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Least-Squares Regression
Chapter 17 Least-Squares Regression Lecture Notes Dr. Rakhmad Arief Siregar Universiti Malaysia Perlis Applied Numerical Method for Engineers
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Curve Fitting
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Curve Fitting
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Curve Fitting
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Simple Statistics
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Regression Polynomial fit Experimental data Least-squares fit
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Linear Regression The simplest example of a least-squares approximation is fitting a straight line a0 and a1 are coefficients representing the intercept and the slope e is the error or residual between the model and the observations
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Linear Regression By rearranging:
e is the error or residual, the discrepancy between the true value of y a0+a1x is the approximate value
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Criteria for a “Best” Fit
By minimizing the sum of the residual error n is total number of points
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Criteria for a “Best” Fit
By minimizing the sum of absolute residual error n is total number of points
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Criteria for a “Best” Fit
By minimizing the sum of the squares of the residuals between the measured y and the y calculated with the linear mode
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Best fit Minimizes the sum of the residuals
Minimizes the sum of the absolute value of residuals Minimizes the maximum error of any individual point
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Least-Squares Fit of a Straight Line
Differentials:
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Least-Squares Fit of a Straight Line
After several mathematical steps, a0 and a1 will yields: Where y and x are the means of y and x, respectively
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Ex. 17.1 Fit a straight line to the x and y values in the first two columns of Table below.
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Ex. 17.1 The following quantities can be computed
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Ex. 17.1 a1 and a0 can be computed:
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Ex. 17.1 The least-squares fit is:
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Problem 17.4 Use least-squares regression to fit a straight line to:
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Problem 17.4
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Quantification of Error of Linear Regression
Squared of residual error:
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Quantification of Error of Linear Regression
If those criteria are met, a “standard deviation” for regression line can be determined as: where: Sy/x is called standard error of estimate. Subscript y/x means the error is for a predicted value of y corresponding to a particular value of x
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Quantification of Error of Linear Regression
The spread of the data around the mean The spread of the data around best fit line
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Quantification of Error of Linear Regression
Small residual errors Large residual errors
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Quantification of Error of Linear Regression
The difference between the two quantities, St –Sr, quantifies the improvement or error reduction due to describing the data in terms of a straight line. The difference is normalized to St to yield: r2 : coefficient of determination r : correlation coefficient
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Ex. 17.2 Compute the total standard deviation, the standard error of the estimate and the correlation coefficient for the data in Ex. 17.1
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Ex. 17.2 Solution Standard deviation: Standard error of estimate:
The extent of the improvement is qualified because sy/x < sy the linear regression model has merit
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Ex. 17.2 Solution The correlation coefficient:
These results indicate 86.8 percent of the original uncertainty has been explained by the linear model
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Linearization of Nonlinear Relationships
Linear regression provides a powerful technique for fitting a best line to data. How about data shown below?
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Linearization of Nonlinear Relationships
Exponential equation Linearization of Nonlinear Relationships Transformations can be used to express the data in form that is compatible with linear regression A straight line with a slope 1 and intercept of ln 1 By natural logarithm
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Linearization of Nonlinear Relationships
Power equation A straight line with a slope 2 and intercept of log 2 By base-10 logarithm
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Linearization of Nonlinear Relationships
The saturation-growth-rate equation A straight line with a slope 3 / 3 and intercept of 1/3 By inverting
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Ex. 17.4 Fit Eq. below to the data in table 17.3 using a logarithmic transformation of the data.
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Ex. 17.4 Intercept of log 2 Slope of 1 Intercept data
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Polynomial Regression
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Polynomial Regression
This method can utilize the least-squares procedure to fit the data to a higher-order polynomial.
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Polynomial Regression
Derivation with respect to each unknown coefficients of polynomial as in
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Polynomial Regression
Derivations can be set equal to zero and rearranged as: How to solve it?
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Polynomial Regression
In matrix form What method can be used?
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Polynomial Regression
The two dimensional case can be easily extended to an m-th order polynomial as: The standard error for this case is formulated as
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Ex. 17.5 Fit a second-order polynomial to the data in table below:
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Ex. 17.5 Solution: m=2, n=6
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Ex. 17.5 Solution: The simultaneous linear equation are:
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Ex. 17.5 Solution: By using gauss elimination it will yield:
a0= , a1= and a2= The least-square quadratic equation:
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Ex. 17.5 The standard error:
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Ex. 17.5 The coefficient of determination:
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Ex. 17.5 99.851% of the original uncertainty has been explain by the model
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Assignment 3 Do Problems 17.5, 17.6, 17.7, 17.10 and 17.12
Submit next week
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Multiple Linear Regression
For this section, two-dimensional case, regression line become a plane
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Multiple Linear Regression
This method can utilize the least-squares procedure to fit the data to a higher-order polynomial.
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Multiple Linear Regression
Derivation with respect to each unknown coefficients of polynomial as in
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Multiple Linear Regression
Derivations can be set equal to zero and rearranged as in matrix form
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Multiple Linear Regression
The two dimensional case can be easily extended to an m-th order polynomial as: The standard error for this case is formulated as
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Ex. 17.6 The following data was calculated from equation: y=5+4x1-3x2
Use multiple linear regression to fit this data
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Ex. 17.6
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Ex. 17.6 Solution
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Ex. 17.6 solution a0=5, a1=4 and a2=-3
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Problems 17.17 Use multiple linear regression to fit.
Compute the coefficients, the standard error of estimate and the correlation coefficient
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Problems 17.17
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Problems 17.17 Solution
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Nonlinear Regression The Gauss-Newton method is one algorithm for minimizing the sum of the squares of the residuals between data and nonlinear equation. For convenience
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Nonlinear Regression The nonlinear model can be expanded in a Tailor series around the parameter values and curtailed after the first derivative Ex. For a two-parameter case:
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Nonlinear Regression It needs to be linearized by substituting into
It will yields
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Nonlinear Regression In matrix form
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Nonlinear Regression By applying least-square theory to
It will yield in normal equation: By using ave Eq. we can compute values for:
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Ex. 17.9
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