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STANDARDS OF THE WEEKLY LESSON 3.1.10.C.Apply patterns as repeated processes or recurring elements in science and technology. D. Apply scale as a way of.

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Presentation on theme: "STANDARDS OF THE WEEKLY LESSON 3.1.10.C.Apply patterns as repeated processes or recurring elements in science and technology. D. Apply scale as a way of."— Presentation transcript:

1 STANDARDS OF THE WEEKLY LESSON 3.1.10.C.Apply patterns as repeated processes or recurring elements in science and technology. D. Apply scale as a way of relating concepts and ideas to one another by some measure. E. Describe patterns of change in nature, physical and man made systems. 3.2.10.A. Apply knowledge and understanding about the nature of scientific and technological knowledge. B. Apply process knowledge and organize scientific and technological phenomena in varied ways. C. Apply the elements of scientific inquiry to solve problems. 3.4.10.C. Distinguish among the principles of force and motion. 3.7.10.AIdentify and safely use a variety of tools, basic machines, materials and techniques to solve problems and answer questions. B.Apply appropriate instruments and apparatus to examine a variety of objects and processes.

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4 Sample FNM word wall (graphic organizer)

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7 Density of cork is less dense and rock is more dense than density of water which equals 1 g/mL or 1 cm 3 A barometer measures air pressure. Memory strategy, weight lifters lift a bar of weights. Milk is a colloid, it looks homogeneous, but is heterogeneous. Milk, does it do a body good? Refer to last slide for graphic organizer example. Put into voc section.

8 Verify in voc. section and in graphic organizer A substance like a gas or liquid that flows and takes the shape of the container Unit for pressure = force/area Greek mathematician and Forde: stated the upward force keeping an object floating is equal to the weight of the fluid the object displaces Pressure caused by weight of atmosphere

9 5 Characteristics of fluids Flow Take shape of container Particles slide past each other Exert pressure 6 In order for the balloon to blow up the pressure inside The balloon must be greater than the pressure the air Outside the balloon exerts on the balloon. 7 Formula P = f / (formula for area or given area) PlugP = 150,000 N / 1.5 cm 2 SolveP = 100,000 N / m 2 Solve in units P = 100,000 Pa

10 Air P Pressure Above water Water P Pressure Above water plus pressure below water Pulled To earth by gravity Exert P Container shape 8 9 Gravity is the weakest of the 4 forces (strong, electromagnetic, weak, and gravity. The moon has 1/6 the gravity of earth and no atmosphere or water so there would be no air or water pressure on the moon. Elevation WATER P Depth in water DECREASES Air P 10 AND 11

11 12 Formula P = f / (formula for area or given area) WHEN YOU INHALE AND INCREASE THE AREA IN THE LUNGS PER THE EQUATION FOR PRESSURE YOU DECREASE THE PRESSURE TO LOWER THAN THE PRESSURE OUTSIDE THE LUNGS. FULL LUNGS HAVE AIR PRESSURE GREATER INSIDE THE LUNG THAN OUTSIDE THE LUNG SO UPON EXHALING THE AIR FLOWS FROM GREATER PRESSURE TO LOWER PRESSURE. 13 AIR AND WATER ALWAYS MOVE FROM GREATER PRESSURE TO LESSER PRESSURE THE WHALE EXHALED SO THE WHALE HAD GREATER PRESSURE IN THE BODY SINCE THE WATER MOVED OUT OF THE WHALE INTO THE AIR AS WATER VAPOR. 14 HIGHER PRSSURE IS OUTSIDE THE TORNADO AND INSIDE THE TORNADO IS LOWER PRESSURE DIFFERENCES IN PRESSURES MAKE WIND GREATER DIFFERENCES MAKE STRONGER WINDS TEMPERATURE CHANGES CAUSE PRESSURE DIFFERENCES.

12 15 THINK ABOUT IT: A COIN NEVER FLOATS. WHY? A COIN ISN’T VERY BIG WE KNOW A COIN HAS A DENSITY OF GREATER THAN 1 g/mL because it sinks in the Deepest of the oceans, (Mariana Trench in the Pacific Ocean), but why? As the coin is placed on top of the ocean water, the ability of the coin to displace water Beneath the coin fast enough to stay afloat isn’t possible so the coin sinks. The force the Coin cannot achieve is a buoyant force great enough to displace water fast enough to Keep the coin floating. 16 Weight = buoyant F Weight = buoyant F Object D = fluid D Weight = buoyant F Object D < fluid D floatsFloats Suspended under water Floats Suspended above water only partly submerged

13 18 D = m / v the volume is the denominator So to solve for v = m/D if D decreases While m stays the same, then v will increase

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