets)Complex (Geons)
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Class-specific Features: Common Building Blocks
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Mutual information H(C) when F=1H(C) when F=0 I(C;F) = H(C) – H(C/F) F=1 F=0 H(C)
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Mutual Information I(C,F) Class:11010100 Feature:10011100 I(F,C) = H(C) – H(C|F)
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Optimal classification features Theoretically: maximizing delivered information minimizes classification error In practice: informative object components can be identified in training images
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Selecting Fragments
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Adding a New Fragment (max-min selection) ? MIΔ MI = MI [ Δ ; class ] - MI [ ; class ] Select: Max i Min k ΔMI (Fi, Fk) (Min. over existing fragments, Max. over the entire pool)
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Horse-class features Car-class features Pictorial features Learned from examples
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Star model Detected fragments ‘vote’ for the center location Find location with maximal vote In variations, a popular state-of-the art scheme
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Fragment-based Classification Fergus, Perona, Zisserman 2003 Agarwal, Roth 2002 Ullman, Sali 1999
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Variability of Airplanes Detected
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Recognition Features in the Brain
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Class-fragments and Activation Malach et al 2008
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EEG
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ERP MI 1 — MI 2 — MI 3 — MI 4 — MI 5 — Harel, Ullman,Epshtein, Bentin Vis Res 2007
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Bag of words
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Bag of visual words A large collection of image patches –
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Generate a dictionary using K-means clustering
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Each class has its words historgram – – – Limited or no Geometry Simple and popular, no longer state-of-the art.
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Classifiers
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SVM – linear separation in feature space
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Optimal Separation SVM Find a separating plane such that the closest points are as far as possible Advantages of SVM: Optimal separation Extensions to the non-separable case: Kernel SVM
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Separating line:w ∙ x + b = 0 Far line:w ∙ x + b = +1 Their distance:w ∙ ∆x = +1 Separation:|∆x| = 1/|w| Margin:2/|w| 0 +1 The Margin
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Max Margin Classification (Equivalently, usually used How to solve such constraint optimization? The examples are vectors x i The labels y i are +1 for class, -1 for non-class
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Using Lagrange multipliers: Using Lagrange multipliers: Minimize L P = With α i > 0 the Lagrange multipliers
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Minimizing the Lagrangian Minimize L p : Set all derivatives to 0: Also for the derivative w.r.t. α i Dual formulation: Maximize the Lagrangian w.r.t. the α i and the above two conditions.
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Solved in ‘dual’ formulation Maximize w.r.t α i : With the conditions: Put into L p W will drop out of the expression
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Dual formulation Mathematically equivalent formulation: Can maximize the Lagrangian with respect to the α i After manipulations – concise matrix form:
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SVM: in simple matrix form We first find the α. From this we can find:w, b, and the support vectors. The matrix H is a simple ‘data matrix’: H ij = y i y j Final classification: w∙x + b ∑α i y i + b Because w = ∑α i y i x i Only with support vectors are used
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DPM Felzenszwalb Felzenszwalb, McAllester, Ramanan CVPR 2008. A Discriminatively Trained, Multiscale, Deformable Part Model Many implementation details, will describe the main points.
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HoG descriptor
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HoG Descriptor Dallal, N & Triggs, B. Histograms of Oriented Gradients for Human Detection
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Using patches with HoG descriptors and classification by SVM Person model: HoG
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Object model using HoG A bicycle and its ‘root filter’ The root filter is a patch of HoG descriptor Image is partitioned into 8x8 pixel cells In each block we compute a histogram of gradient orientations
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The filter is searched on a pyramid of HoG descriptors, to deal with unknown scale Dealing with scale: multi-scale analysis
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A part Pi = (Fi, vi, si, ai, bi). Fi is filter for the i-th part, vi is the center for a box of possible positions for part i relative to the root position, si the size of this box ai and bi are two-dimensional vectors specifying coefficients of a quadratic function measuring a score for each possible placement of the i-th part. That is, a i and b i are two numbers each, and the penalty for deviation ∆x, ∆y from the expected location is a 1 ∆ x + a 2 ∆y + b 1 ∆x 2 + b 2 ∆y 2 Adding Parts
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Bicycle model: root, parts, spatial map Person model
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The full score of a potential match is: ∑ F i ∙ H i + ∑ a i1 x i + a i2 y i + b i1 x i 2 + b i2 y i 2 F i ∙ H i is the appearance part x i, y i, is the deviation of part p i from its expected location in the model. This is the spatial part. Match Score
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search with gradient descent over the placement. This includes also the levels in the hierarchy. Start with the root filter, find places of high score for it. For these high-scoring locations, each for the optimal placement of the parts at a level with twice the resolution as the root-filter, using GD. Final decision β∙ψ > θ implies class Recognition Essentially maximize ∑ Fi Hi + ∑ ai1 xi + ai2 y + bi1x2 + bi2y2 Over placements (xi yi)
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‘Pascal Challenge’ Airplanes Obtaining human-level performance?
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All images contain at least 1 bike
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Bike Recognition
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