Download presentation
Presentation is loading. Please wait.
1
GRAPHICAL ANALYSIS OF MOTION
Chapter 2.3 GRAPHICAL ANALYSIS OF MOTION 1
2
Describe the following motion
3
from the graph to an actual motion and
In Kinematic, when you work on a graph analysis problem you must translate: from the graph to an actual motion and from an actual motion to its representation on a graph. 3
4
Objective Solve “slope of a curve” with unit a graph.
Identify direction of motion from a graph Transfer a position vs. time graph to velocity vs. time graph. Solve “area under a curve” with right unit Solve displacement and distance from speed vs. time graph. 4
5
Example: a line drawn at 45° always has a slope of 1 (no units),
“slope of a curve” Students don’t recognize that a slope has units or how to determine those units. Example: a line drawn at 45° always has a slope of 1 (no units), Position vs. time graph, slope is a velocity and unit is [m/s] 5
6
When the velocity is constant, the average velocity is equal to the instantaneous velocity at any time. 6
7
a. x Object starts at the origin and moves in the positive direction with constant velocity. t Object starts to the right of the origin and moves in the negative direction with constant velocity ending at the origin. x b. t 7
8
Object moving to the right at a fast constant speed.
A qualitative description of the motion depicted in the following v-versus-t graphs: a. v Object moving to the right at a fast constant speed. t b. v Object moving to the left at a slow constant speed. t
9
Object starts to the right of
x Object starts to the right of the origin and moves in the positive direction with constant velocity. t x d. Object starts to the left of the origin and moves in the positive direction with constant velocity ending at the origin. t 9
10
Object starts to the left of the origin and moves in
x Object starts to the left of the origin and moves in the negative direction with constant velocity. t x f. Object starts to the right of the origin and moves in the negative direction with constant velocity. t 10
11
v t Object starts at R of origin. Moves R at constant v, stands still then moves L at faster constant v.
12
Object moves L at constant v, then
x t Object moves L at constant v, then moves R at constant v but slower, then stands still. 12
13
• Students don’t recognize that an “area under the curve”
Area under a curve • Students don’t recognize that an “area under the curve” has units or how the units of an “area” can be something other than area units. The area under the v-versus-t curve is displacement. But distance is a length? How can a length equal an area? 13
14
The students should be able to calculate the area under the v-t curve and understand that the value obtained is the displacement 14
15
Object starts at R of origin. Moves L at constant v, stands still then
moves L again at constant v but faster. 15
16
then moves L at constant v but slower.
x v t Object is at rest. Moves R at constant v, then moves L at constant v but slower. 16
17
Practice: find displacement
18
Practice: find displacement
19
INTERPRETING GRAPHS Give a qualitative description of the motion at the different time intervals. v (m/s) t (s)
20
INTERPRETING GRAPHS Give a qualitative description of the motion at the different time intervals. Stops, Resting, speeding up + direction Slowing down + direction, speeding up - direction, Slowing down - direction, Constant speed + direction, constant speed - direction v (m/s) t (s)
21
Motion diagram and Position vs, Time graph
Look at the following motion diagram Transfer this motion into position vs. time graph. What is mathematical equation of this graph?
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.