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Physics Subject Area Test WAVES LIGHT & OPTICS.

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Presentation on theme: "Physics Subject Area Test WAVES LIGHT & OPTICS."— Presentation transcript:

1 Physics Subject Area Test WAVES LIGHT & OPTICS

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3 Vibrations and Waves

4 Simple Harmonic Motion A restoring force is one that moves a system back to an equilibrium position. Example: mass on frictionless table, attached to spring.

5 Example: gravity acting on a mass hanging from a string. Example: gravity acting on a mass hanging from a spring. Hooke’s Law

6 When the restoring force is linearly proportional to the amount of the displacement from equilibrium, the force is said to be a Hooke’s Law force.

7 When oscillations are small, the motion is called simple harmonic motion (shm) and can be described by a simple sine curve.

8 Wavelength, , is the distance between two consecutive peaks.

9 Amplitude is the height of the wave above or below the equilibrium point.

10 The wave period, P, this the time it take one wave to pass the observer.

11 Frequency, f, is the number of waves passing a particular point in one second.

12 In symbolic form or

13 Waves transfer energy, not matter, from one place to another A Vibrating source transfers a disturbance Speed depends on type of vibrating source and medium through which it travels Wave speed = f x The same type of wave moves at the same speed regardless of f or For any wave, f is inversely proportional to

14 What does the period (T) depend upon? Length of the pendulum ( l ) Acceleration due to gravity ( g ). Period does not depend upon the bob mass or the amplitude of the swing. Vibration of a pendulum. The to-and- fro vibratory motion is also called oscillatory motion (or oscillation).

15 Transverse waves vibrate across from direction of travel Longitudinal waves vibrate along the direction of travel (as in a spring)

16 Molecules in the air vibrate about some average position creating the compressions and rarefactions. We call the frequency of sound the pitch.

17 When two wave pass each other their superposition causes reinforcement or cancellation.

18 * Speed of sound (in air, 0 ⁰ C, 1 atm) = 331 m/s

19 The standing sound wave in the column of air in a tube closed at one end must have a displacement node at the closed end and antinode at the open end Only odd multiples are possible λ 1 = 4L, λ 2 = 4/3L, λ 3 = 4/5L, λ 4 = 7/4L, … Eigenfrequencies: (f = v/ λ) f 1 = v/4L, f 2 = 3v/4L, f 3 = 5v/4L, …

20 eigenfrequencies

21 http://www.astro.sunysb.edu/mzingale/software/astro/doppler.avi A receiver will detect a higher frequency when the source is approaching, and a lower frequency when the source is moving away from the receiver. f’/ f = v’/v f’ = f (1 ± V R /v) Doppler shift, moving receiver

22 Suppose that a stationary siren emits a tone of frequency 440 Hz as the train moves away from it at 30.0m/s. What is the frequency received on the train? A motorboat speeding at 6.0 m/s is moving in the same direction as a group of water waves of frequency 0.62 Hz and speed 2.5 m/s (relative to the water). What is the frequency with which the wave crests pound on the motorboat? f’ = f (1 - V R /v) f’ = 440Hz (1 – 30 m/s/331 m/s)= 400Hz f’ = f (1 - V R /v) f’ = 0.62Hz (1 – 6.0m/s/2.5 m/s)= - 0.87Hz

23 * Lenses work because light slows down in media other than a vacuum. * The speed of light is given by: * n is the index of refraction

24 Substance n vacuum 1 air1.0003 water 1.3 glass 1.5 Index of refraction is unitless

25 * When light encounters a boundary between two media, some of the light is reflected and some is transmitted into the new medium. * If the light strikes the boundary at an angle, the transmitted light is refracted.

26 * Ray diagram: rays point perpendicular to the wavefront. Wave diagram: shows the crests of the traveling waves

27 1. All angles are measured from the normal. The normal is the line perpendicular to the surface at the point of reflection.

28 2. The reflected angle is equal to the incident angle.

29 3. Snell’s Law for refraction

30 * A ray of light strikes the surface of a beaker of hydrogen peroxide (n = 1.414) making a 30º angle with the surface normal. * What angle does the reflected ray make with the normal? * What angle does the transmitted ray make with the normal?

31 * a) The angle of the reflected ray is the same as the incident ray, 30º * b)

32 * The critical angle of incidence results in a transmitted ray that is parallel to the boundary surface.

33 * If the angle of incidence is greater than the critical angle, all the light is reflected and none is transmitted.

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35 * Converging lens: focuses parallel rays to a point a distance F from the lens * Diverging lens: causes parallel rays to diverge, as if emanating from a point source a distance F behind the lens

36 * d i =distance from lens to image * d 0 =distance from lens to object * f = focal length of lens

37 * f is positive for converging lens * f is negative for diverging lens * Negative d i is an image on the same side of the lens as the object * Positive d i is an image on the opposite side of the lens as the object

38 * If the light rays actually pass through the point they appear to come from, the image is real. * If the light rays are not actually coming from this position, the image is virtual.

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41 1. Draw the lens, the object (arrow), and both focuses (F).

42 2. Draw a ray from the top of the object to the lens. This ray will be parallel to the axis of the optical system until it strikes the lens. Then is bends to pass through the focus. (Red ray)

43 3. Draw a ray passing from top of the object through the center of the lens. (Blue ray)

44 4. Draw a ray from the top of the object through the near focal point. After the lens, this ray becomes parallel to the optical axis. (Green ray)

45 1. Draw the lens, object, and focal length on the same side as the object.

46 2. Draw a line from the top of the object to the lens, parallel to the optical axis. After the lens, draw the line as if it had come from the near focus. (Red ray)

47 3. Draw ray from the top of the object towards the far focus. After the lens, this ray become parallel to the optical axis. (Green ray)

48 4. Draw a ray from the top of the image through the center of the lens. (Blue ray)

49 * The angle of reflection is equal to the angle of incidence, measured with respect to the normal.

50 * The thin lens equation we used before can also be applied to mirrors. * In the case of mirrors, a positive d i means the image is on the same side of the mirror as the object. * This sign convention is opposite that used for lenses.

51 * The focal point of a plane mirror is at infinity. * The image formed by a plane mirror is virtual and upright. * To trace rays reflecting off a plane mirror, just use law of reflection.

52 * The image distance and object distance are the same for a plane mirror.

53 * A spherical mirror is a section of a sphere. * If the outside surface of the sphere is reflecting, the mirror is convex. * If the inside surface is reflecting, the mirror is concave.

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55 * 1. Draw ray from top of object to the curved mirror. After reflecting off mirror, the ray passes through the focal point. (Blue ray)

56 * 2. Draw a ray from the top of the object through the focal point. The ray will be parallel to the optical axis after reflecting. (Green)

57 The rays do not intersect, so we must extend them, resulting in a virtual image.

58 1. Draw ray parallel to optical axis. After reflection, this ray travels as if it is coming from the far focus. (Blue ray)

59 2. Draw line from top of object to focus. At the mirror, the ray becomes parallel to the optical axis. (Green ray)


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