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Math 96A Test 1 Flash Cards
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Math 96 Test 1 Real numbers & properties
Solve equations & inequalities Absolute Value equations & inequalities Translation word problems Exponent Rules Graph linear functions Find equation of a line
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Classify the given numbers.
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Classify the given numbers.
Natural: 1, 2, 3, 4, … also will be whole, integer, rational and real Whole: 0, 1, 2, 3, … also will be integer, rational and real Integer: … , -2, -1, 0, 1, 2, … also will be rational and real Rational: can be written as a fraction – decimals with repeating or terminating decimals Irrational: decimals with no repeating patterns and they go forever Real: all the above numbers are real numbers – so far everything you know is a real number!
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Classify the given numbers.
-2 .4545… Natural Numbers Whole Numbers Integers Rational Number Irrational Numbers Real Numbers
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Classify the given numbers.
-2 .4545… Natural Numbers Whole Numbers X Integers X Rational Number X Irrational Numbers Real Numbers
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Name the properties of Real numbers.
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Name the properties of Real numbers.
Associative: something new inside the parentheses – add and multiply Commutative: something has moved its location – add and multiply Distributive: multiply on the outside, adding in the inside Identities: “it” will not change – add by zero OR multiply by 1 Inverses: will make “it” go away – add the opposite OR multiply by the reciprocal
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Name the properties of Real numbers.
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Name the properties of Real numbers.
Multiplication Property of ZERO: if you multiply BY zero you get zero! Multiplication Property of ZERO: a (0) = 0 Closure: you get an answer! a + b = c Trichotomy Property: 1 of 3 things must be true a < b or a = b or a > b Transitive Property: if a < b and b < c then a < c
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Name the properties of Real numbers.
4 • 0 = 0
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Name the properties of Real numbers.
4 • 0 = 0 The Zero Product Property
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Solve each equation for x.
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Solve each equation for x.
Step 1. identify the variable you are solving for and clear parentheses Step 2. clear fractions (multiply by the LCM) and/or clear decimals (multiply by 10s) Step 3. get just 1 variable Step 4. get the variable alone, furthest first – according to the reverse Order of Operations
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Solve each equation for x.
5[2 – (2x – 4)] = 2(5 – 3x)
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Solve each equation for x.
5[2 – (2x – 4)] = 2(5 – 3x) 5[2 – 2x + 4] = 2(5 – 3x) 5[– 2x + 6] = 2(5 – 3x) -10x + 30 = 10 – 6x -4x + 30 = 10 -4x = -20 x = 5
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Solve each equation for x.
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Solve each equation for x.
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Graph the following Inequalities
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Graph the following Inequalities
Greater than and Less than – open circle Greater than or equal to and Less than or equal to – closed circle If x comes first – go the same way as the inequality Space numbers evenly on the number line, one variable – one line
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Graph the following inequality
x > -2
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Graph the following inequality
x > -2
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Solve Inequalities for x, and graph your solution.
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Solve Inequalities for x, and graph your solution.
IF you multiply (or divide) by a negative, the inequality will change direction. Follow the rules for graphing inequalities.
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Solve this inequality for x, and graph your solution
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Solve this inequality for x, and graph your solution
Multiplied by a Negative
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Solve for the indicated variable.
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Solve for the indicated variable.
Step 1. identify the variable you are solving for and clear parentheses Step 2. clear fractions (multiply by the LCM) and/or clear decimals (multiply by 10s) Step 3. get just 1 variable, factor if needed Step 4. get the variable alone, furthest first – according to the reverse order of operations
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Solve for the indicated variable.
W = ab + ah; solve for a
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Solve for the indicated variable.
W = ab + ah; solve for a Too many a’s – factor! W = a (b + h) W = a(b + h) (b + h) (b + h)
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Solve the following equations containing Absolute Value bars.
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Solve the following equations containing Absolute Value bars.
Make sure you FIRST isolate the absolute value bars 2 Bars – 2 Problems – what can go into the bars and come out as desired? Special case: | x | = negative No Solution
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Solve the following equation containing Absolute Value bars.
| 2x – 1 | = 8
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Solve the following equation containing Absolute Value bars.
| 2x – 1 | = 8 | 2x – 1 | = 3 2x – 1 = 3 2x – 1 = -3 2x = 4 x = 2 2x = -2 x = -1
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Solve each of the Absolute Value Inequalities and graph.
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Solve each of the Absolute Value Inequalities and graph.
Make sure you FIRST isolate the absolute value bars 2 Bars – 2 Problems – what can go into the bars and come out as desired? Special cases: | x | < negative | x | > negative No Solution all real numbers
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Solve the Absolute Value Inequality and graph.
| 4 – 2x | + 5 > 3
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Solve the Absolute Value Inequality and graph.
| 4 – 2x | + 5 > 3 | 4 – 2x | > -2 Always True, Absolute Value is greater than a Negative
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Translate these words and write an equation then solve it.
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Translate these words and write an equation then solve it.
Read the whole problem all the way through at least once. Write what you read as you read it Sum – (add inside parentheses ) Total – (add inside parentheses ) Difference – (subtract inside parentheses) Less than – write subtraction “backwards” Subtracted from – write subtraction backwards
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Translate these words and write an equation then solve it.
Five times the difference between three and twice a number is negative five.
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Translate these words and write an equation then solve it.
Five times the difference between three and twice a number is negative five. 5(3 – 2n) = -5 15 – 10n = -5 -10n = -20 n = 2 The number is two! End in Words!
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Simplify the given expression. Do not leave negative exponents.
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Simplify the given expression. Do not leave negative exponents.
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Simplify the given expression. Do not leave negative exponents.
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Simplify the given expression. Do not leave negative exponents.
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Simplify the given expression. Do not leave negative exponents.
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Simplify the given expression. Do not leave negative exponents.
Clear outside exponents first, move the “location” of the base that has a negative exponent the base still has an exponent, but now it is positive.
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Simplify the given expression. Do not leave negative exponents.
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Simplify the given expression. Do not leave negative exponents.
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Simplify the given expression. Do not leave negative exponents.
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Simplify the given expression. Do not leave negative exponents.
Clear outside exponents first, make sure all parenthesis are “gone” before “moving” bases. The base is only what the exponent touches.
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Simplify the given expression. Do not leave negative exponents.
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Simplify the given expression. Do not leave negative exponents.
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Graph by Plotting Points
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Graph by Plotting Points
Use my favorite numbers -2, -1, 0, 1, 2 Replace x with the value you have in the table and find the value of y. (x, y) a point is an ordered pair of numbers First number, go along the x-axis Second number, go in the y-axis direction
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Graph by Plotting Points
y = ½ x – 5
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Graph by Plotting Points
y = ½ x – 5 (-2, ) y = ½ (-2) – 5 y = -6 (-2, -6) (4, ) y = ½ (4) – 5 y = -3 (4, -3)
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Graph by Intercepts
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Graph by Intercepts Let x = 0 to find the y-intercept, the point on the y-axis. Let y = 0 to find the x-intercept, the point on the x-axis.
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Graph by Intercepts 2x – 4y = -8
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Graph by Intercepts 2x – 4y = -8 2(0) – 4y = -8 -4y = -8 y = 2 (0, 2)
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Graph by using Slope-Intercept form
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Graph by using Slope-Intercept form
Solve for y: y = mx + b b = y-intercept, start on y-axis from the “starting” point, go up and over
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Graph by using Slope-Intercept form
3x – 2y = 4
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Graph by using Slope-Intercept form
3x – 2y = 4 -3x x -2y = -3x + 4 (-½)(-2y) = (-½)(-3x + 4) y = 3/2 x – 2
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Graph the corresponding line on the Cartesian coordinate system.
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Graph the corresponding line on the Cartesian coordinate system.
Plot points, using an x-y table Graph using intercepts, two separate points (x, 0) and (0, y) Solve for y, graph using the slope-intercept form. Start on the y-axis, go up/down and then over.
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Graph by using any method
y = -2x + 3
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Graph by using any method
y = -2x + 3
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Find an equation for the line that satisfies the given conditions.
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Find an equation for the line that satisfies the given conditions.
Equation of a line: y = mx + b Point (x, y) Given two points stack & subtract to find slope m in y = mx + b, replace x, y, and m - to find b
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Find an equation for the line that satisfies the given conditions.
Find the equation of the line containing the two points (-3, 4) and (2, 1)
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Find an equation for the line that satisfies the given conditions.
Find the equation of the line containing the two points (-3, 4) and (2, 1) y – y1 = m(x – x1) y – 1 = -3/5(x – 2) clear the parentheses y – 1 = -3/5x + 6/5 clear the fraction, multiply by 5 5(y – 1) = -3x + 6 Simplify 5y – 5 = -3x + 6 get all the variables on 1 side 3x + 5y = 11 and the constants on the other side
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Find an equation for the line that satisfies the given conditions.
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Find an equation for the line that satisfies the given conditions.
Parallel lines have the same slope Perpendicular lines have opposite & reciprocal slope Given an equation: Ax + By = C Solve for y to find m parallel use m perpendicular use - 1/m use the given point (x, y) y = mx + b: replace x, y, and m to find b
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Find an equation for the line that satisfies the given conditions.
Perpendicular to 3x – y = 4 and passes through the point (-3,6).
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Find an equation for the line that satisfies the given conditions.
Perpendicular to 3x – y = 4 and passes through the point (-3,6). Solve the equation for y – find the slope -y = -3x + 4 y = 3x – 4 m = 3 use for perpendicular line m = -1/3 6 = (-1/3)(-3) + b 5 = b Equation: y = -1/3 x + 5
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