2. Kinematics Physics of Motion

9. kinematics Kinematics is the science of describing the motion of objects using words, diagrams, numbers, graphs, and equations.

10. Speed How fast something moves Distance/time Miles PER hour Meters PER second

11. Fast Thinking 1. Which of the following represents a speed? a. 6 m b. 4 hr/km sec c. 2 m/sec 2 d. 8 m/sec

12. Velocity Speed plus a direction Example: 10 m/s heading north east 4 m/s heading vertically

13. Vector Quantities Properties that have magnitude (size) and direction Example: velocity

14. Scalar quantities Properties that only have magnitude Examples: Speed Temperature

15. definitions 1. A ________________ quantity is completely described by its magnitude. 2. A _________________ quantity has both magnitude and direction. 3. The velocity of an object at any given instant in time is known as the _________________ velocity. 4. The rate at which the velocity changes is known as the __________________.

16. Acceleration Rate of change of velocity Vector Can be + or – Speeding up or slowing down Slowing is – acceleration or deceleration (celer = latin for speed) m/s/s meters per second per second (m/s 2 )

17. Acceleration due to gravity (g) g = 9.8m/s/s You can round it up to 10 m/s/s In freefall, every second you are travelling 10m/s more than the previous second

18. On your marks…get set…go! 2. Which of the following represents an acceleration? a. 16 m2/sec 2 b. 4 hr/km sec c. 8 km/hr d. 2 m/s 2

19. Displacement Defined as NET distance traveled. (you can walk to school 3miles, walk home 3miles…you have traveled 6 miles, but your displacement is zero Vector Compare to “distance” a scalar quantity

20. I WALK THE LINE… A. Johnny Cash walks 150 meters due east and then turns around and walks 30 meters due west. He walked a distance of a. 30 meters b.150 meters c. 120 meters d. 180 meters

21. B. 4. Johnny’s displacement is a. 30 meters east b.150 meters east c. 120 meters east d. 180 meters west

22. The velocity of this car is constantly changing direction… Therefore it is continually accelerating

23. Describing motion with diagrams

24. The distance between dots on a ticker tape represents the object's position change during that time interval. A large distance between dots indicates that the object was moving fast during that time interval. A small distance between dots means the object was moving slow during that time interval.

27. For the following tickertapes Describe the motion occuring

29. Vector diagrams Arrows represent direction and magnitude of velocity

30. Using graphs to describe motion Position / time graph The Meaning of Shape for a p-t Graph Look at the following graphs…

31. Car moving to the right with constant velocity of +10m/s

33. Now consider a car moving with a rightward (+), changing velocity - that is, a car that is moving rightward but speeding up or accelerating.

35. Positive Velocity Changing Velocity (acceleration)

36. Constant Velocity Positive Velocity

37. The Importance of Slope the slope of the line on a position-time graph reveals useful information about the velocity of the object. If the velocity is constant, then the slope is constant (i.e., a straight line). If the velocity is changing, then the slope is changing (i.e., a curved line). If the velocity is positive, then the slope is positive (i.e., moving upwards and to the right).

38. Slow, Rightward (+) Constant Velocity Fast, Rightward (+) Constant Velocity

39. Slow, Leftward (-) Constant Velocity Fast, Leftward (-) Constant Velocity

40. If the slope is changing (curve) Then velocity is changing Therefore the object is accelerating Slope going up? = moving right Going down? = moving left

41. Leftward (-) Velocity; Slow to Fast Leftward (-) Velocity Fast to Slow

42. What is happening?

43. A. The object has a positive or rightward velocity (note the + slope). The object has a changing velocity (note the changing slope); it is accelerating. The object is moving from slow to fast (since the slope changes from small big). B.The object has a negative or leftward velocity (note the - slope). The object has a changing velocity (note the changing slope); it has an acceleration. The object is moving from slow to fast (since the slope changes from small to big).

44. Meaning of Slope on a position-time graph consider a car moving at a constant velocity of +5 m/s for 5 seconds, abruptly stopping, and then remaining at rest (v = 0 m/s) for 5 seconds.

46. the slope of the line on a position- time graph is equal to the velocity of the object. If the object is moving with a velocity of +4 m/s, then the slope of the line will be +4 m/s. If the object is moving with a velocity of -8 m/s, then the slope of the line will be - 8 m/s. If the object has a velocity of 0 m/s, then the slope of the line will be 0 m/s.

47. How to calculate slope Slope = rise/run Pick two points on the line and determine their coordinates. Determine the difference in y-coordinates of these two points (rise). Determine the difference in x-coordinates for these two points (run). Divide the difference in y-coordinates by the difference in x-coordinates (rise/run or slope).

48. EASY!!

49. More difficult…determine the velocity of this object

50. Slope = -3.0 m/s Using the two given data points, the rise can be calculated as -24.0 m (the - sign indicates a drop). The run can be calculated as 8.0 seconds. Thus, the slope is -3.0 m/s.

51. The Meaning of Shape for a velocity-time Graph Consider a car moving with a constant, rightward (+) velocity of +10 m/s. a car moving with a constant velocity is a car with zero acceleration.

52. constant, positive velocity results in a line of zero slope (a horizontal line has zero slope) when plotted as a velocity- time graph

53. Now consider a car moving with a rightward (+), changing velocity - that is, a car that is moving rightward but speeding up or accelerating. Since the car is moving in the positive direction and speeding up, the car is said to have a positive acceleration. accelerating positive acceleration

54. Note that a motion described as a changing, positive velocity results in a sloped line when plotted as a velocity-time graph. The slope of the line is positive, corresponding to the positive acceleration.

55. Positive Velocity Zero Acceleration Positive Velocity Positive Acceleration

56. the slope of the line on a velocity- time graph reveals useful information about the acceleration of the object. If the acceleration is zero, then the slope is zero (i.e., a horizontal line). If the acceleration is positive, then the slope is positive (i.e., an upward sloping line). If the acceleration is negative, then the slope is negative (i.e., a downward sloping line).

57. velocity is positive whenever the line lies in the positive region (above the x-axis) of the graph. Velocity is negative whenever the line lies in the negative region (below the x-axis) of the graph. A positive velocity means the object is moving in the positive direction; and a negative velocity means the object is moving in the negative direction. (regardless if it is sloping up or sloping down). Finally, if a line crosses over the x-axis from the positive region to the negative region of the graph (or vice versa), then the object has changed directions.

59. Slowing down?/Speeding up? if the line is moving away from the x-axis (the 0-velocity point), then the object is speeding up. If the line is moving towards the x-axis, then the object is slowing down.

61. Check Your Understanding 1. Consider the graph at the right. The object whose motion is represented by this graph is... (include all that are true): a.moving in the positive direction. b.moving with a constant velocity. c.moving with a negative velocity. d.slowing down. e.changing directions. f.speeding up. g.moving with a positive acceleration. h.moving with a constant acceleration.

62. Answers: a, d and h apply. a: TRUE since the line is in the + region. b. FALSE since there is an acceleration (changing vel.) c. FALSE since a - vel. would be a line in the - region. d. TRUE since the line is approaching the 0-vel. point. e. FALSE since the line never crosses the axis. f. FALSE since the line is not moving away from x- axis g. FALSE since the line has - or downward slope. h. TRUE since the line is straight (has constant slope)

63. Time (s) Velocity (m/s) 010 1 2 3 4 5 Meaning of slope on V-T graph

64. Changing velocity = acceleration Time (s) Velocity (m/s) 00 110 220 330 440 550

65. What is happening here?

66. in the first four seconds, the car is not changing its velocity (the velocity remains at 2 m/s) and then the car increases its velocity by 2 m/s per second over the next four seconds

67. Check Your Understanding The velocity-time graph for a two-stage rocket is shown below. Use the graph and your understanding of slope calculations to determine the acceleration of the rocket during the listed time intervals. t = 0 - 1 second t = 1 - 4 second t = 4 - 12 second

68. answers A. The acceleration is +40 m/s/s. The acceleration is found from a slope calculation. The line rises +40 m/s for every 1 second of run.

69. B. The acceleration is +20 m/s/s. The acceleration is found from a slope calculation. The line rises +60 m/s for 3 seconds of run. The rise/run ratio is +20 m/s/s. C. The acceleration is -20 m/s/s. The acceleration is found from a slope calculation. The line rises -160 m/s for 8 seconds of run. The rise/run ratio is -20 m/s/s.

70. Relating the Shape of V-T graphs to the Motion

76. What’s happening?

77. The object moves in the + direction at a constant speed - zero acceleration (interval A). The object then continues in the + direction while slowing down with a negative acceleration (interval B). Finally, the object moves at a constant speed in the + direction, slower than before (interval C).

79. The object moves in the + direction while slowing down - a negative acceleration (interval A). It then remains at rest (interval B). The object then moves in the - direction while speeding up - a negative acceleration (interval C).

81. The object moves in the + direction with a constant velocity and zero acceleration (interval A). The object then slows down while moving in the + direction - a neg. acceleration until it finally reaches a 0 velocity (stops) (interval B). Then the object moves in the - direction while speeding up - a neg. acceleration (interval C).

82. Area under graph=displacement For velocity vs. time graphs, the area bound by the line and the axes represents the distance.

83. Area = b * h Area = (6 s) * (30 m/s) Area = 180 m

84. Area = 0.5 * b * h Area = (0.5) * (4 s) * (40 m/s) Area = 80 m

85. Area = 0.5 * b * (h1 + h2) Area = (0.5) * (2 s) * (10 m/s + 30 m/s) Area = 40 m

86. In a velocity – time graph…the area under the graph represents…

87. What is this object doing?

88. Moving with constant acceleration - velocity increasing at a steady rate from rest (0) example: car accelerating from 0 to 60 mph - typical car test trial

89. Look at this velocity time graph. What do you think it might show? Hint: Think about what the graph is telling you. What is happening to the velocity? Is the acceleration constant? What happens to the velocity when the line crosses the X axis?

90. The graph shows the motion of a ball thrown upwards! The graph is a straight line, starting at a high velocity and decreasing until velocity is zero - this occurs when the line crosses the X-axis of the graph. The line continues - with the same gradient. This indicates that the acceleration remains constant. However, the line is now below the X-axis so the velocity is now increasing - and negative. This tells us that the direction of motion has reversed.

91. Think about This Clue…

92. ...now think about this Look at this velocity time graph. What do you think it might show? Hint: Think about what the graph is telling you. What is happening to the velocity? Is the velocity constant? What might be happening when the velocity switches from + to -?

93. This graph might show the motion of a tennis ball as it is knocked backwards and forwards across the net! The graph has some straight sections, showing that the moving object travels at a constant velocity for some time. The graph then rapidly switches from + to - and from - to +. This rapid switching suggests a very fast change of direction - in fact so fast that the time scale cannot display any detail!

94. Ok…now what…? A car already going fast decides to accelerate from 60 kph to 90 kph

95. Constantly changing velocity equals…? Accelerating example: rocket accelerating away from lift off - constant thrust but burning fuel means that rocket weighs less - so accelerates at a greater rate

97. Starts off fast… Moving with constant negative acceleration - velocity decreasing at a steady rate example: car braking from 60 mph to rest

98. EASY PEASY …THINK VIN DEISEL IN THAT awful STREET RACING MOVIE… Car accelerates from rest, travels with a constant velocity, accelerates to overtake then drops back to the steady velocity before braking to a halt

99. freefall Free-falling objects do not encounter air resistance. All free-falling objects (on Earth) accelerate downwards at a rate of approximately 10 m/s/s (to be exact, 9.8 m/s/s)

100. For an object in freefall… What is the formula for velocity? What is the formula for how far it travels? So…if this dude falls for 10 seconds how fast is he going? How far has he fallen? V=gt D=5t 2