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GRAPHICAL ANALYSIS OF MOTION

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1 GRAPHICAL ANALYSIS OF MOTION
Chapter 2.3 GRAPHICAL ANALYSIS OF MOTION 1

2 Describe the following motion

3 from the graph to an actual motion and
In Kinematic, when you work on a graph analysis problem you must translate: from the graph to an actual motion and from an actual motion to its representation on a graph. 3

4 Objective Solve “slope of a curve” with unit a graph.
Identify direction of motion from a graph Transfer a position vs. time graph to velocity vs. time graph. Solve “area under a curve” with right unit Solve displacement and distance from speed vs. time graph. 4

5 Example: a line drawn at 45° always has a slope of 1 (no units),
 “slope of a curve” Students don’t recognize that a slope has units or how to determine those units. Example: a line drawn at 45° always has a slope of 1 (no units), Position vs. time graph, slope is a velocity and unit is [m/s] 5

6 When the velocity is constant, the average velocity is equal to the instantaneous velocity at any time. 6

7 a. x Object starts at the origin and moves in the positive direction with constant velocity. t Object starts to the right of the origin and moves in the negative direction with constant velocity ending at the origin. x b. t 7

8 Object moving to the right at a fast constant speed.
A qualitative description of the motion depicted in the following v-versus-t graphs: a. v Object moving to the right at a fast constant speed. t b. v Object moving to the left at a slow constant speed. t

9 Object starts to the right of
x Object starts to the right of the origin and moves in the positive direction with constant velocity. t x d. Object starts to the left of the origin and moves in the positive direction with constant velocity ending at the origin. t 9

10 Object starts to the left of the origin and moves in
x Object starts to the left of the origin and moves in the negative direction with constant velocity. t x f. Object starts to the right of the origin and moves in the negative direction with constant velocity. t 10

11 v t Object starts at R of origin. Moves R at constant v, stands still then moves L at faster constant v.

12 Object moves L at constant v, then
x t Object moves L at constant v, then moves R at constant v but slower, then stands still. 12

13 • Students don’t recognize that an “area under the curve”
Area under a curve • Students don’t recognize that an “area under the curve” has units or how the units of an “area” can be something other than area units. The area under the v-versus-t curve is displacement. But distance is a length? How can a length equal an area? 13

14 The students should be able to calculate the area under the v-t curve and understand that the value obtained is the displacement 14

15 Object starts at R of origin. Moves L at constant v, stands still then
moves L again at constant v but faster. 15

16 then moves L at constant v but slower.
x v t Object is at rest. Moves R at constant v, then moves L at constant v but slower. 16

17 Practice: find displacement

18 Practice: find displacement

19 INTERPRETING GRAPHS Give a qualitative description of the motion at the different time intervals. v (m/s) t (s)

20 INTERPRETING GRAPHS Give a qualitative description of the motion at the different time intervals. Stops, Resting, speeding up + direction Slowing down + direction, speeding up - direction, Slowing down - direction, Constant speed + direction, constant speed - direction v (m/s) t (s)

21 Motion diagram and Position vs, Time graph
Look at the following motion diagram Transfer this motion into position vs. time graph. What is mathematical equation of this graph?


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