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Classical Mechanics Lecture 6
Today’s Concept: Friction
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Midterm Redux Seems like time is a big issue!!! Practice makes faster…
Average=18.6/20
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Friction
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Friction
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Friction
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Always opposes the relative motion of two surfaces
Friction Always opposes the relative motion of two surfaces
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Friction
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Static Friction
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Static Friction
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Static Friction
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Without Friction
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Friction
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Friction
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Friction
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Friction
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Friction
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Friction
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Friction
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Main Points
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Main Points
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Pre-lecture thoughts
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Microscopic explanation of Friction
What is Friction? Why can’t we walk through walls? Basically the same answer to both questions… Electron clouds of atoms repel (or bond to) each other
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Checkpoint A box sits on the horizontal bed of a moving truck. Static friction between the box and the truck keeps the box from sliding around as the truck drives. If the truck moves with constant acceleration to the left as shown, which of the following diagrams best describes the static frictional force acting on the box: S a A B C
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CheckPoint S a If the truck moves with constant accelerating to the left as shown, which of the following diagrams best describes the static frictional force acting on the box: 56% correct A B C A) In order to keep the box from sliding to the back of the truck as it accelerates, the frictional force needs to pull/push the box forward. B) Friction always opposes motion/acceleration.
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Clicker Question A box of mass M sits on a horizontal table. A horizontal string having tension T applies a force on the box, but static friction between the box and the table keeps the box from moving. What is the magnitude of the total force acting on the box? M f T A) Mg B) mMg C) T D) 0 Since acceleration is zero.
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Clicker Question A box of mass M sits on a horizontal table. A horizontal string having tension T applies a force on the box, but static friction between the box and the table keeps the box from moving. What is the magnitude of the static frictional force acting on the box? M f T A) Mg B) mMg C) T D) 0 Since the box is not moving the forces must be equal, otherwise there would be an acceleration. 38% correct
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CheckPoint 47% got this right on first try 36
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Checkpoint
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38% got this right on first try
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Checkpoint
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CheckPoint m2 m2 Case 1 g Case 2 g m1 m1
A block slides on a table pulled by a string attached to a hanging weight. In Case 1 the block slides without friction and in Case 2 there is kinetic friction between the sliding block and the table. m2 m2 Case 1 (No Friction) g Case 2 (With Friction) g m1 m1 In which case is the tension in the string biggest? A) Case B) Case C) Same 65% got this right on first try 40
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m2 m2 Case 1 (No Friction) g Case 2 (With Friction) g m1 m1 In which case is the tension in the string biggest? A) Case 1 B) Case 2 C) Same B) M1 will not be accelerating as fast in case two than in case one because there is the extra force of friction acting against mass 1. Since the acceleration is smaller in case two, there has to be more of a force acting against gravity, the only other possible force is Tension. 41
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Resume here
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Lets work it out A block (m2) slides on a table pulled by a string attached to a mass (m1) hanging over the side. The coefficient of kinetic friction between the sliding block and the table is mk. What is the tension in the string? m2 g m1 43
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Tension in String A block (m2) slides on a table pulled by a string attached to a mass (m1) hanging over the side. The coefficient of kinetic friction between the sliding block and the table is mk. What is the tension in the string? T1 m2 T2 g What is the relationship between the magnitude of the tension of the string at block 2 and the magnitude of the tension in the string at block 1? A) T1 > T2 B) T1 = T2 C) T1 < T2 m1 44
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Acceleration of coupled blocks
A block (m2) slides on a table pulled by a string attached to a mass (m1) hanging over the side. The coefficient of kinetic friction between the sliding block and the table is mk. What is the tension in the string? m2 g m1 What is the relationship between the magnitudes of the acceleration of the two blocks? A) a1 = a2 B) a1 < a2 C) a1 > a2 45
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m2 1) FBD N T m2 g f T m1 m1 m2g m1g 46
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m2 1) FBD 2) SF=ma N T m2 g f T m1 m1 m2g N = m2g m1g T – m m2g = m2a
m1g – T = m1a add m1g – m m2g = m1a + m2a m1g – m m2g a = m1 + m2 47
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T is smaller when a is bigger
1) FBD 2) SF=ma N T m2 g f T m1 m1 m2g m1g m1g – T = m1a m1g – m m2g T = m1g – m1a a = m1 + m2 T is smaller when a is bigger 48
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Accelerating Blocks
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Accelerating Blocks
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Carnival Ride
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Carnival Ride
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Accelerating Truck
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Accelerating Truck
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Mass on Incline
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Mass on Incline
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Mass on Incline
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Mass on Incline 2
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Mass on Incline 2
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Mass on Incline 2
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Mass on Incline 2
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Block
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Pushing Blocks
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