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Published byKathryn Hoover Modified over 9 years ago
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The graph is a hoirzontal line. Velocity is zero.
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The slope > 0 (positive). The object is moving towards the end position
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The slope <0 (negative). The object is moving towards the start position
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Speed or velocity is at middle instant of the time interval.
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Constructing Speed time graph or velocity time graph
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Construct from a distance-time graph (or a displacement-time graph)
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Displacement and v-t graph The following slides show you the relationship between displacement (S) and the v-t graph (velocity-time graph)
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Area = 0.6 x (0.2- 0.1) Area = speed x time = distance Graph area under the graph? area under the graph from t = 0.1s to 0.2s is the distance travelled during t=0.1s to 0.2s
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V1V1 Displacement travelled by the object from time t 1 to t 2 = area A
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The area under v-t graph V/ms -1 t/s v2v2 v1v1 t2t2 t1t1 Displacement due to v 1 from t 1 to t 2 Displacement due to the increase of velocity from v 1 to v 2 from t 1 to t 2
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c is the y-intercept, c = 0. Slope m= a. The equation isv =at y = mx
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‘at’ or ‘v’ t S = area
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ymxc
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u ut at t 1/2 (a t 2 ) u v t S=(u+v)t/2
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no s v a t
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u,v,a& scan be ‘+’ or ‘-’ depend on direction
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v = - 4ms -1 Case 1 u = 1ms -1 v = 4ms -1 t = 3s a = ? Case 2 ‘+’direction u = 1ms -1 t = 5s
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