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What is DC Electricity. Chapter 2. Resistance The property of a material to inhibit the flow of current.

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Presentation on theme: "What is DC Electricity. Chapter 2. Resistance The property of a material to inhibit the flow of current."— Presentation transcript:

1 What is DC Electricity. Chapter 2

2 Resistance The property of a material to inhibit the flow of current.

3 Resistor

4 Resistor Molded Carbon Composite

5 Resistor Wirewound Film Molded Carbon Composite

6 Wire wound

7 Film Surface Mount Technology SMT

8 Resistivity A L

9 Resistivity: Example A 1m long piece of gold has a cross sectional area of 0.1cm 2. The resistivity of gold at 20°C is 2.24 X 10 -8 ohm-meters.ρ ρ =2.24 X 10 -8 ohm-meters A = 0.1cm 2 L = 1m

10 Resistivity: Gold ρ =2.24 X 10 -8 ohm-meters A = 0.1cm 2 L = 1m R = ρL A R = (2.24 X 10 -8 Ώ-m)(1m) 0.00001m 2 R =0.00224 Ώ

11 Resistivity: Carbon ρ =50 X 10 -5 ohm-meters A = 0.1cm 2 L = 1m R = ρL A R = (50 X 10 -5 Ώ-m)(1m) 0.00001m 2 R =50 Ώ

12 Resistor Color Code 0 1 2 3 4 5 6 7 8 9

13 Tolerance 5% The measure of how good a component is. How close it is to the actual value. 10% 20% GoldSilverNo Band

14 Tolerance 100Ω 5%: 95-105Ω 10%: 90-110Ω 20%: 80-120Ω

15 } Digits 36 Multiplier 00000 Tolerance 5 % R =3600000 Ώ or 3.6M Ώ

16 } Digits 47 Multiplier Tolerance 20 % R =36 Ώ

17 Voltage Sources Voltage sources added in Series increase the Voltage and the Current stays the same. V = 1.5v I = 1A V = 4.5v I = 1A

18 Voltage Sources Voltage sources added in Parallel increase the Current and the Voltage stays the same. V = 1.5v I = 1A V = 1.5v I = 3A

19 Exampl e Exampl e Battery: V = 1.5v, I = 1A V=3v I= 3A V=3v I=1A

20 Ohm’s Law The Current(I) in a circuit is directly proportional to the Voltage(E,V) and inversely proportional to the Resistance(R). I = ERER

21 Ohm’s Law RI E Find: E E = I x R

22 Ohm’s Law RI E Find: R R = E/I

23 Ohm’s Law RI E Find: I I = E/R

24 Ohm’s Law Units RΩRΩ IAIA EvEv

25 RkΩRkΩ ImAImA E (v)

26 Ohm’s Law Units RMΩRMΩ IμAIμA E (v)

27 Ohm’s Law Example RΩRΩ IAIA EvEv R=2Ω, E=12v Find: I I = E/R =12v/2Ω I = 6A

28 Ohm’s Law Example RkΩRkΩ I mA EvEv E=120, I=60mA Find: R R = E/I =120v/60mA R = 2kΩ

29 Ohm’s Law Example RkΩRkΩ I mA EvEv R=10kΩ, I=12mA Find: E E = I x R =12mA x 10kΩ I = 120v

30 Wheel of Answers RΩRΩ IAIA EvEv R kΩ I mA EvEv


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