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Clicker Questions Chapter 4

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Presentation on theme: "Clicker Questions Chapter 4"— Presentation transcript:

1 Clicker Questions Chapter 4
Barbara Mowery York College

2 A homogeneous mixture of two or more components is referred to as
a solute. a solution. an electrolyte. a mess. Answer: b

3 A homogeneous mixture of two or more components is referred to as
a solute. a solution. an electrolyte. a mess. Answer: b

4 The solvent in a sample of soda pop is
sugar. carbon dioxide. water. air. Answer: c

5 The solvent in a sample of soda pop is
sugar. carbon dioxide. water. air. Answer: c

6 The gaseous solute in a sample of soda pop is
sugar. carbon dioxide. water. air. Answer: b

7 The gaseous solute in a sample of soda pop is
sugar. carbon dioxide. water. air. Answer: b

8 water. sugar. air. electrolytes.
Gatorade® and other sports drinks conduct electricity because they contain water. sugar. air. electrolytes. Answer: d

9 water. sugar. air. electrolytes.
Gatorade® and other sports drinks conduct electricity because they contain water. sugar. air. electrolytes. Answer: d

10 When Fe(NO3)2 dissolves in water, the particles in solution are
Fe+ and (NO3)2–. Fe2+ and 2 NO3–. Fe and 2 NO3. Fe and N2 and 3 O2. Answer: b

11 When Fe(NO3)2 dissolves in water, the particles in solution are
Fe+ and (NO3)2–. Fe2+ and 2 NO3–. Fe and 2 NO3. Fe and N2 and 3 O2. Answer: b

12 Which set includes only substances that produce electrolytes in water?
NaBr, KCl, MgSO4 C6H12O6, CH3OH, C6H6 HCl, NH3, Cl2, N2 SiO2, CaCO3, H2SO4 Answer: a

13 Which set includes only substances that produce electrolytes in water?
NaBr, KCl, MgSO4 C6H12O6, CH3OH, C6H6 HCl, NH3, Cl2, N2 SiO2, CaCO3, H2SO4 Answer: a

14 Which compound below is not soluble in water?
NaBr KNO3 MgSO4 ZnS Answer: d

15 Which compound below is not soluble in water?
NaBr KNO3 MgSO4 ZnS Answer: d

16 Pb(NO3)2 + 2 KI  PbI2 + 2 KNO3 The physical evidence that the above reaction occurs is
an explosion. the formation of a gas. that the solution boils. the formation of a precipitate. Answer: d

17 Pb(NO3)2 + 2 KI  PbI2 + 2 KNO3 The physical evidence that the above reaction occurs is
an explosion. the formation of a gas. that the solution boils. the formation of a precipitate. Answer: d

18 H2SO4 and NaOH HNO3 and CaCl2 Ba(NO3)2 and Na3PO4 LiCl and SrI2
Which pair of compounds will produce a precipitate if solutions of appropriate concentrations are mixed together? H2SO4 and NaOH HNO3 and CaCl2 Ba(NO3)2 and Na3PO4 LiCl and SrI2 Answer: c

19 H2SO4 and NaOH HNO3 and CaCl2 Ba(NO3)2 and Na3PO4 LiCl and SrI2
Which pair of compounds will produce a precipitate if solutions of appropriate concentrations are mixed together? H2SO4 and NaOH HNO3 and CaCl2 Ba(NO3)2 and Na3PO4 LiCl and SrI2 Answer: c

20 When an acid reacts with a base, the result is
cancellation. elimination. neutralization. adduct formation. Answer: c

21 When an acid reacts with a base, the result is
cancellation. elimination. neutralization. adduct formation. Answer: c

22 K+ and NO3–. H+ and OH–. H+ and NO3–. K+ and OH–.
When nitric acid is neutralized by potassium hydroxide, the spectator ions are K+ and NO3–. H+ and OH–. H+ and NO3–. K+ and OH–. Answer: a

23 K+ and NO3–. H+ and OH–. H+ and NO3–. K+ and OH–.
When nitric acid is neutralized by potassium hydroxide, the spectator ions are K+ and NO3–. H+ and OH–. H+ and NO3–. K+ and OH–. Answer: a

24 Which compound below is not a strong acid?
HC2H3O2 H2SO4 HNO3 HBr Answer: a

25 Which compound below is not a strong acid?
HC2H3O2 H2SO4 HNO3 HBr Answer: a

26 When an atom undergoes oxidation, it ______ electrons.
gains loses retains balances Answer: b

27 When an atom undergoes oxidation, it ______ electrons.
gains loses retains balances Answer: b

28 When an atom undergoes reduction, it ______ electrons.
gains loses retains balances Answer: a

29 When an atom undergoes reduction, it ______ electrons.
gains loses retains balances Answer: a

30 reduced; gains reduced; loses oxidized; gains oxidized; loses
When Zn(s) reacts with HCl(aq) to produce H2(g) and ZnCl2(aq), the zinc is _____ because it _____ electrons. reduced; gains reduced; loses oxidized; gains oxidized; loses Answer: d

31 reduced; gains reduced; loses oxidized; gains oxidized; loses
When Zn(s) reacts with HCl(aq) to produce H2(g) and ZnCl2(aq), the zinc is _____ because it _____ electrons. reduced; gains reduced; loses oxidized; gains oxidized; loses Answer: d

32 Al + H+  Al3+ + H2 When the oxidation–reduction reaction above is correctly balanced, the coefficients are 1, 2  1, 1. 1, 3  1, 2. 2, 3  2, 3. 2, 6  2, 3. Answer: d

33 Al + H+  Al3+ + H2 When the oxidation–reduction reaction above is correctly balanced, the coefficients are 1, 2  1, 1. 1, 3  1, 2. 2, 3  2, 3. 2, 6  2, 3. Answer: d

34 In the list shown, the metal that is most easily oxidized is ___.
Ca Fe Cu Answer: a

35 In the list shown, the metal that is most easily oxidized is ___.
Ca Fe Cu Answer: a

36 A solution is prepared by dissolving 35
A solution is prepared by dissolving 35.0 g of NaCl in water to make 500 mL of solution. What is the molarity? 7.00 M 3.04 M 1.97 M 1.20 M Answer: d

37 A solution is prepared by dissolving 35
A solution is prepared by dissolving 35.0 g of NaCl in water to make 500 mL of solution. What is the molarity? 7.00 M 3.04 M 1.97 M 1.20 M Answer: d

38 250.0 mL of 0.100 M AgNO3 solution contains _____ g of silver nitrate.
4.25 8.50 17.0 34.0 Answer: a

39 250.0 mL of 0.100 M AgNO3 solution contains _____ g of silver nitrate.
4.25 8.50 17.0 34.0 Answer: a

40 To make 250. 0 mL of 0. 500 M KI solution, _____ mL of 6
To make mL of M KI solution, _____ mL of M KI must be used. 20.8 41.7 500.0 3000.0 Answer: a

41 To make 250. 0 mL of 0. 500 M KI solution, _____ mL of 6
To make mL of M KI solution, _____ mL of M KI must be used. 20.8 41.7 500.0 3000.0 Answer: a

42 HCl + KOH  KCl + H2O 25. 00 mL of HCl was titrated using 18
HCl + KOH  KCl + H2O mL of HCl was titrated using mL of M NaOH. The concentration of HCl is M. M. M. M. Answer: b

43 HCl + KOH  KCl + H2O 25. 00 mL of HCl was titrated using 18
HCl + KOH  KCl + H2O mL of HCl was titrated using mL of M NaOH. The concentration of HCl is M. M. M. M. Answer: b

44 HX + NaOH  NaX + H2O 229 mg of HX was titrated using 29. 33 mL of 0
HX + NaOH  NaX + H2O 229 mg of HX was titrated using mL of M NaOH. What is element X? F Cl Br I Answer: c

45 HX + NaOH  NaX + H2O 229 mg of HX was titrated using 29. 33 mL of 0
HX + NaOH  NaX + H2O 229 mg of HX was titrated using mL of M NaOH. What is element X? F Cl Br I Answer: c


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