1. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 1 Chapter 5 Compounds and Their Bonds 5.3 Naming and Writing Ionic Formulas

2. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 2 Charges of Representative Elements

3. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 3 Names of Some Common Ions

4. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 4 Give the names of the following ions: Ba 2+ Al 3+ K + _________ __________ _________ N 3  O 2  F  _________ __________ _________ P 3  S 2  Cl  _________ __________ _________ Learning Check

5. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 5 Ba 2+ Al 3+ K + barium aluminum potassium N 3  O 2  F  nitride oxide fluoride P 3  S 2  Cl  phosphide sulfide chloride Solution

6. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 6 Naming Ionic Compounds with Two Elements To name a compound with two elements,  identify the cation and anion  name the cation first, followed by the name of the anion

7. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 7 Formula IonsName Cation Anion NaClNa + Cl – sodium chloride K 2 SK + S 2– potassium sulfide MgOMg 2+ O 2– magnesium oxide CaI 2 Ca 2+ I – calcium iodide Al 2 O 3 Al 3+ S 2– aluminum sulfide Examples of Ionic Compounds with Two Elements

8. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 8 Write the names of the following compounds: 1) CaO___________ 2) KBr___________ 3) Al 2 O 3 ___________ 4) MgCl 2 ___________ Learning Check

9. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 9 Write the names of the following compounds: 1) CaOcalcium oxide 2) KBrpotassium bromide 3) Al 2 O 3 aluminum oxide 4) MgCl 2 magnesium chloride Solution

10. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 10 Learning Check Write the formulas and names for compounds of the following ions: Br – S 2− N 3− Na + Al 3+

11. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 11 Solution Br − S 2− N 3− Na + Al 3+ NaBr sodium bromide Na 2 S sodium sulfide Na 3 N sodium nitride AlBr 3 aluminum bromide Al 2 S 3 aluminum sulfide AlN aluminum nitride

12. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 12 Transition Metals Form Positive Ions Most transition metals and Group 4(14) metals,  Form 2 or more positive ions  Zn 2+, Ag +, and Cd 2+ form only one ion.

13. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. Metals with Variable Charge The names of transition metals with two or more positive ions (cations) use a Roman numeral after the name of the metal to identify ionic charge. 13

14. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 14 Naming Ionic Compounds with Variable Charge Metals

15. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 15 Examples of Names of Compounds with Variable Charge Metals

16. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. Guide to Naming Ionic Compounds with Variable Charge Metals 16

17. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 17 Naming FeCl 2 STEP 1 Determine the charge of the cation from the anion. Fe ion + 2 Cl – = Fe ion + 2– = 0 Fe ion = 2+ = Fe 2+ STEP 2 Name the cation by the element name, and use a Roman numeral to show its charge. Fe 2+ = iron(II) STEP 3 Write the anion with an ide ending. chloride STEP 4 Name the cation first, then the anion. iron(II) chloride

18. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 18 Naming Cr 2 O 3 STEP 1 Determine the charge of cation from the anion. 2Cr ions + 3O 2– = 2Cr ions + 3(2–) = 2Cr ions + 6– = 0 2Cr ions = 6+ Cr ion = 3+ = Cr 3+ STEP 2 Name the cation by the element name, and use a Roman numeral to show its charge. Cr 3+ = chromium(III) STEP 3 Write the anion with an ide ending. oxide STEP 4 Name the cation first, then the anion. chromium (III) oxide

19. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 19 Learning Check Select the correct name for each. A. Fe 2 S 3 1) iron sulfide 2) iron(II) sulfide 3) iron(III) sulfide B. CuO 1) copper oxide 2) copper(I) oxide 3) copper(II) oxide

20. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 20 Solution Select the correct name for each. A. Fe 2 S 3 3) iron(III) sulfide Fe 3+ S 2– B. CuO 3) copper(II) oxide Cu 2+ O 2–

21. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 21 Guide to Writing Formulas from the Name

22. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 22 Writing Formulas Write a formula for potassium sulfide. STEP 1 Identify the cation and anion. potassium= K + sulfide = S 2− STEP 2 Balance the charges. K + S 2− K + 2(1+) + 1(2–) = 0 STEP 3 Write the cation first. 2K + and 1S 2− = K 2 S 1 = K 2 S

23. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 23 Writing Formulas Write a formula for iron(III) chloride. STEP 1 Identify the cation and anion. iron (III) = Fe 3+ (III = charge of 3+) chloride = Cl − STEP 2 Balance the charges. Fe 3+ Cl − Cl − 1(3+) + 3(1–) = 0 STEP 3 Write the cation first. 1Fe 3+ and 3Cl − = FeCl 3

24. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 24 Learning Check The correct formula for each of the following is: A. copper(I) nitride 1) CuN2) CuN 3 3) Cu 3 N B. lead(IV) oxide 1) PbO 2 2) PbO 3) Pb 2 O 4

25. General, Organic, and Biological Chemistry Copyright © 2010 Pearson Education, Inc. 25 Solution The correct formula for each of the following is: A. copper(I) nitride 3) Cu 3 N3Cu + + N 3– = 3(1+) + (3–) = 0 B. lead(IV) oxide 1) PbO 2 Pb 4+ + 2O 2– = (4+) + 2(2–) = 0