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12.3 Surface Area of Circular Solids

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Presentation on theme: "12.3 Surface Area of Circular Solids"— Presentation transcript:

1 12.3 Surface Area of Circular Solids
cylinder cone sphere

2 Cylinder: base is a circle
Contains 2 congruent parallel bases. Right circular cylinder perpendicular line from center to each base. Net: h r

3 Net: T113: LAcyl = Ch C = circumference h= height Lateral area: A = bh b = circumference (2πr or πd) h b h r

4 Total area: TA = 2(πr2) + 2πrh
Lateral area: A = bh b = circumference (2πr or πd) Net: b h h r

5 Find the surface area of the following cylinder:
7cm TA = 2(πr2) + 2πrh 10cm

6 l Cone: base is a circle Slant height and lateral height are the same. l = slant height Cone will mean a right cone where the altitude passes through the center of the circular base.

7 l = slant height T114: LA = ½ Cl = πrl Net: C = circumference
r = radius

8 Find the surface area of the cone.
The diameter is 10 The slant height is 6 TA = LA + Abase = πr2 + πrl

9 Sphere: special surface area formula.
NO lateral edges No lateral area Proof will come later – requires limits. Postulate: TA = 4πr2 Radius of the sphere!

10 Find the total surface area of the following shape
Find the total surface area of the following shape. Hint: just what you see!


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