1. Slide 12- 1 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley

2. Exponential and Logarithmic Functions CHAPTER 12.1Composite and Inverse Functions 12.2Exponential Functions 12.3Logarithmic Functions 12.4Properties of Logarithms 12.5Common and Natural Logarithms 12.6Exponential and Logarithmic Equations with Applications 12

3. Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Composite and Inverse Functions 12.1 1.Find the compososition of two functions. 2.Show that two functions are inverses. 3.Show that a function is one-to-one. 4.Find the inverse of a function. 5.Graph a given function’s inverse function.

4. Slide 12- 4 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Composite functions: If f and g are functions, then the composition of f and g is defined as For all x in the domain g for which g(x) is the domain of f. The composition of g and f is defined as for all x in the domain of g for which f(x) is in the domain of g.

5. Slide 12- 5 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley If and find the following. Solution Example Replace g(x) with 2x – 5. In f(x), replace x with 2x – 5. Simplify. a. b. a.

6. Slide 12- 6 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley continued Replace f(x) with 3x + 8. In g(x), replace x with 3x + 8 Simplify. b.

7. Slide 12- 7 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Inverse functions: Two functions f and g are inverses if and only if for all x in the domain of g and for all x in the domain of f. Inverse Functions To determine whether two functions f and g are inverses of each other, 1. Show that for all x in the domain of g. 2.Show that for all x in the domain of f.

8. Slide 12- 8 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Solution Example Verify that f and g are inverses. We need to show that and Since and, f and g are inverses.

9. Slide 12- 9 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley One-to-One function: A function f is one-to-one if for any two numbers a and b in its domain, when f(a) = f(b), a = b and when a b, f(a) f(b). Horizontal Line Test for One-to-One Functions Given a function’s graph, the function is one-to-one if every horizontal line that can intersect the graph does so at one and only one point.

10. Slide 12- 10 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Determine whether the graph is a one-to-one function. Solution Example A horizontal line can intersect the graph in more than one point, so the function is not one-to-one.

11. Slide 12- 11 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Finding the Inverse Function of a One-to-One Function 1. If necessary, replace f(x) with y. 2.Replace all x’s with y’s and y’s with x’s. 3.Solve the equation from step 2 for y. 4.Replace y with f -1 (x). Existence of Inverse Functions A function has an inverse function if and only if the function is one-to-one.

12. Slide 12- 12 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Solution Example Find f -1 (x) for the function f(x) = 7x – 4. y = 7x – 4 x = 7y – 4 Since f[f -1 (x)]= x and f -1 [f (x)] = x, they are inverses.

13. Slide 12- 13 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Graph of Inverse Functions The graphs of f and f -1 are symmetric to the graph of y = x.

14. Slide 12- 14 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Solution Example Sketch the inverse of the function whose graph is shown. Draw the line y = x and reflect the graph on the line.

15. Slide 12- 15 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley If f(x) = x + 7 and g(x) = 2x – 12, what is a) -44 b) -3 c) 3 d) 44

16. Slide 12- 16 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley If f(x) = x + 7 and g(x) = 2x – 12, what is a) -44 b) -3 c) 3 d) 44

17. Slide 12- 17 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Find f -1 (x) for 6x – 7. a) b) c) d)

18. Slide 12- 18 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Find f -1 (x) for 6x – 7. a) b) c) d)

19. Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Exponential Functions 12.2 1.Define and graph exponential functions. 2.Solve equations of the form b x = b y for x. 3.Use exponential functions to solve application problems.

20. Slide 12- 20 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Exponential function: If b > 0, b 1, and x is any real number, then the exponential function is f(x) = b x. Note: The definition of the exponential function has two restrictions on b. If b = 1, then f(x) = b x = 1 x = 1, which is a linear function. If b < 0, then we could get values for which the function is not defined as a real number.

21. Slide 12- 21 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example Graph f(x) = 2 x, and g(x) = 3 x.. Solution x–2–1012 f(x)f(x)124 g(x)g(x)139 Comparing the graphs, we can see the greater value of b, the steeper the graph. f(x) = 2 x g(x) = 3 x

22. Slide 12- 22 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example Graph f(x) = 3 x+3. Solution x f(x)f(x) -43 -1 = -33 0 = 1 -23 1 = 3 3 2 = 9 03 3 = 27 f(x) = 3 x+3

23. Slide 12- 23 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Solving Exponential Equations 1. If necessary, write both sides of the equation as a power of the same base. 2.If necessary, simplify the exponents. 3.Set the exponents equal to each other. 4.Solve the resulting equation. The One-to-One Property of Exponentials Given b > 0 and b 1, if b x = b y, then x = y.

24. Slide 12- 24 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example Solve. a. 3 x = 81 b. Solution a.3 x = 81 3 x = 3 4 x = 4 The solution set is {4}. b. The solution set is {–4}.

25. Slide 12- 25 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example Rayanne deposited $15,000 in an account that pays 7% annual interest compounded quarterly. How much is accumulated in the account after 10 years? Solution Understand We are asked to find A and given that t = 10, P = $15,000, r = 0.07, and n = 4. Plan Use the formula

26. Slide 12- 26 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley continued Substitution. Simplify. Evaluate using a calculator and round to the nearest cent. Execute Answer After 10 years, the accumulated account is $30,023.96.

27. Slide 12- 27 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley continued Check Verify that the principal is $15,000 if the accumulated amount is $30,023.96 after the principal is compounded quarterly. Since the accumulated amount was rounded, it is expected our calculated value of the principal to be slightly different from $15,000.

28. Slide 12- 28 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Which of the following functions does the graph represent? a) f(x) = 4 x+2 b) f(x) = 4 x–2 c) f(x) = 2 x+4 d) f(x) = 2 x–4

29. Slide 12- 29 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Which of the following functions does the graph represent? a) f(x) = 4 x+2 b) f(x) = 4 x–2 c) f(x) = 2 x+4 d) f(x) = 2 x–4

30. Slide 12- 30 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley A stereo system is purchased for $2500. It’s value each year is about 85% of its value in the preceding year. Its value in dollars after t years is given by the exponential function V(t) = 2500(0.85) t. Find the salvage value of the stereo after 4 yr. a) $1285.23 b) $1296.42 c) $1305.02 d) $1316.84

31. Slide 12- 31 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley A stereo system is purchased for $2500. It’s value each year is about 85% of its value in the preceding year. Its value in dollars after t years is given by the exponential function V(t) = 2500(0.85) t. Find the salvage value of the stereo after 4 yr. a) $1285.23 b) $1296.42 c) $1305.02 d) $1316.84

32. Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Logarithmic Functions 12.3 1.Convert between exponential and logarithmic forms. 2.Solve logarithmic equations by changing to exponential form. 3.Graph logarithmic functions. 4.Solve applications involving logarithms.

33. Slide 12- 33 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Logarithm: If b > 0 and b 1, then y = log b x is equivalent to x = b y. x = b y y = log b x The exponent is the logarithm. The base is the base of the logarithm.

34. Slide 12- 34 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Solving Logarithmic Equations To solve an equation of the form log b x = y, where b, x, or y is a variable, write the equation in exponential form, b y = x, and then solve for the variable. Example Solve log 7 x = 3. Solution Write the equation in exponential form. log 7 x = 3 7 3 = x343 = x

35. Slide 12- 35 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example Solve Solution Begin by rewriting the equation in exponential form and then solve. Divide both sides by -3 to isolate the logarithm. Simplify. Subtract 11 from both sides. Write in exponential form. For any real number b, where b > 0 and b 1, 1. log b b = 1 2. log b 1 = 0

36. Slide 12- 36 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Graphing Logarithmic Functions To graph a function in the form f(x) = log b x, 1. Replace f(x) with y and then write the logarithm in exponential form x = b y. 2. Find ordered pairs that satisfy the equation by assigning values to y and finding x. 3.Plot the ordered pairs and draw a smooth curve through the points.

37. Slide 12- 37 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example Graph f(x) = log 1/4 x. Solution Replacing f(x) by y, we see that the equation y = log 1/4 x can be rewritten in exponential form as y –2 –1 0 1 2 x = 0

38. Slide 12- 38 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example The function P = 95 – 30 log 2 x models the percent, P, of students who recall the important features of a classroom lecture over time, where x is the number of days that have elapsed since the lecture was given. What percent of the students recall the important features of a lecture 8 days after it was given? (Source: Psychology for the New Millennium, 8 th Edition, Spencer A. Rathos, Thomson Publishing Company) Solution Understand We are given the function that models the percent, P, of students who recall the important features of a lecture x days after it is given. We are to find the percent of students who recall the important features of a lecture 8 days after it was given.

39. Slide 12- 39 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley continued Execute Answer 5% of the students remember the important features of a lecture 8 days after it is given. Plan Evaluate P = 95 – 30log 2 x where x = 8. P = 95 – 30log 2 8 P = 95 – 30(3) P = 95 – 90 P = 5 Check 5 = 95 – 30log 2 x –90 = – 30log 2 x 3 = log 2 x 2 3 = x 8 = x

40. Slide 12- 40 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Write 6 2 = 36 in logarithmic form. a) b) c) d)

41. Slide 12- 41 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Write 6 2 = 36 in logarithmic form. a) b) c) d)

42. Slide 12- 42 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Write in exponential form. a) b) c) d)

43. Slide 12- 43 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Write in exponential form. a) b) c) d)

44. Slide 12- 44 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Solve log 3 x = 5. a) -243 b) -125 c) 125 d) 243

45. Slide 12- 45 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Solve log 3 x = 5. a) -243 b) -125 c) 125 d) 243

46. Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Properties of Logarithms 12.4 1.Apply the inverse properties of logarithms. 2.Apply the product, quotient, and power properties of logarithms.

47. Slide 12- 47 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Inverse Properties of Logarithms For any real numbers b and x, where b > 0 and b 1, and x > 0, 1. b log b x = x 2. log b b x = x

48. Slide 12- 48 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Further Properties of Logarithms For real numbers x, y, and b, where x > 0, y > 0, b > 0, and b 1. Product Rule of Logarithms: log b xy = log b x + log b y Quotient Rule of Logarithms: Power Rule of Logarithms: log b x r = rlog b x (The logarithm of the product of two numbers is equal to the sum of the logarithms of the numbers.) (The logarithm of the quotient of two numbers is equal to the difference of the logarithms of the numbers.) (The logarithm of a number raised to the power is equal to the exponent times the logarithm of the number.)

49. Slide 12- 49 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example Use the product rule of logarithms to write each expression as a sum of logarithms. a. log b pqrb. log b x(x + 5) Solution a. log b pqr = log b p + log b q + log b r b. log b x(x+5) = log b x + log b (x + 5)

50. Slide 12- 50 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example Use the quotient rule of logarithms in the form to write the expression as a single logarithm. Solution

51. Slide 12- 51 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example Use the power rule of logarithms to write the expression as a multiple of a logarithm. Solution a. log 3 x 11 log 3 x 11 = 11 log 3 x b. a. b. = log b x -7 = -7log b x

52. Slide 12- 52 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example Write the expression as a sum or difference of multiples of logarithms. Solution Use the product and quotient rules. = log b x 7 + log b z 9  log b y 4 Use the power rule. = 7 log b x + 9 log b z  4 log b y

53. Slide 12- 53 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example Write the expression as a single logarithm. Leave answer in simplest form without negative or fractional exponents. Solution

54. Slide 12- 54 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Use the power rule to write the expression as a multiple of a logarithm. a) b) c) d)

55. Slide 12- 55 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Use the power rule to write the expression as a multiple of a logarithm. a) b) c) d)

56. Slide 12- 56 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Express as a single logarithm: a) b) c) d)

57. Slide 12- 57 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Express as a single logarithm: a) b) c) d)

58. Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Common and Natural Logarithms 12.5 1.Define common logarithms and evaluate them using a calculator. 2.Solve applications using common logarithms. 3.Define natural logarithms and evaluate them using a calculator. 4.Solve applications using natural logarithms.

59. Slide 12- 59 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Common logarithms: Logarithms with a base of 10. Log 10 x is written as log x. Solution Example Use a calculator to approximate each common logarithm. Round to the nearest thousandth if necessary. a. log 456b. log 0.00257 a. log 456 b.log 0.00257

60. Slide 12- 60 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example The function is used to calculate sound intensity, where d represents the intensity in decibels, I represents the intensity watts per unit of area, and I 0 represents the faintest audible sound to the average human ear, which is 10 -12 watts per square meter. What is the intensity level of sounds at a decibel level of 75 dB? Understand We are given the function, and we are to find the sound intensity, I.

61. Slide 12- 61 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley continued Execute Answer The sound intensity is 10 –4.5. Plan Using, substitute 75 for d and 10 -12 for I 0 and then solve for I.

62. Slide 12- 62 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley continued Check If the sound intensity is 10 -4.5, verify the decibel reading is 75.

63. Slide 12- 63 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Natural logarithms: Base-e logarithms are called natural logarithms and log e x is written as ln x. Note that ln e = 1. Solution Example Use a calculator to approximate each natural logarithm to four decimal places. a. ln 67 b. ln 0.0072 a. ln 67 b.ln 0.00257

64. Slide 12- 64 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example If an account pays 8% annual interest, compounded continuously, how long will it take a deposit of $25,000 to produce an account balance of $100,000? Understand We are to find the time it takes for $25,000 to grow to $100,000 if it is compounded continuously at 8%. Plan In, replace P with 25,000, r with 0.08, A with $100,000, and then simplify.

65. Slide 12- 65 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley continued Answer The account balance will reach $100,000 in approximately 17.33 years. Substitute. Divide. Approximate using a calculator. Execute

66. Slide 12- 66 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley continued Check Because 17.33 was not the exact time, $100,007.45 is reasonable.

67. Slide 12- 67 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Use a calculator to approximate log 0.267 to four decimal places. a) -1.3205 b) -0.5735 c) 1.3060 d) 1.8493

68. Slide 12- 68 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Use a calculator to approximate log 0.267 to four decimal places. a) -1.3205 b) -0.5735 c) 1.3060 d) 1.8493

69. Slide 12- 69 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Use a calculator to approximate ln 21 to four decimal places. a) 0.7636 b) 1.3316 c) 3.0445 d) 5.3688

70. Slide 12- 70 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Use a calculator to approximate ln 21 to four decimal places. a) 0.7636 b) 1.3316 c) 3.0445 d) 5.3688

71. Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Exponential and Logarithmic Equations with Applications 12.6 1.Solve equations that have variables as exponents. 2.Solve equations containing logarithms. 3.Solve applications involving exponential and logarithmic functions. 4.Use the change-of-base formula.

72. Slide 12- 72 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Properties for Solving Exponential and Logarithmic Equations For any real numbers b, x, and y, where b > 0 and b 1, 1. If b x = b y, then x = y. 2. If x = y, then b x = b y. 3.For x > 0 and y > 0, if log b x = log b y, then x = y. 4.For x > 0 and y > 0, if x = y, then log b x = log b y. 5.For x > 0, if log b x = y, then b y = x.

73. Slide 12- 73 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example Solve 8 x = 15. Solution Use if x = y, then log b x = log b y (property 4). Divide both sides by log 8. The exact solution is. Using a calculator, we find. Check8 x = 15 8 1.3023 = 15 15.0001 = 15 The answer is correct.

74. Slide 12- 74 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Solving Equations Containing Logarithms To solve equations containing logarithms, use the properties of logarithms to simplify each side of the equation and then use one of the following. If the simplification results in an equation in the form log b x = log b y, use the fact that x = y, and then solve for the variable. If the simplification results in an equation in the form log b x = y, write the equation in exponential form, b y = x, and then solve for the variable (as we did in Section 10.3).

75. Slide 12- 75 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example Solve Solution This equation is in the form log b x = y, so write it in exponential form, b y = x. Solve for x.

76. Slide 12- 76 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example Solve Solution Logarithms are defined for positive numbers only. A check will show that x = 5 the only solution.

77. Slide 12- 77 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example Solve. Solution These 2 solutions check and are the solutions for this equation.

78. Slide 12- 78 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example If $1000 is deposited into an account at 7.6% interest compounded continuously, how much money will be in the account after 8 years? Understand We are given P = $1000, r = 0.076, and t = 8 and we are asked to find A. Plan Use Execute

79. Slide 12- 79 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley continued There will be $1836.75 in the account.Answer CheckUse the formula It checks.

80. Slide 12- 80 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example A nuclear reactor contains 200 grams of radioactive plutonium 239 P. Plutonium disintegrates according to the formula A = A 0 e -0.0000284t. How much will remain after 5000 years? Understand We are given A 0 = 200 g and t = 5000 years and are asked to find A. Plan Use Execute Simplify. Substitute.

81. Slide 12- 81 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley continued About 173.52 grams will remain after 5000 years. Answer Check Use A = A 0 e -0.0000284t to verify that it takes 5000 years for 200 grams of 239 P to disintegrate to 173.52 grams. It checks. 173.52 = 200e -0.0000284t

82. Slide 12- 82 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Change-of-Base Formula In general, if a > 0, a 1, b > 0, b 1, and x > 0, then In terms of common and natural logarithms,

83. Slide 12- 83 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Example Use the change-of-base formula to calculate log 5 12. Round the answer to four decimal places. Solution Check The answer is correct.

84. Slide 12- 84 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Solve log x + log(x – 3) = 1. a) x = -2 b) x = 5 c) x = -2 or x = 5 d) x is undefined.

85. Slide 12- 85 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Solve log x + log(x – 3) = 1. a) x = -2 b) x = 5 c) x = -2 or x = 5 d) x is undefined.

86. Slide 12- 86 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley If $500 is deposited into an account at 9% interest compounded continuously, how much will be in the account after 5 years? a) $653.79 b) $784.16 c) $892.36 d) $45,008.57

87. Slide 12- 87 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley If $500 is deposited into an account at 9% interest compounded continuously, how much will be in the account after 5 years? a) $653.79 b) $784.16 c) $892.36 d) $45,008.57

88. Slide 12- 88 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Use the change-of-base formula to approximate log 7 56. a) 0.48 b) 0.85 c) 2.07 d) 8

89. Slide 12- 89 Copyright © 2006 Pearson Education, Inc. Publishing as Pearson Addison-Wesley Use the change-of-base formula to approximate log 7 56. a) 0.48 b) 0.85 c) 2.07 d) 8