Presentation is loading. Please wait.

Presentation is loading. Please wait.

Do Now How many mL of pure water must be added to 67 mL of a 35% saline solution to result in a solution that is 22% saline? [Round your answer to the.

Similar presentations


Presentation on theme: "Do Now How many mL of pure water must be added to 67 mL of a 35% saline solution to result in a solution that is 22% saline? [Round your answer to the."— Presentation transcript:

1 Do Now How many mL of pure water must be added to 67 mL of a 35% saline solution to result in a solution that is 22% saline? [Round your answer to the nearest hundedth of a mL.]

2 Do Now Let x = the # of mL of pure water that must be added. NOTE: Pure water has 0% salt.

3 Do Now Let x = the # of mL of pure water that must be added. Answer: 39.59 mL of pure water must be added to the original mixture.

4 Minilesson: Where:

5 Minilesson (cont’d): Unit Price X Total Price = # of units Red Fescue Total Combined Blueseed 0.85r r 0.85 (63 —r) 63 0.90 1.20(63 —r) 56.70 1.20 Let r = Pounds of Red seed 63 — r = lbs Blueseed Handout Q 1, first page This column provides the equation to solve

6 Minilesson (cont’d): Let r = Pounds of Red seed 63 — r = lbs Blueseed Answer: 54 lbs if red fescue 9 lbs of blue seed.

7 Minilesson (cont’d): Let r = Pounds of Red seed 63 — r = lbs Blueseed YOU MUST CHECK YOUR WORK!!

8 Minilesson (cont’d): Unit Price X Total Price = # of units 62 ¢ candy Total Combined 18.60 30 0.62 x (30 + x) 0.70 0.82x 0.70(30 + x) 0.82 Let x = pounds of 82 ¢ candy Handout Q 5, first page 82 ¢ candy This column provides the equation to solve

9 Minilesson (cont’d): Let x = pounds of 82 ¢ candy Answer: 20 lbs of the 82-cent candy.

10 Minilesson (cont’d): YOU MUST CHECK YOUR WORK!!

11 Minilesson (cont’d):

12 Minilesson: Solution problems concern the concentration of a certain substance within H 2 O. The substance as a % of the solution You see this especially at the pharmacy when you need to buy hydrocortisone, rubbing alcohol, hydrogen peroxide, etc. The packaging tells you the percent of concentration of the active ingredient. The amt of solution The amt of substance IN the solution × =

13 Minilesson (cont’d): + = 25% Salt15% Salt19.4% Salt

14 Guided Practice Handout, Side 1, qq. 1, 5 Handout, Side 2, qq. 19, 23

15 Independent Practice Handout, Side 1, qq. 2, 9 Handout, Side 2, qq. 20, 24

16 Our Textbook, p. 324, qq. 9--14 Answers on next page

17 Our Textbook, p. 324, ANSWERS 9) 25 L 10) 30 mL 11) 3 g 12) 15 kg of the $5; 25 kg of the $5.80 13) 8 kg dried apples; 12 kg dried apricots 14) 80 ₵ per Liter


Download ppt "Do Now How many mL of pure water must be added to 67 mL of a 35% saline solution to result in a solution that is 22% saline? [Round your answer to the."

Similar presentations


Ads by Google