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Published byRosanna Stokes Modified over 9 years ago
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Averages….. In table form
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We will start with discrete data i.e. the data can only take certain values e.g. shoe size
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Number of children in a car No. of children in carFrequency (or No. of cars) 03 19 25 32 41
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The mode means ……. most common
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The mode is ……. 1 child per car
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The range is the Highest number of children – smallest number (per car)
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So the range = 4 – 0 = 4
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It is NOT ….. 9 – 1 = 8
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median Put in size order (Already done in our table) Find the middle value
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We have 20 pieces of data To find the position of the data value we need…. Add 1 onto the number of data values 21 Half this 10½ We need to look halfway between the 10 th and 11 th pieces of data 1 and 1 So the median is ……….
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1
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Now for the trickiest bit…. The mean
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We need to find the total number of children in the cars And then divide by the total number of cars
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Add a column to your table No. of children Frequency (No. of cars) Group total 030 x 3 = 0 191 x 9 = 9 252 x 5 = 10 323 x 2 = 6 414 x 1 = 4 TOTAL2029
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Mean number of children per car …… Total No. of children ÷ total frequency
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Mean = 29 ÷ 20 = …….. 1.45 children per car
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One for you then…… No. of rings per studentFrequency 073 115 27 34 41
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Mode (most common) = … 0 rings
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Range = ……. 4 rings – 0 rings = 4
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Median …… 100 pieces of data Do the ‘add one and half business’ which leaves us looking for the 50½ value (in between the 50 th and 51 st values) 50 th value is ‘0’ and 51 st value is also ‘0’ So median is 0
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Mean …… New column on table
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Like this …… No. of ringsFrequencyGroup Total 0730 x 73 = 0 1151 x 15 = 15 272 x 7 = 14 343 x 4 = 12 414 x 1 = 4 TOTAL100 45
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Mean = 45 ÷ 100 = …… 0.45
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Here’s another one …… No. of fingersFrequency 81 92 1046 110 121
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Mode = ……. 10
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Range = …… 12 – 8 = 4
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Median 50 data values so do the ‘add 1 and half’ thing – we want the 25 th and 26 th values Median is 10
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Mean No. of fingersFrequencyGroup total 818 x 1 = 8 929 x 2 = 18 104610 x 46 = 460 11011 x 0 = 0 12112 x 1 = 12 TOTAL 50 498
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Mean = 498 ÷ 50 = 9.96
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