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Jo Richardson Community School BTEC First Diploma in Engineering
Using Arithmetic Solve the following two problems using the appropriate arithmetic to ensure that your answers are realistic and reasonable Problem 1: You are manufacturing a series of tools in a batch. The batch consists of 13 parts. You must manufacture the parts using a length of cold rolled steel at 40x20x400. Each part to be manufactured has an overall size of 40x20x40. 1. Calculate how many parts can be made from the length of steel. Problem 2: Each part that you manufacture must have a section from it removed. This section is located in the centre of each part and is sized at 15mm2 1. Calculate how much waste there will be per square as a percentage to the manufactured part. 2. Calculate the overall waste from the entire length of steel. Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 1a(i,ii) Grading Criteria: P Key Skills: Assignment 1: Using arithmetic to solve engineering problems Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Plotting Graphs Linear graphs From these results create a graph showing the relationship between those two quantities (plot I(mA) on the X-axis). V 1 2 3 4 5 I (mA) 10 20 30 40 50 y x Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 1b(i) Grading Criteria: P Key Skills: Assignment 1: Plotting linear graphs Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Plotting Graphs Linear graphs From these results create a graph showing the relationship between those two quantities (plot I(mA) on the X-axis). V 1 2 3 4 5 I (mA) 10 20 30 40 50 Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 1b(i) Grading Criteria: P3 Key Skills: Assignment 1: Plotting linear graphs T Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Plotting Graphs Non-linear graphs A light bulb has been tested for its electrical properties and the results collected are shown in the table below: From these results create a graph showing the relationship between those two quantities (plot I(mA) on the X-axis). V 1 2 3 4 5 I (mA) 19 31 39 47 53 y x Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 1b(ii) Grading Criteria: P Key Skills: Assignment 1: Plotting non-linear graphs Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Plotting Graphs Non-linear graphs A light bulb has been tested for its electrical properties and the results collected are shown in the table below: From these results create a graph showing the relationship between those two quantities (plot I(mA) on the X-axis). V 1 2 3 4 5 I (mA) 19 31 39 47 53 Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 1b(ii) Grading Criteria: P Key Skills: Assignment 1: Plotting non-linear graphs T Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Transposition and Evaluation of Formulae Use mathematical methods to transpose and evaluate simple formulae Simplify these expressions, removing brackets where possible, and write your result in algebraic form: a) b) A temperature F, measured on the Fahrenheit scale, and the same temperature C, on the Celsius scale, are related by the formula: 2. Convert the following temperatures to the Fahrenheit scale. a) Normal body temperature: 37oC b) Room temperature: 20oC B Brackets O Order (Powers) D Division M Multiplication A Addition S Subtraction Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 2a Grading Criteria: P Key Skills: Assignment 2: Use mathematical methods to transpose and evaluate simple formulae Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Transposition and Evaluation of Formulae Use mathematical methods to transpose and evaluate simple formulae Simplify these expressions, removing brackets where possible, and write your result in algebraic form: a) b) A temperature F, measured on the Fahrenheit scale, and the same temperature C, on the Celsius scale, are related by the formula: 2. Convert the following temperatures to the Fahrenheit scale. a) Normal body temperature: 37oC b) Room temperature: 20oC 6 – (4 x 2) 6 – 8 = -2 (2) 2a 2 x 2a = 4a B Brackets O Order (Powers) D Division M Multiplication A Addition S Subtraction F = 9 x (37) + 32 F = 98.6 5 F = 9 x (20) + 32 F = 68 5 Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 2a Grading Criteria: P Key Skills: Assignment 1: Use mathematical methods to transpose and evaluate simple formulae T Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Transposition and Evaluation of Formulae Transpose and evaluate a complex formula You must correctly answer the following showing your workings The general equation for a straight line is: Transpose the formula to make x the subject of the formula Evaluate x when m = 8.5, y = 120 and c = 75. Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 2b(i) Grading Criteria: M Key Skills: Assignment 2: Transposition and evaluation of formula Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Transposition and Evaluation of Formulae Transpose and evaluate a complex formula You must correctly answer the following showing your workings The general equation for a straight line is: Transpose the formula to make x the subject of the formula Evaluate x when m = 8.5, y = 120 and c = 75. y = m x + c y – c = m x y - c = x x = y – c m m x = y – c x = (120-75) x = 4 5 x = to 3d.p m 8.5 8.5 Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 2b(i) Grading Criteria: M Key Skills: Assignment 2: Transposition and evaluation of formula T Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Transposition and Evaluation of Formulae Transpose and evaluate a complex formula You must correctly answer the following showing your workings Using the following common equation, Transpose the formula to make u the subject of the formula. Evaluate u when t = 20, a = 0.5 and s = 200. Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 2b(ii) Grading Criteria: M Key Skills: Assignment 2: Transposition and evaluation of formula Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Transposition and Evaluation of Formulae Transpose and evaluate a complex formula You must correctly answer the following showing your workings Using the following common equation, Transpose the formula to make u the subject of the formula. Evaluate u when t = 20, a = 0.5 and s = 200. s = u t + ½ a t2 s - ½ a t2 = u t s – ½ a t2 = u s – 1(a t2) = u s – (a t2) = u s – a t = u u = ½ (s – a t) t 2t 2t t u = ½ (s – a t) u = ½ (200 – 0.5 x 20) u = ½ (200 – 10) u = ½ x 190 u = 95 Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 2b(ii) Grading Criteria: M Key Skills: Assignment 2: Transposition and evaluation of formula T Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Transposition and Evaluation of Formulae Transpose and evaluate a complex formula You must correctly answer the following showing your workings Using the following common equation, Transpose the formula to make c the subject of the formula. Evaluate c when a = 1.75 and b = 0.25 Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 2b(iii) Grading Criteria: M Key Skills: Assignment 2: Transposition and evaluation of formula Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Transposition and Evaluation of Formulae Transpose and evaluate a complex formula You must correctly answer the following showing your workings Using the following common equation, Transpose the formula to make c the subject of the formula. Evaluate c when a = 1.75 and b = 0.25 b2 = (a2 – c2) b2 + c2 = a2 a2 – b2 = c2 c = (a2 – b2) c = (a2 – b2) c = (1.752 – 0.252) c = ( – ) c = 3 Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 2b(iii) Grading Criteria: M Key Skills: Assignment 2: Transposition and evaluation of formula T Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Transposition and Evaluation of Formulae Transpose and evaluate combining formulae You must correctly answer the following showing your workings Using the following common equation, I2R = VI Transpose the formula to make V the subject of the formula. Evaluate V when I = 4 and R = 1 Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 2c Grading Criteria: D Key Skills: Assignment 2: Transposition and evaluation of formula Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Transposition and Evaluation of Formulae Transpose and evaluate combining formulae You must correctly answer the following showing your workings Using the following common equation, I2R = VI Transpose the formula to make V the subject of the formula. I2 R = V I I2 R = V I2 R = V I R = V V = I R Evaluate V when I = 4 and R = 1 V = I R V = 4 x 1 V = 4 I I Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 2c Grading Criteria: D Key Skills: Assignment 2: Transposition and evaluation of formula T Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Using a Scientific Calculator Perform chained calculations in assignment 2 using the basic and special functions keys of an electronic scientific calculator. Using the buttons adjacent, show the steps you have taken to complete Task 2bi Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 2d Grading Criteria: D Key Skills: Assignment 2: Using a Scientific Calculator Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Using a Scientific Calculator Carry out chained calculations using an electronic calculator. You will be observed during these tasks. YOU MUST MAKE SURE YOU GET YOUR OBSERVATION SHEET SIGNED TO ACHIEVE THIS GRADE CRITERIA. Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 2d Grading Criteria: D Key Skills: Assignment 2: Using a Scientific Calculator Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Surface area of regular shapes Calculate the surface area for TWO shapes. These shapes are similar to those used in your practical sessions. The data can be used to determine the amount of finishing needed to complete the projects by polishing the faces and the quantity of materials used. Scribing Block Depth Gauge 40mm 30mm 25mm 25mm 40mm Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 3a Grading Criteria: P Key Skills: Assignment 3: Calculating surface area of regular shapes Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Surface area of regular shapes Calculate the surface area for TWO shapes. These shapes are similar to those used in your practical sessions. The data can be used to determine the amount of finishing needed to complete the projects by polishing the faces and the quantity of materials used. Scribing Block Depth Gauge Known: Side A x 2 Side B x 2 Side C x 2 Surface Area of A 25mm x 40mm = 1000mm2 Surface Area of B 40mm x 30mm = 1200mm2 Surface Area of C 30mm x 25mm = 750mm2 Total Surface Area = 2(SAA) + 2(SAB) + 2(SAC) = 2(1000) + 2(1200) + 2(750) = = 5900mm2 40mm 30mm 25mm B C A Surface Area of A A = r2 A = x (1/2d) A = x (1/2 x 25)2 A = x A = mm2 2d.p Surface Area of B A = C x height A = (d) x height A = (78.540) x 40 A = mm2 2d.p Total Surface Area = 2(SAA) + SAB = (2 x ) = = mm2 Known: C = 2r or C = d A = r2 d = 2r or r = ½ d Side A x 2 Side B x 1 25mm A 40mm B B Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 3a Grading Criteria: P Key Skills: Assignment 3: Calculating surface area of regular shapes T Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Volume of regular shapes Calculate the volume for TWO shapes. These shapes are similar to those used in your practical sessions. The data can be used to determine the amount of finishing needed to complete the projects by polishing the faces and the quantity of materials used. Scribing Block Depth Gauge 40mm 30mm 25mm 25mm 40mm Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 3b Grading Criteria: P Key Skills: Assignment 3: Calculating volume of regular shapes Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Volume of regular shapes Calculate the volume for TWO shapes. These shapes are similar to those used in your practical sessions. The data can be used to determine the amount of finishing needed to complete the projects by polishing the faces and the quantity of materials used. Scribing Block Depth Gauge Known: Cross Section = A V = A x length Surface Area of A 25mm x 40mm = 1000mm2 Volume of Shape V = 1000 x 30 V = 30000mm3 40mm 30mm 25mm B C A Known: Cross Section = A A = r2 d = 2r or r = ½ d V = A x length Surface Area of A A = r2 A = x (1/2d) A = x (1/2 x 25)2 A = x A = mm2 2d.p Volume of Shape V = x 40 V = mm3 25mm A 40mm B Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 3b Grading Criteria: P Key Skills: Assignment 3: Calculating volume of regular shapes T Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Surface area of compound shapes You must ‘identify’ the ‘data’ required and determine (calculate) the TOTAL SURFACE AREA of TWO compound shapes – you must show ALL your workings SHAPE 1 – Trapezoid 40 A B 130 50 60 CL Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 3c(i) Grading Criteria: M Key Skills: Assignment 3: identify the data required and determine the area of two compound shapes Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Surface area of compound shapes You must ‘identify’ the ‘data’ required and determine (calculate) the TOTAL SURFACE AREA of TWO compound shapes – you must show ALL your workings SHAPE 1 – Trapezoid Known: Side A x 2 Side B x 2 Top x 1 Base x 1 Total Surface Area of A = i + ii + iii i = ½ (1/2(130-40) x 60) i = ½ (2700) i = 1350 i = iii therefore iii = 1350 ii = 40 x 60 ii = 2400 = = 5100 Surface Area of B Find x using Pythagoras Theorem c = x c2 = a2 + b2 c = a2 + b2 c = c = 5625 c = 75 therefore x = 75 Total Area = 75 x 50 Total Area = 3750 Surface Area of Top Area = 40 x 50 = 2000 Surface Area of Base Area = 130 x 50 = 65000 Total Surface Area = 2A + 2B + Top + Base = 2(5100) + 2(3750) = = 84700 40 A B 130 50 x 60 x b i ii iii CL a Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 3c(i) Grading Criteria: M Key Skills: Assignment 3: identify the data required and determine the area of two compound shapes T Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Surface area of compound shapes You must ‘identify’ the ‘data’ required and determine (calculate) the TOTAL SURFACE AREA of TWO compound shapes – you must show ALL your workings Scribing Block Base 50 80 160 R = 40 Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 3c(ii) Grading Criteria: M Key Skills: Assignment 3: identify the data required and determine the area of two compound shapes Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Surface area of compound shapes You must ‘identify’ the ‘data’ required and determine (calculate) the TOTAL SURFACE AREA of TWO compound shapes – you must show ALL your workings Scribing Block Base Known: Side A x 2 Side B x 2 Side C x 1 Side D x 1 Total Surface Area of A = A + Ai A = 80 x 80 = 6400 To find Ai, find the ½ the area or a circle when r = 40 Area = r2 Area = x 1600 Area = Therefore total area = A + Ai = = Surface Area of B Area = 80 x 50 = 4000 Surface Area of C Surface Area of D To find curve – find the circumference of the ½ circle when r = 40 Circumference = 2r Circumference = 2 x x 40 Circumference = ½ Circumference = Area = x 50 = 6283 Total Surface Area Area = 2A + 2B + C + D = 2( ) + 2(4000) = = 50 B 80 C A D D Ai 160 R = 40 80 CL Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 3c(ii) Grading Criteria: M Key Skills: Assignment 3: identify the data required and determine the area of two compound shapes T Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Surface area of compound shapes You must ‘identify’ the ‘data’ required and determine (calculate) the TOTAL VOLUME of TWO compound shapes – you must show ALL your workings SHAPE 1 – Trapezoid 40 A B 130 50 60 CL Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 3d(i) Grading Criteria: M Key Skills: Assignment 3: identify the data required and determine the volume of two compound shapes Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Surface area of compound shapes You must ‘identify’ the ‘data’ required and determine (calculate) the TOTAL VOLUME of TWO compound shapes – you must show ALL your workings SHAPE 1 – Trapezoid Total Surface Area of A = 5100 Volume = Surface Area x length = 5100 x 50 = 40 A B 130 50 60 CL Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 3d(i) Grading Criteria: M Key Skills: Assignment 3: identify the data required and determine the volume of two compound shapes T Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Surface area of compound shapes You must ‘identify’ the ‘data’ required and determine (calculate) the TOTAL VOLUME of TWO compound shapes – you must show ALL your workings Scribing Block Base – 50 80 A Ai 160 R = 40 Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 3d(ii) Grading Criteria: M Key Skills: Assignment 3: identify the data required and determine the area of two compound shapes Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Surface area of compound shapes You must ‘identify’ the ‘data’ required and determine (calculate) the TOTAL VOLUME of TWO compound shapes – you must show ALL your workings Scribing Block Base – Total Surface Area of A = A + Ai = A + Ai = = Volume = Surface Area x length = x 50 = 50 80 A Ai 160 R = 40 Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 3d(ii) Grading Criteria: M Key Skills: Assignment 3: identify the data required and determine the area of two compound shapes T Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Using Pythagoras Pythagoras’ Theorem to find the hypotenuse, opposite and tangent length Using Pythagoras’s theorem, calculate the length of the hypotenuse, giving your results in metres. Show all steps in your calculations. B 20mm a2 + b2 = c2 A C 30mm Likewise c2 - a2 = b2 c a c2 - b2 = a2 Hypotenuse Opposite b Adjacent Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 4a(i) Grading Criteria: P Key Skills: Assignment 4: Solutions to right angle triangle problems Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Using Pythagoras Pythagoras’ Theorem to find the hypotenuse, opposite and tangent length Using Pythagoras’s theorem, calculate the length of the hypotenuse, giving your results in metres. Show all steps in your calculations. B C = a2 + b2 C = C = ( ) C = 1300 C = 36.06mm 20mm a2 + b2 = c2 A C 30mm Likewise c2 - a2 = b2 c a c2 - b2 = a2 Hypotenuse Opposite b Adjacent Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 4a(i) Grading Criteria: P Key Skills: Assignment 4: Solutions to right angle triangle problems T Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Using Pythagoras Pythagoras’ Theorem to find the hypotenuse, opposite and tangent length Using Pythagoras’s theorem, calculate the length of the hypotenuse, giving your results in metres. Show all steps in your calculations. 100cm 85cm X a2 + b2 = c2 80m 20m X Likewise c2 - a2 = b2 c a c2 - b2 = a2 X 80cm b 120cm Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 4a(ii) Grading Criteria: P Key Skills: Assignment 4: Solutions to right angle triangle problems Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Using Pythagoras Pythagoras’ Theorem to find the hypotenuse, opposite and tangent length Using Pythagoras’s theorem, calculate the length of the hypotenuse, giving your results in metres. Show all steps in your calculations. X = a2 + b2 C = C = ( ) C = 17225 C = cm 100cm 85cm X X = a2 + b2 C = C = ( ) C = 6800 C = 82.46m a2 + b2 = c2 80m 20m X Likewise c2 - a2 = b2 c a c2 - b2 = a2 X = c2 - a2 C = C = ( ) C = 8000 C = 89.44cm X 80cm b 120cm Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 4a(ii) Grading Criteria: P Key Skills: Assignment 4: Solutions to right angle triangle problems T Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Sine, Cosine and Tangent ratio tables Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: Grading Criteria: FACT SHEET Key Skills: Assignment 4: Sine, Cosine and Tangent ratio tables FACT SHEET Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
There are three formulae involved in trigonometry Sine = opposite/hypotenuse Cosine = adjacent/hypotenuse Tangent = opposite/adjacent These can easily be remembered using SOH CAH TOA Using Pythagoras Pythagoras’ Theorem using sine, cosine and tangent ratios Using sine, cosine and tangent tables, calculate the following: 1. 3. a 20cm 650 2. 15mm a Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 4b Grading Criteria: P6 Key Skills: Assignment 4: Solutions to right angle triangle problems T Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
There are three formulae involved in trigonometry Sine = opposite/hypotenuse Cosine = adjacent/hypotenuse Tangent = opposite/adjacent These can easily be remembered using SOH CAH TOA Using Pythagoras Pythagoras’ Theorem using sine, cosine and tangent ratios Using sine, cosine and tangent tables, calculate the following: Using the Tangent Ratio Table Known – adjacent and opposite values Tan (angle) = opposite / adjacent Tan 28 = a / 15 a = tan 28 x 15 a = x 15 a = 7.98mm 1. 3. a 20cm 650 Using the Cosine Ratio Table Known – adjacent and hypotenuse values Cos (angle) = adjacent / hypotenuse Cos 65 = a / 20 a = cos 65 x 20 a = x 20 a = 8.45cm 2. Using the Sine Ratio Table Known – opposite and hypotenuse values Sin (angle) = opposite / hypotenuse Sin 25 = 15 / a Sin25 x a = 15 a = 15 / sin25 a = 15 / a = 35.49m 15mm a Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 4b Grading Criteria: P Key Skills: Assignment 4: Solutions to right angle triangle problems T Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Using trigonometry to solve complex shapes Calculate the length of VA Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 4c Grading Criteria: M Key Skills: Assignment 4: Using trigonometry to solve complex shapes Jo Richardson Community School BTEC First Diploma in Engineering
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Jo Richardson Community School BTEC First Diploma in Engineering
Using trigonometry to solve complex shapes Calculate the length of VA Name: Candidate No: Unit 3: Mathematics for Engineering Technicians Task: 4c Grading Criteria: M Key Skills: Assignment 4: Using trigonometry to solve complex shapes T Jo Richardson Community School BTEC First Diploma in Engineering
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