Presentation is loading. Please wait.

Presentation is loading. Please wait.

1 Press Ctrl-A ©G Dear 2010 – Not to be sold/Free to use Area and Perimeter of Irregular Blocks Stage 6 - Year 11 Applied Mathematic (Preliminary General.

Similar presentations


Presentation on theme: "1 Press Ctrl-A ©G Dear 2010 – Not to be sold/Free to use Area and Perimeter of Irregular Blocks Stage 6 - Year 11 Applied Mathematic (Preliminary General."— Presentation transcript:

1 1 Press Ctrl-A ©G Dear 2010 – Not to be sold/Free to use Area and Perimeter of Irregular Blocks Stage 6 - Year 11 Applied Mathematic (Preliminary General 1)

2 2 If you are doing building, landscaping or some other activity you may need to find the perimeter or area of an irregular block of land. Regular Irregular End of Slide

3 3 Surveyor’s Notebook. This is a diagrammatic representation. Transverse Irregular block of land. 0 10m 12m 20m 25m 10m 10 35 50 1220 5m 20m 45 25 20 Surveyors Notebook. End of Slide

4 4 0.5x20x5 0.5x10x12 Rectangle T1 = = 60 T2 = 0.5x10x20 = 100 T3 = = 50 T4 = 0.5x15x25 = 187.5 TR = 0.5x25x(25+12) = 465.5 RE = 20x35 = 700 Area Trap =0.5xhx(a+b) Finding the Area 10m 12m 20m 25m 10m 5m 20m End of Slide Triangle 1 T1 Triangle 2 T2 Triangle 3 T3 Triangle 4 T4 Trapezium TR RE Area Triangle =0.5xbxhArea Rectangle = LxB Total Area =1563m 2

5 5 Finding the Perimeter 10m 12m 20m 25m 10m 5m 20m End of Slide T1 T2 T3 T4 TR RE T1: c 1 2 = 10 2 +12 2 =244 c 1 ≈15.6 T2: c 2 2 =10 2 +20 2 =500 c 2 ≈22.4 T3: c 3 2 = 5 2 +20 2 =425 c 3 ≈20.6 T4: c 4 2 =15 2 +25 2 =850 c 4 ≈29.2 TR: c T 2 =13 2 +25 2 =794 c 4 ≈28.2 13m RE: c R 2 =35 c 4 ≈35 Total = 151 m c 2 = a 2 + b 2

6 6 Finding the Area House Press

7 7 Finding the AreaWe want to concrete the driveway. If the concrete is 30cm thick then how much concrete do we need? End of Slide

8 8 Finding the AreaDraw the line shown below. Divide in half,and half again. End of Slide Simpson’s Rule: A ≈ h÷3(d first +4d middle +d last ) h=6m d f =0m d m =3m d L =2.5m

9 9 End of Slide Simpson’s Rule: A ≈ h÷3(d first +4d middle +d last ) h=6m d f =0m d m =3m d L =2.5m A ≈ 6÷3 x (0 + 4x3 + 2.5) h=6m d F =2.5m d m =2.8m d L =0m + 6÷3 x (2.5 + 4x2.8 + 0)≈ 56.4 m 2 V ≈ 56.4 m 2 x.3 m ≈ 16.92 m 3 ≈ 17 m 3


Download ppt "1 Press Ctrl-A ©G Dear 2010 – Not to be sold/Free to use Area and Perimeter of Irregular Blocks Stage 6 - Year 11 Applied Mathematic (Preliminary General."

Similar presentations


Ads by Google