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WARM-UP: Find the missing measurement in each triangle. 1. 2. 3. 4. 6 10 x 60 ° 10 x 54 ° 10 x x°x° 6 x = 8 x = 17.0 x = 59 °

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Presentation on theme: "WARM-UP: Find the missing measurement in each triangle. 1. 2. 3. 4. 6 10 x 60 ° 10 x 54 ° 10 x x°x° 6 x = 8 x = 17.0 x = 59 °"— Presentation transcript:

1 WARM-UP: Find the missing measurement in each triangle. 1. 2. 3. 4. 6 10 x 60 ° 10 x 54 ° 10 x x°x° 6 x = 8 x = 17.0 x = 59 °

2 CHANGE IN HW POLICY No work = no credit (unless vocab or problems where work not needed) Any homework turned in on test day is worth half credit

3 LESSON 10-1 I can find perimeters and areas of triangles and parallelograms I can find perimeters and areas of triangles and parallelograms on the coordinate plane

4 A = 1 2 bh A = bh b h b h Sum of all the sides

5 A = 1 2 bh A = 1 2 (24)(28) A = 336 m 2

6 A = 1 2 (33)(20) = 330 A = 1 2 (21)(16) = 168 Total = 330 + 168= 498 un 2

7 = 672 un 2

8 A = 1 2 bh 1 2 (b)(8) 72 = 72 = 4b 18 in = b

9 15 m 9 m 12 m A = 1 2 (12)(9) = 54 m 2

10 WARM-UP: Find the area of each triangle. 1. 2. 3. 4. 6 10 8 60 ° 10 8.66 54 ° 10 17 59 ° 10 6 24 21.65 68.75 30 5 13.75

11 WARM-UP: Find the exact area of each triangle. 1. 2. 20 30 ° 20 45 ° A = 1 2 bh = 1 2 = 100 un 2 A = 1 2 bh = 1 2 =

12 A = bh A = 30(18) A = 540 m 2

13 A = bh A = 18(16) A = 288 ft 2

14 h 60° 24 h 60° sin 60 = h 24 h = 20.78 20.78 A = bh A = 24(20.78) A = 498.72 in 2

15 32 22 P = 32 + 22 + 32 + 22 = 108 in h cos 30 = h 22 h = 19.05 A = 32(19.05) = 609.6 in 2

16 6 3 A = bh A = 6(3) A = 18 un 2

17 b h = 20 un 2

18 10-1 worksheet ASSIGNMENT

19 WARM-UP: Find the area of each figure. 1. 2. 20 5 25 16 12 8 A = 360 un 2 A = 82 un 2

20 LESSON 10-2 I can find perimeters and areas of kites, trapezoids and rhombi I can determine whether points on a coordinate plane define a kite, trapezoid or rhombus

21 A = 1 / 2 h(b 1 +b 2 ) h b1b1 b2b2 A = 1 / 2 d 1 d 2 d1d1 d2d2

22 A = 1 / 2 h(b 1 +b 2 ) A = ½(309)(205+511) h b1b1 A = 110,622 mi 2 b2b2

23 A = 1 / 2 h(b 1 +b 2 ) A = 1 / 2 (15)(40+18) A = 1 / 2 (15)(58) A = 435 m 2

24 M N P R A = 1 2 d1d2d1d2 = 1 2 = 1 2 = 15 un 2

25 or 20.4 un 2

26 b2b2 12 in 6 in A = 1 / 2 h(b 1 +b 2 ) 144 = 1 / 2 12(6+b 2 ) 144 = 6(6+b 2 ) 6 6 24 = 6+b 2 -6 -6 18 in = b 2

27 A = 1 / 22432 A = 384 m 2 20 12 16 d 1 = 24 d 2 = 32

28 A = 1 / 2 7 6 A = 21 un 2 P = 18.8 un

29

30 10-2 worksheet ASSIGNMENT

31 WARM-UP x° Find x in each figure. (Assume all angles in each figure are congruent. 1. 2. x° 3. 4. x° 90° 72° 60°

32 LESSON 10-3 I can find areas of regular polygons

33 A = 1 2 Pa a P = perimeter

34 12 6 a 36° tan 36 = 6 a a = 8.26 a A = 1 2 Pa = 1 2 (60)(8.26) = 247.8 cm 2

35 12 6 a 30° tan 30 = 6 a a = 10.39 a A = 1 2 Pa = 1 2 (72)(10.39) = 374.04 un 2

36 7 h 14 h = 12.12 h A = 1 2 bh = 1 2 (14)(12.12) = 84.84 m 2

37 8.08 x 30° tan 30 = x 7 x = 4.04 7 A = 1 2 Pa = 1 2 (48.48)(7) = 169.68 un 2

38 10-3 worksheet ASSIGNMENT

39 LESSON 10-4 I can find the area of circles I can find the area of a sector of a circle

40 A = π r 2

41 20Square – circle bh – π r 2 40(40) – π (20) 2 1600 – 1256.64 = 343.36 m 2

42 Circle – Square – bh π r 2 24 π (12) 2 452.39– 288 = 164.39 m 2

43 8 4 Big circle – 2( small circles) π (8) 2 – 2 π (4) 2 201.06– 100.53 = 100.53 m 2

44 pair of radii arc area of the circle A = θ 360 π r 2

45 A = θ 360 π r 2 A = 80 360 π (9) 2 = 56.55 in 2

46 A = 40 360 π (12) 2 = 50.27 cm 2

47 Sector – triangle 15 90 360 π (15) 2 – 1 2 (15)(15) 176.71– 112.5 = 64.21 un 2

48 Sector + triangle 8 8 270 360 π (8) 2 + 1 2 (8)(8) 150.80+ 32 = 182.80 un 2

49 10-4 worksheet Quiz tomorrow! ASSIGNMENT

50 WARM-UP: Find the area of each figure. 1. 2. 20 5 25 16 12 8 A = 360 un 2 A = 82 un 2

51 LESSON 10-5 I can find the area of circles I can find the area of a sector of a circle

52

53 34(15) = 510 Half circle 7.5 (0.5) π (7.5) 2 = 88.36 Total = 598.36 ft 2

54 22(22) = 484 20 22(20) 2 = 220 Total = 704 cm 2

55 7(4) 2 = 14 7(2) 2 = 7 Total = 21 un 2

56 Total = 40 un 2

57 Big rectangle – small rectangle 32(16) 512 – 12(5) – 60 = 452 cm 2

58 3(3) = 9 12(2) = 24 6 6(3) = 18 Total = 9 + 18 + 24 = 51 ft 2

59 10-5 worksheet ASSIGNMENT

60 LESSON 10-6 I can use similarity and proportions to find perimeters and areas of similar figures

61 shape size a:ba 2 :b 2

62 a:b 9:6 9 2 : 6 2 81:36 81 36 60 x = 81x = 2160 x = 26.67 in 2

63 a:b 12:18 12 2 : 18 2 144:324 144 324 x 90 = 324x = 12960 x = 40 cm 2

64 50 cm 2 98 cm 2 a 2 :b 2 50:98 a:b

65 2.5 2 (13) = 81.25 bushels

66 a 2 :b 2 1875:135 a:b

67 3232 5252 $2.50 x = 9x = $62.50 x = $6.94 Price is determined by in 2 (area)

68 10-6 worksheet ASSIGNMENT

69

70

71

72 WHAT’S THE AREA? Work with your group to come up with some strategies Decide on one strategy that everyone thinks will work Use any or all of the provided tools Calculate the area using your chosen tools and strategy!

73

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