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Kinematics Equations
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IB Motion Graph Review
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Distance/Position/Displacement Time Graphs Constant vel.
Starting point Slope = Velocity Slower Velocity
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Positive Negative Quadrants Where object is w/ref to starting point.
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What is the object’s: a. displacement distance 10 30
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Constant Velocity/Speed
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Constant / Uniform Acceleration. On velocity time graph accl
Constant / Uniform Acceleration. On velocity time graph accl. is slope of straight line. + or neg a shown?
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What’s going on here physically?
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Sign of velocity is direction of motion shown by the quadrant.
What does this show?
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What does -v mean?
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What does the sign of slope mean?
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Displacement = Area Under Curve v = d/t then, vt = d.
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To find displacement, calc area of triangle + rectangle.
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When is object back at start point?
+ area must = - area
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Acceleration – time graphs
Graph d-t, v-t, a-t tossed ball & caught at same height.
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Kerr pg 39 #1 & pg 71 Topic 2.1 #1-4.
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