2. Shear stress versus shear strain For homogeneous & isotropic materials pure shear causes angular distortion of a material as shown above. Pure shear is most often studied by torsional tests of thin bars. Behavior is completely analogous to normal stresses.

3. Shear stress-strain diagram G is shear modulus or modulus of rigidity

4. The shear stress-strain diagram for a titanium alloy bar tested in torsion is shown in the Figure. Determine i)Shear modulus ii)Proportional Limit iii)Ultimate stress iv)Yield stress v)Fracture stress

5. A bearing pad used to support machines is shown. The following formulae can be used to determine shear stress, shear strain and displacement. For small angles

6. Problem (4): The plastic block shown of 50 mm depth is bonded to a rigid support and to a vertical plate to which a 240-kN load P is applied. Knowing that for the plastic used G=1000 MPa, determine the deflection of the plate. Spring 2006 Mid Term Question Rigid support

7. Problem (4): The plastic block shown of 50 mm depth is bonded to a rigid support and to a vertical plate to which a 240-kN load P is applied. Knowing that for the plastic used G=1000 MPa, determine the deflection of the plate. Spring 2006 Mid Term Question Rigid support

8. Allowable Stress F.S.=1 F.S.=3 Factor of safety

9. Designing for allowable stress Tension Bearing (compression) Shear

10. Problem (6): Determine the intensity w of the maximum distributed load that can be supported by the hanger assembly so that an allowable shear stress of  allow = 15 ksi is not exceeded in the 0.40-in.-diameter bolts at A and B, and an allowable tensile stress of σ allow = 25 ksi is not exceeded in the 0.5-in.-diameter rod AB. Spring 2006 Mid Term Question Solve at home – will cover in help session on Sept 7th